Interpreting a problem in combinatorial geometry Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Number of line segments intersecting diagonals are divided into in a convex polygonLazy caterer's sequence, cutting pizza into most pieces with n straight cuts. Graph theory proof.Trying to understand formula for counting regions of hyperplane arrangements in $mathbbR^2$n lines cut a plane into at least (n+1)(n+2)n/3 regions.no. of regions a plane is divided into by $n$ lines in general positionAnother olympiad question related to Extremal Principle (regarding geometry problem)In how many parts is a plane cut by n lines, or a space cut by n planes?Question about how we count the number of ways to do a task.Combinatorics problem with geometryCounting regions outside a convex hull
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Interpreting a problem in combinatorial geometry
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Number of line segments intersecting diagonals are divided into in a convex polygonLazy caterer's sequence, cutting pizza into most pieces with n straight cuts. Graph theory proof.Trying to understand formula for counting regions of hyperplane arrangements in $mathbbR^2$n lines cut a plane into at least (n+1)(n+2)n/3 regions.no. of regions a plane is divided into by $n$ lines in general positionAnother olympiad question related to Extremal Principle (regarding geometry problem)In how many parts is a plane cut by n lines, or a space cut by n planes?Question about how we count the number of ways to do a task.Combinatorics problem with geometryCounting regions outside a convex hull
$begingroup$
Problem: Let $L$ be a set of $n$ lines in the plane in general position, that is, no three of them containing the same point. The lines of $L$ cut the plane into $k$ regions. Prove by induction on $n$ that this subdivision of the plane has $binomn2$ vertices, $n^2$ edges, and $binomn2 + n + 1$ cells.
I don't need help solving this problem, I just need help interpreting it. What does it mean that the plane is cut into $k$ regions? I thought that the number of regions was determined by $n$. Also, what's the point of the $k$ if we're not proving anything about it?
Finally, what is meant by cells? Also, are edges the finite segments between intersections?
combinatorics euclidean-geometry
$endgroup$
add a comment |
$begingroup$
Problem: Let $L$ be a set of $n$ lines in the plane in general position, that is, no three of them containing the same point. The lines of $L$ cut the plane into $k$ regions. Prove by induction on $n$ that this subdivision of the plane has $binomn2$ vertices, $n^2$ edges, and $binomn2 + n + 1$ cells.
I don't need help solving this problem, I just need help interpreting it. What does it mean that the plane is cut into $k$ regions? I thought that the number of regions was determined by $n$. Also, what's the point of the $k$ if we're not proving anything about it?
Finally, what is meant by cells? Also, are edges the finite segments between intersections?
combinatorics euclidean-geometry
$endgroup$
3
$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29
add a comment |
$begingroup$
Problem: Let $L$ be a set of $n$ lines in the plane in general position, that is, no three of them containing the same point. The lines of $L$ cut the plane into $k$ regions. Prove by induction on $n$ that this subdivision of the plane has $binomn2$ vertices, $n^2$ edges, and $binomn2 + n + 1$ cells.
I don't need help solving this problem, I just need help interpreting it. What does it mean that the plane is cut into $k$ regions? I thought that the number of regions was determined by $n$. Also, what's the point of the $k$ if we're not proving anything about it?
Finally, what is meant by cells? Also, are edges the finite segments between intersections?
combinatorics euclidean-geometry
$endgroup$
Problem: Let $L$ be a set of $n$ lines in the plane in general position, that is, no three of them containing the same point. The lines of $L$ cut the plane into $k$ regions. Prove by induction on $n$ that this subdivision of the plane has $binomn2$ vertices, $n^2$ edges, and $binomn2 + n + 1$ cells.
I don't need help solving this problem, I just need help interpreting it. What does it mean that the plane is cut into $k$ regions? I thought that the number of regions was determined by $n$. Also, what's the point of the $k$ if we're not proving anything about it?
Finally, what is meant by cells? Also, are edges the finite segments between intersections?
combinatorics euclidean-geometry
combinatorics euclidean-geometry
asked Apr 1 at 13:15
WesleyWesley
619613
619613
3
$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29
add a comment |
3
$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29
3
3
$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29
$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29
add a comment |
2 Answers
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$begingroup$
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line
$endgroup$
add a comment |
$begingroup$
For the statement to be correct, no two lines may be parallel. The symbol $k$ has no significance whatsoever, and might as well be omitted; the question would have been clearer if it said
The lines of $L$ cut the plane into some number of regions.
The question is also poorly phrased as it does not specify what the words "vertices", "edges", "regions" and "cells" mean. Judging from the given formulas, my best guess is the following:
A vertex is a point of intersection of two lines. Denote the set of vertices by $V$:
$$V:=lcap m: l,min L.$$
The vertices partition the lines into segments; these are the edges. Note that some are bounded and some are unbounded. More precisely, the set of edges is the set of connected components of $(bigcup L)-V$.
Similarly, omitting the lines from the plane leaves a number of regions, and again some are bounded and some are unbounded. The cells are the bounded regions. More precisely, the set of regions is the set of connected components of $P-bigcup L$, where $P$ denotes the plane, and the set of cells is the subset of bounded connected components of $P-bigcup L$.
$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line
$endgroup$
add a comment |
$begingroup$
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line
$endgroup$
add a comment |
$begingroup$
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line
$endgroup$
I tried the case for $n=3$ and I think i found the correct interpretation, but you should do it yourself to confirm. It seems that they do not allow for parallel lines, in which case you are right that the $k$ in "$k$ regions" is not relevant.
"Vertices" is clear: a vertex is a point where a pair of lines intersect
"Edges" are any piece of line: a finite line segment between vertices, an infinite ray emanating from a vertex, or a whole line (in the case of $n=1$)
"Cells" means any face created by the lines. In other words, a region of the plane is a cell if you can draw a continuous path between any 2 points in the cell without crossing a line
answered Apr 1 at 13:28
NazimJNazimJ
890110
890110
add a comment |
add a comment |
$begingroup$
For the statement to be correct, no two lines may be parallel. The symbol $k$ has no significance whatsoever, and might as well be omitted; the question would have been clearer if it said
The lines of $L$ cut the plane into some number of regions.
The question is also poorly phrased as it does not specify what the words "vertices", "edges", "regions" and "cells" mean. Judging from the given formulas, my best guess is the following:
A vertex is a point of intersection of two lines. Denote the set of vertices by $V$:
$$V:=lcap m: l,min L.$$
The vertices partition the lines into segments; these are the edges. Note that some are bounded and some are unbounded. More precisely, the set of edges is the set of connected components of $(bigcup L)-V$.
Similarly, omitting the lines from the plane leaves a number of regions, and again some are bounded and some are unbounded. The cells are the bounded regions. More precisely, the set of regions is the set of connected components of $P-bigcup L$, where $P$ denotes the plane, and the set of cells is the subset of bounded connected components of $P-bigcup L$.
$endgroup$
add a comment |
$begingroup$
For the statement to be correct, no two lines may be parallel. The symbol $k$ has no significance whatsoever, and might as well be omitted; the question would have been clearer if it said
The lines of $L$ cut the plane into some number of regions.
The question is also poorly phrased as it does not specify what the words "vertices", "edges", "regions" and "cells" mean. Judging from the given formulas, my best guess is the following:
A vertex is a point of intersection of two lines. Denote the set of vertices by $V$:
$$V:=lcap m: l,min L.$$
The vertices partition the lines into segments; these are the edges. Note that some are bounded and some are unbounded. More precisely, the set of edges is the set of connected components of $(bigcup L)-V$.
Similarly, omitting the lines from the plane leaves a number of regions, and again some are bounded and some are unbounded. The cells are the bounded regions. More precisely, the set of regions is the set of connected components of $P-bigcup L$, where $P$ denotes the plane, and the set of cells is the subset of bounded connected components of $P-bigcup L$.
$endgroup$
add a comment |
$begingroup$
For the statement to be correct, no two lines may be parallel. The symbol $k$ has no significance whatsoever, and might as well be omitted; the question would have been clearer if it said
The lines of $L$ cut the plane into some number of regions.
The question is also poorly phrased as it does not specify what the words "vertices", "edges", "regions" and "cells" mean. Judging from the given formulas, my best guess is the following:
A vertex is a point of intersection of two lines. Denote the set of vertices by $V$:
$$V:=lcap m: l,min L.$$
The vertices partition the lines into segments; these are the edges. Note that some are bounded and some are unbounded. More precisely, the set of edges is the set of connected components of $(bigcup L)-V$.
Similarly, omitting the lines from the plane leaves a number of regions, and again some are bounded and some are unbounded. The cells are the bounded regions. More precisely, the set of regions is the set of connected components of $P-bigcup L$, where $P$ denotes the plane, and the set of cells is the subset of bounded connected components of $P-bigcup L$.
$endgroup$
For the statement to be correct, no two lines may be parallel. The symbol $k$ has no significance whatsoever, and might as well be omitted; the question would have been clearer if it said
The lines of $L$ cut the plane into some number of regions.
The question is also poorly phrased as it does not specify what the words "vertices", "edges", "regions" and "cells" mean. Judging from the given formulas, my best guess is the following:
A vertex is a point of intersection of two lines. Denote the set of vertices by $V$:
$$V:=lcap m: l,min L.$$
The vertices partition the lines into segments; these are the edges. Note that some are bounded and some are unbounded. More precisely, the set of edges is the set of connected components of $(bigcup L)-V$.
Similarly, omitting the lines from the plane leaves a number of regions, and again some are bounded and some are unbounded. The cells are the bounded regions. More precisely, the set of regions is the set of connected components of $P-bigcup L$, where $P$ denotes the plane, and the set of cells is the subset of bounded connected components of $P-bigcup L$.
answered Apr 1 at 13:47
ServaesServaes
30.7k342101
30.7k342101
add a comment |
add a comment |
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$begingroup$
I agree the statement is not as clear as it could be. For one thing, it explains that "general position" means no three lines through the same point, but it doesn't mention that no two lines can be parallel (which I believe is also intended by "general position"). And they could have said "some number of" instead of $k$, so the use of that symbol was unnecessary.
$endgroup$
– David K
Apr 1 at 13:29