abelian group as Z moduleabelian and finite groupModule, vector space and abelian groupDeterming whether (S, *) is an Abelian groupLocally graded group with all proper subgroups abelianHow is an abelian $G$-operator group with $m1 = m$ a $mathbb Z[G]$-moduleThe homomorphic image of an abelian group is abelianProve that middle cancellation implies that the group is abelianIs $G$ an Abelian group?Prove or disapprove: Group of order $135$ must be abelian“Module” versus “Abelian Group” of the Integers, German Language usage circa 1962

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abelian group as Z module


abelian and finite groupModule, vector space and abelian groupDeterming whether (S, *) is an Abelian groupLocally graded group with all proper subgroups abelianHow is an abelian $G$-operator group with $m1 = m$ a $mathbb Z[G]$-moduleThe homomorphic image of an abelian group is abelianProve that middle cancellation implies that the group is abelianIs $G$ an Abelian group?Prove or disapprove: Group of order $135$ must be abelian“Module” versus “Abelian Group” of the Integers, German Language usage circa 1962













0












$begingroup$


How Would you prove that every abelian group can be understood as a Z-Module in a unique way?



I would guess that you would have to prove its bijective, but not sure how to go about this










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What is the definition of a $mathbb Z$-module?
    $endgroup$
    – awllower
    Nov 4 '14 at 13:30















0












$begingroup$


How Would you prove that every abelian group can be understood as a Z-Module in a unique way?



I would guess that you would have to prove its bijective, but not sure how to go about this










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What is the definition of a $mathbb Z$-module?
    $endgroup$
    – awllower
    Nov 4 '14 at 13:30













0












0








0


3



$begingroup$


How Would you prove that every abelian group can be understood as a Z-Module in a unique way?



I would guess that you would have to prove its bijective, but not sure how to go about this










share|cite|improve this question









$endgroup$




How Would you prove that every abelian group can be understood as a Z-Module in a unique way?



I would guess that you would have to prove its bijective, but not sure how to go about this







linear-algebra group-theory abelian-groups






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 4 '14 at 13:25









user189820user189820

1




1







  • 1




    $begingroup$
    What is the definition of a $mathbb Z$-module?
    $endgroup$
    – awllower
    Nov 4 '14 at 13:30












  • 1




    $begingroup$
    What is the definition of a $mathbb Z$-module?
    $endgroup$
    – awllower
    Nov 4 '14 at 13:30







1




1




$begingroup$
What is the definition of a $mathbb Z$-module?
$endgroup$
– awllower
Nov 4 '14 at 13:30




$begingroup$
What is the definition of a $mathbb Z$-module?
$endgroup$
– awllower
Nov 4 '14 at 13:30










1 Answer
1






active

oldest

votes


















4












$begingroup$

Given an abelian group $G$ its set of endomorphisms
$$
rm End(G)=f:Grightarrow G,texthomomorphism
$$

is a ring under the usual operations of sum and composition, with unity the identity map.



Given any ring with unity $R$ there is a unique map of unital rings
$$
Bbb Zlongrightarrow R
$$

given by $nmapsto ncdot1_R$ with the usual convention for $n<0$ (preserving the identity mandates $1_Bbb Zmapsto 1_R$). By applying this to $rm End(G)$ you immediately see that $G$ has a unique structure of $Bbb Z$-module.






share|cite|improve this answer











$endgroup$













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    1 Answer
    1






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    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4












    $begingroup$

    Given an abelian group $G$ its set of endomorphisms
    $$
    rm End(G)=f:Grightarrow G,texthomomorphism
    $$

    is a ring under the usual operations of sum and composition, with unity the identity map.



    Given any ring with unity $R$ there is a unique map of unital rings
    $$
    Bbb Zlongrightarrow R
    $$

    given by $nmapsto ncdot1_R$ with the usual convention for $n<0$ (preserving the identity mandates $1_Bbb Zmapsto 1_R$). By applying this to $rm End(G)$ you immediately see that $G$ has a unique structure of $Bbb Z$-module.






    share|cite|improve this answer











    $endgroup$

















      4












      $begingroup$

      Given an abelian group $G$ its set of endomorphisms
      $$
      rm End(G)=f:Grightarrow G,texthomomorphism
      $$

      is a ring under the usual operations of sum and composition, with unity the identity map.



      Given any ring with unity $R$ there is a unique map of unital rings
      $$
      Bbb Zlongrightarrow R
      $$

      given by $nmapsto ncdot1_R$ with the usual convention for $n<0$ (preserving the identity mandates $1_Bbb Zmapsto 1_R$). By applying this to $rm End(G)$ you immediately see that $G$ has a unique structure of $Bbb Z$-module.






      share|cite|improve this answer











      $endgroup$















        4












        4








        4





        $begingroup$

        Given an abelian group $G$ its set of endomorphisms
        $$
        rm End(G)=f:Grightarrow G,texthomomorphism
        $$

        is a ring under the usual operations of sum and composition, with unity the identity map.



        Given any ring with unity $R$ there is a unique map of unital rings
        $$
        Bbb Zlongrightarrow R
        $$

        given by $nmapsto ncdot1_R$ with the usual convention for $n<0$ (preserving the identity mandates $1_Bbb Zmapsto 1_R$). By applying this to $rm End(G)$ you immediately see that $G$ has a unique structure of $Bbb Z$-module.






        share|cite|improve this answer











        $endgroup$



        Given an abelian group $G$ its set of endomorphisms
        $$
        rm End(G)=f:Grightarrow G,texthomomorphism
        $$

        is a ring under the usual operations of sum and composition, with unity the identity map.



        Given any ring with unity $R$ there is a unique map of unital rings
        $$
        Bbb Zlongrightarrow R
        $$

        given by $nmapsto ncdot1_R$ with the usual convention for $n<0$ (preserving the identity mandates $1_Bbb Zmapsto 1_R$). By applying this to $rm End(G)$ you immediately see that $G$ has a unique structure of $Bbb Z$-module.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 29 at 10:02









        Shlomi A

        264213




        264213










        answered Nov 4 '14 at 13:48









        Andrea MoriAndrea Mori

        20.1k13466




        20.1k13466



























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