Confusion About Invertible ModulesFinitely generated projective modules are locally freeAre projective modules over an artinian ring free?The existence of a projective resolution of M from finite rank free modulesHartshorne Chapter II exercise 5.7 on Invertible sheavesProjectivity of a (prime) ideal in a noetherian integral domainEvery finitely generated flat module over a ring with a finite number of minimal primes is projectiveQuotient of free modules is torsion implies rank is the same?Computing Picard groups by showing invertible modules are uniquely determinedInvertible ideals and locally free moduleThe multiplication of rank for finite projective modules

What defenses are there against being summoned by the Gate spell?

Do I have a twin with permutated remainders?

How much RAM could one put in a typical 80386 setup?

Add text to same line using sed

Why can't we play rap on piano?

I'm flying to France today and my passport expires in less than 2 months

A newer friend of my brother's gave him a load of baseball cards that are supposedly extremely valuable. Is this a scam?

NMaximize is not converging to a solution

How does one intimidate enemies without having the capacity for violence?

Theorems that impeded progress

What does the "remote control" for a QF-4 look like?

Approximately how much travel time was saved by the opening of the Suez Canal in 1869?

Paid for article while in US on F-1 visa?

strTok function (thread safe, supports empty tokens, doesn't change string)

How much of data wrangling is a data scientist's job?

Does detail obscure or enhance action?

Character reincarnated...as a snail

Why doesn't H₄O²⁺ exist?

If human space travel is limited by the G force vulnerability, is there a way to counter G forces?

Can a Cauchy sequence converge for one metric while not converging for another?

Are the number of citations and number of published articles the most important criteria for a tenure promotion?

Why does Kotter return in Welcome Back Kotter?

Can you really stack all of this on an Opportunity Attack?

Why is 150k or 200k jobs considered good when there's 300k+ births a month?



Confusion About Invertible Modules


Finitely generated projective modules are locally freeAre projective modules over an artinian ring free?The existence of a projective resolution of M from finite rank free modulesHartshorne Chapter II exercise 5.7 on Invertible sheavesProjectivity of a (prime) ideal in a noetherian integral domainEvery finitely generated flat module over a ring with a finite number of minimal primes is projectiveQuotient of free modules is torsion implies rank is the same?Computing Picard groups by showing invertible modules are uniquely determinedInvertible ideals and locally free moduleThe multiplication of rank for finite projective modules













-1












$begingroup$


According to the Stacks Project, a module is invertible iff it is locally free of rank one.(In the strong sense, not just that the stalks are free).Link



So, according to this link, the module is finite projective of rank one. But this question says that this is not true. What is the correct answer here?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    Can you spell out the place where "this question" says that this is not true?
    $endgroup$
    – Youngsu
    Mar 29 at 14:41










  • $begingroup$
    It says that condition 1) is strictly stronger.
    $endgroup$
    – Jehu314
    Mar 29 at 15:03






  • 1




    $begingroup$
    What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
    $endgroup$
    – Youngsu
    Mar 29 at 17:56






  • 1




    $begingroup$
    Finiteness is the difference as stated in those two links.
    $endgroup$
    – Youngsu
    Mar 29 at 18:31






  • 1




    $begingroup$
    What is your question? Are you asking whether a locally free module of rank $1$ is projective?
    $endgroup$
    – Qiaochu Yuan
    Mar 29 at 19:48















-1












$begingroup$


According to the Stacks Project, a module is invertible iff it is locally free of rank one.(In the strong sense, not just that the stalks are free).Link



So, according to this link, the module is finite projective of rank one. But this question says that this is not true. What is the correct answer here?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    Can you spell out the place where "this question" says that this is not true?
    $endgroup$
    – Youngsu
    Mar 29 at 14:41










  • $begingroup$
    It says that condition 1) is strictly stronger.
    $endgroup$
    – Jehu314
    Mar 29 at 15:03






  • 1




    $begingroup$
    What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
    $endgroup$
    – Youngsu
    Mar 29 at 17:56






  • 1




    $begingroup$
    Finiteness is the difference as stated in those two links.
    $endgroup$
    – Youngsu
    Mar 29 at 18:31






  • 1




    $begingroup$
    What is your question? Are you asking whether a locally free module of rank $1$ is projective?
    $endgroup$
    – Qiaochu Yuan
    Mar 29 at 19:48













-1












-1








-1





$begingroup$


According to the Stacks Project, a module is invertible iff it is locally free of rank one.(In the strong sense, not just that the stalks are free).Link



So, according to this link, the module is finite projective of rank one. But this question says that this is not true. What is the correct answer here?










share|cite|improve this question









$endgroup$




According to the Stacks Project, a module is invertible iff it is locally free of rank one.(In the strong sense, not just that the stalks are free).Link



So, according to this link, the module is finite projective of rank one. But this question says that this is not true. What is the correct answer here?







commutative-algebra projective-module






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 29 at 11:46









Jehu314Jehu314

1549




1549







  • 1




    $begingroup$
    Can you spell out the place where "this question" says that this is not true?
    $endgroup$
    – Youngsu
    Mar 29 at 14:41










  • $begingroup$
    It says that condition 1) is strictly stronger.
    $endgroup$
    – Jehu314
    Mar 29 at 15:03






  • 1




    $begingroup$
    What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
    $endgroup$
    – Youngsu
    Mar 29 at 17:56






  • 1




    $begingroup$
    Finiteness is the difference as stated in those two links.
    $endgroup$
    – Youngsu
    Mar 29 at 18:31






  • 1




    $begingroup$
    What is your question? Are you asking whether a locally free module of rank $1$ is projective?
    $endgroup$
    – Qiaochu Yuan
    Mar 29 at 19:48












  • 1




    $begingroup$
    Can you spell out the place where "this question" says that this is not true?
    $endgroup$
    – Youngsu
    Mar 29 at 14:41










  • $begingroup$
    It says that condition 1) is strictly stronger.
    $endgroup$
    – Jehu314
    Mar 29 at 15:03






  • 1




    $begingroup$
    What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
    $endgroup$
    – Youngsu
    Mar 29 at 17:56






  • 1




    $begingroup$
    Finiteness is the difference as stated in those two links.
    $endgroup$
    – Youngsu
    Mar 29 at 18:31






  • 1




    $begingroup$
    What is your question? Are you asking whether a locally free module of rank $1$ is projective?
    $endgroup$
    – Qiaochu Yuan
    Mar 29 at 19:48







1




1




$begingroup$
Can you spell out the place where "this question" says that this is not true?
$endgroup$
– Youngsu
Mar 29 at 14:41




$begingroup$
Can you spell out the place where "this question" says that this is not true?
$endgroup$
– Youngsu
Mar 29 at 14:41












$begingroup$
It says that condition 1) is strictly stronger.
$endgroup$
– Jehu314
Mar 29 at 15:03




$begingroup$
It says that condition 1) is strictly stronger.
$endgroup$
– Jehu314
Mar 29 at 15:03




1




1




$begingroup$
What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
$endgroup$
– Youngsu
Mar 29 at 17:56




$begingroup$
What is your argument? It is better for the readers if you state the necessary statements in your post and specify your question explicitly.
$endgroup$
– Youngsu
Mar 29 at 17:56




1




1




$begingroup$
Finiteness is the difference as stated in those two links.
$endgroup$
– Youngsu
Mar 29 at 18:31




$begingroup$
Finiteness is the difference as stated in those two links.
$endgroup$
– Youngsu
Mar 29 at 18:31




1




1




$begingroup$
What is your question? Are you asking whether a locally free module of rank $1$ is projective?
$endgroup$
– Qiaochu Yuan
Mar 29 at 19:48




$begingroup$
What is your question? Are you asking whether a locally free module of rank $1$ is projective?
$endgroup$
– Qiaochu Yuan
Mar 29 at 19:48










0






active

oldest

votes












Your Answer





StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3167056%2fconfusion-about-invertible-modules%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes















draft saved

draft discarded
















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3167056%2fconfusion-about-invertible-modules%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Triangular numbers and gcdProving sum of a set is $0 pmod n$ if $n$ is odd, or $fracn2 pmod n$ if $n$ is even?Is greatest common divisor of two numbers really their smallest linear combination?GCD, LCM RelationshipProve a set of nonnegative integers with greatest common divisor 1 and closed under addition has all but finite many nonnegative integers.all pairs of a and b in an equation containing gcdTriangular Numbers Modulo $k$ - Hit All Values?Understanding the Existence and Uniqueness of the GCDGCD and LCM with logical symbolsThe greatest common divisor of two positive integers less than 100 is equal to 3. Their least common multiple is twelve times one of the integers.Suppose that for all integers $x$, $x|a$ and $x|b$ if and only if $x|c$. Then $c = gcd(a,b)$Which is the gcd of 2 numbers which are multiplied and the result is 600000?

Ingelân Ynhâld Etymology | Geografy | Skiednis | Polityk en bestjoer | Ekonomy | Demografy | Kultuer | Klimaat | Sjoch ek | Keppelings om utens | Boarnen, noaten en referinsjes Navigaasjemenuwww.gov.ukOffisjele webside fan it regear fan it Feriene KeninkrykOffisjele webside fan it Britske FerkearsburoNederlânsktalige ynformaasje fan it Britske FerkearsburoOffisjele webside fan English Heritage, de organisaasje dy't him ynset foar it behâld fan it Ingelske kultuergoedYnwennertallen fan alle Britske stêden út 'e folkstelling fan 2011Notes en References, op dizze sideEngland

Հադիս Բովանդակություն Անվանում և նշանակություն | Դասակարգում | Աղբյուրներ | Նավարկման ցանկ