The pentagon in isosceles triangle Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)question about triangleConstructing a triangle given three concurrent cevians?Isosceles triangle helpwhen you draw 1 altitude/ perpendicular bisector of an equilateral triangle, what can you form?Isosceles triangle and scalene triangleFinding the coordinates of the vertices of an equilateral triangle.2 circles in an isosceles triangleConstruct an equilateral triangle with area equal to a given triangleFind an angle in the figure defined by a equilateral triangle and a regular pentagonArea Of Pentagon
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The pentagon in isosceles triangle
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)question about triangleConstructing a triangle given three concurrent cevians?Isosceles triangle helpwhen you draw 1 altitude/ perpendicular bisector of an equilateral triangle, what can you form?Isosceles triangle and scalene triangleFinding the coordinates of the vertices of an equilateral triangle.2 circles in an isosceles triangleConstruct an equilateral triangle with area equal to a given triangleFind an angle in the figure defined by a equilateral triangle and a regular pentagonArea Of Pentagon
$begingroup$
The triangle with the sides a,a,and b is isoscele.cut off from it two triangle, symmetric to each other with respect to the altitude perpendicular to the base b,so that the remaining symmetric pentagon is equilateral. Express the sides x of pentagon in terms of a and b
geometry
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
$endgroup$
add a comment |
$begingroup$
The triangle with the sides a,a,and b is isoscele.cut off from it two triangle, symmetric to each other with respect to the altitude perpendicular to the base b,so that the remaining symmetric pentagon is equilateral. Express the sides x of pentagon in terms of a and b
geometry
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
$endgroup$
add a comment |
$begingroup$
The triangle with the sides a,a,and b is isoscele.cut off from it two triangle, symmetric to each other with respect to the altitude perpendicular to the base b,so that the remaining symmetric pentagon is equilateral. Express the sides x of pentagon in terms of a and b
geometry
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
$endgroup$
The triangle with the sides a,a,and b is isoscele.cut off from it two triangle, symmetric to each other with respect to the altitude perpendicular to the base b,so that the remaining symmetric pentagon is equilateral. Express the sides x of pentagon in terms of a and b
geometry
geometry
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
edited Apr 1 at 12:33
J. W. Tanner
4,9921520
4,9921520
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
asked Apr 1 at 12:15
Behnam MotallebiBehnam Motallebi
12
12
add a comment |
add a comment |
1 Answer
1
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$begingroup$
A triangle that you cut off has sides $a-x$, $1over2(b-x)$, and $x$. Apply the cosine theorem to this triangle, knowing that $cosalpha=bover 2a$. In this way you obtain a quadratic equation for $x$. For good measure you should check what are allowable values for $b$, given $a$.
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
$endgroup$
add a comment |
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$begingroup$
A triangle that you cut off has sides $a-x$, $1over2(b-x)$, and $x$. Apply the cosine theorem to this triangle, knowing that $cosalpha=bover 2a$. In this way you obtain a quadratic equation for $x$. For good measure you should check what are allowable values for $b$, given $a$.
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
$endgroup$
add a comment |
$begingroup$
A triangle that you cut off has sides $a-x$, $1over2(b-x)$, and $x$. Apply the cosine theorem to this triangle, knowing that $cosalpha=bover 2a$. In this way you obtain a quadratic equation for $x$. For good measure you should check what are allowable values for $b$, given $a$.
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
$endgroup$
add a comment |
$begingroup$
A triangle that you cut off has sides $a-x$, $1over2(b-x)$, and $x$. Apply the cosine theorem to this triangle, knowing that $cosalpha=bover 2a$. In this way you obtain a quadratic equation for $x$. For good measure you should check what are allowable values for $b$, given $a$.
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
$endgroup$
A triangle that you cut off has sides $a-x$, $1over2(b-x)$, and $x$. Apply the cosine theorem to this triangle, knowing that $cosalpha=bover 2a$. In this way you obtain a quadratic equation for $x$. For good measure you should check what are allowable values for $b$, given $a$.
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
answered Apr 1 at 13:31
Christian BlatterChristian Blatter
176k9115328
176k9115328
add a comment |
add a comment |
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