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About prove of converse of Frobenius theorem in manifolds


Visualizing Frobenius TheoremIntegrable ManifoldsFrobenius Condition for Singular Integrable DistributionsHolomorphic Frobenius TheoremAre all smooth manifolds the zero locus of a smooth function?existence of integral of one form.Definition of a distribution and integral manifoldsImmersion of the manifold in the Flowout TheoremSmooth distribution: first examples.trouble understanding Moser theorem













1












$begingroup$


Theorem



$M$:a smooth manifold
$D$:$c$-dim, smooth distribution on M



If for all $m$ in $M$, there exists a integral manifold of $D$ which includes $m$, $D$ is involutive.



Proof(?)
Let $X$ and $Y$ are smooth vector field on $M$ lying in $D$. Fix $m$ in $M$ and $(N,Ψ)$:Integral manifold of $D$ at $m$. There exist vector field $Z$ and $W$ on $N$ such that $Z$ is $Ψ$-related with $X$ and $W$ is so on with $Y$. If $Z$ and $W$ is smooth, $[X,Y]$ and $[Z,W]$ are $Ψ$-related
. Because $(N,Ψ)$ is integral manifold, $[X,Y]_m$ in $D(m)$.



But, I don’t understand why $Z$ and $W$ are smooth. Please tell me the reason.










share|cite|improve this question











$endgroup$
















    1












    $begingroup$


    Theorem



    $M$:a smooth manifold
    $D$:$c$-dim, smooth distribution on M



    If for all $m$ in $M$, there exists a integral manifold of $D$ which includes $m$, $D$ is involutive.



    Proof(?)
    Let $X$ and $Y$ are smooth vector field on $M$ lying in $D$. Fix $m$ in $M$ and $(N,Ψ)$:Integral manifold of $D$ at $m$. There exist vector field $Z$ and $W$ on $N$ such that $Z$ is $Ψ$-related with $X$ and $W$ is so on with $Y$. If $Z$ and $W$ is smooth, $[X,Y]$ and $[Z,W]$ are $Ψ$-related
    . Because $(N,Ψ)$ is integral manifold, $[X,Y]_m$ in $D(m)$.



    But, I don’t understand why $Z$ and $W$ are smooth. Please tell me the reason.










    share|cite|improve this question











    $endgroup$














      1












      1








      1





      $begingroup$


      Theorem



      $M$:a smooth manifold
      $D$:$c$-dim, smooth distribution on M



      If for all $m$ in $M$, there exists a integral manifold of $D$ which includes $m$, $D$ is involutive.



      Proof(?)
      Let $X$ and $Y$ are smooth vector field on $M$ lying in $D$. Fix $m$ in $M$ and $(N,Ψ)$:Integral manifold of $D$ at $m$. There exist vector field $Z$ and $W$ on $N$ such that $Z$ is $Ψ$-related with $X$ and $W$ is so on with $Y$. If $Z$ and $W$ is smooth, $[X,Y]$ and $[Z,W]$ are $Ψ$-related
      . Because $(N,Ψ)$ is integral manifold, $[X,Y]_m$ in $D(m)$.



      But, I don’t understand why $Z$ and $W$ are smooth. Please tell me the reason.










      share|cite|improve this question











      $endgroup$




      Theorem



      $M$:a smooth manifold
      $D$:$c$-dim, smooth distribution on M



      If for all $m$ in $M$, there exists a integral manifold of $D$ which includes $m$, $D$ is involutive.



      Proof(?)
      Let $X$ and $Y$ are smooth vector field on $M$ lying in $D$. Fix $m$ in $M$ and $(N,Ψ)$:Integral manifold of $D$ at $m$. There exist vector field $Z$ and $W$ on $N$ such that $Z$ is $Ψ$-related with $X$ and $W$ is so on with $Y$. If $Z$ and $W$ is smooth, $[X,Y]$ and $[Z,W]$ are $Ψ$-related
      . Because $(N,Ψ)$ is integral manifold, $[X,Y]_m$ in $D(m)$.



      But, I don’t understand why $Z$ and $W$ are smooth. Please tell me the reason.







      differential-geometry






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 29 at 14:13







      稲垣真郷

















      asked Mar 29 at 10:03









      稲垣真郷稲垣真郷

      62




      62




















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