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Phase transition threshold for acyclic directed graph



The 2019 Stack Overflow Developer Survey Results Are InFamily of sets. Directed acyclic graph representation.Combinatorial problem: Directed Acyclic GraphDirected Acyclic Graph Questionbipartite graph vs. directed acyclic graphDirected acyclic graph problemName for “Stratified” or “Synchronized” directed acyclic graph?Longest Path in a acyclic, directed graphDirected acyclic graph and adjacency matrixPlanarity of a “cell graph”Directed acyclic graph










3












$begingroup$


Let $G$ be an acyclic directed graph with $MN$ vertices arranged into $M$ generations of $N$ vertices each. We stipulate that edges may only go from generation $j$ to generation $j+1$, so there are $(M-1)N^2$ permissible edges. Each permissible edge is chosen independently with probability $p$, and the resulting subset of permissible edges is used to construct $G$.



The quantity of interest is the probability $P(p)$ that a randomly-chosen vertex $x$ in the first generation of $G$ is connected by a directed path to a random-chosen vertex $y$ in the $M$th generation of $G$. As $N$ becomes large for fixed $M$, one expects a phase transition in $P$ from near $0$ to near $1$ as $p$ crosses some threshold $p_0$.



Question: What is this threshold $p_0$ in terms of $M$ and $N$?



For example, when $M=3$ (first interesting case), it seems that the threshold is $p_0=N^-frac12$, and I would guess that $p_0=N^-fracM-2M-1$ in general.



Is this correct, and how does one prove it? Or where can I find this problem analyzed? I have found many somewhat-relevant sources on percolation, but they mostly involve lattices or Erdös-Rényi graphs.










share|cite|improve this question











$endgroup$
















    3












    $begingroup$


    Let $G$ be an acyclic directed graph with $MN$ vertices arranged into $M$ generations of $N$ vertices each. We stipulate that edges may only go from generation $j$ to generation $j+1$, so there are $(M-1)N^2$ permissible edges. Each permissible edge is chosen independently with probability $p$, and the resulting subset of permissible edges is used to construct $G$.



    The quantity of interest is the probability $P(p)$ that a randomly-chosen vertex $x$ in the first generation of $G$ is connected by a directed path to a random-chosen vertex $y$ in the $M$th generation of $G$. As $N$ becomes large for fixed $M$, one expects a phase transition in $P$ from near $0$ to near $1$ as $p$ crosses some threshold $p_0$.



    Question: What is this threshold $p_0$ in terms of $M$ and $N$?



    For example, when $M=3$ (first interesting case), it seems that the threshold is $p_0=N^-frac12$, and I would guess that $p_0=N^-fracM-2M-1$ in general.



    Is this correct, and how does one prove it? Or where can I find this problem analyzed? I have found many somewhat-relevant sources on percolation, but they mostly involve lattices or Erdös-Rényi graphs.










    share|cite|improve this question











    $endgroup$














      3












      3








      3





      $begingroup$


      Let $G$ be an acyclic directed graph with $MN$ vertices arranged into $M$ generations of $N$ vertices each. We stipulate that edges may only go from generation $j$ to generation $j+1$, so there are $(M-1)N^2$ permissible edges. Each permissible edge is chosen independently with probability $p$, and the resulting subset of permissible edges is used to construct $G$.



      The quantity of interest is the probability $P(p)$ that a randomly-chosen vertex $x$ in the first generation of $G$ is connected by a directed path to a random-chosen vertex $y$ in the $M$th generation of $G$. As $N$ becomes large for fixed $M$, one expects a phase transition in $P$ from near $0$ to near $1$ as $p$ crosses some threshold $p_0$.



      Question: What is this threshold $p_0$ in terms of $M$ and $N$?



      For example, when $M=3$ (first interesting case), it seems that the threshold is $p_0=N^-frac12$, and I would guess that $p_0=N^-fracM-2M-1$ in general.



      Is this correct, and how does one prove it? Or where can I find this problem analyzed? I have found many somewhat-relevant sources on percolation, but they mostly involve lattices or Erdös-Rényi graphs.










      share|cite|improve this question











      $endgroup$




      Let $G$ be an acyclic directed graph with $MN$ vertices arranged into $M$ generations of $N$ vertices each. We stipulate that edges may only go from generation $j$ to generation $j+1$, so there are $(M-1)N^2$ permissible edges. Each permissible edge is chosen independently with probability $p$, and the resulting subset of permissible edges is used to construct $G$.



      The quantity of interest is the probability $P(p)$ that a randomly-chosen vertex $x$ in the first generation of $G$ is connected by a directed path to a random-chosen vertex $y$ in the $M$th generation of $G$. As $N$ becomes large for fixed $M$, one expects a phase transition in $P$ from near $0$ to near $1$ as $p$ crosses some threshold $p_0$.



      Question: What is this threshold $p_0$ in terms of $M$ and $N$?



      For example, when $M=3$ (first interesting case), it seems that the threshold is $p_0=N^-frac12$, and I would guess that $p_0=N^-fracM-2M-1$ in general.



      Is this correct, and how does one prove it? Or where can I find this problem analyzed? I have found many somewhat-relevant sources on percolation, but they mostly involve lattices or Erdös-Rényi graphs.







      graph-theory percolation






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Oct 25 '18 at 17:10







      physmath121

















      asked Oct 25 '18 at 16:02









      physmath121physmath121

      162




      162




















          1 Answer
          1






          active

          oldest

          votes


















          1












          $begingroup$

          I have no final answer but this is my progress:



          Here is an explicit formula for $P(p)$:
          $$P(p) = 1 - (1-p^M-1)^N^M-2$$



          Here $1 - p^M-1$ is the probability that a complete path from $v_1$ to $v_M$ is not completely connected and $N^M-2$ is the number of possible paths from $v_1$ to $v_M$. (Where $v_i$ is some node in generation $i$).



          Inserting $M=3$ and $p_0 = N^frac-12$ gives you:
          $$P(p_0) = 1 - left(fracN-1Nright)^N.$$



          Your general formula for $p_0$ will give you:
          $$P(p_0) = 1 - left( fracK-1K right)^K$$
          where $K := N^M-2$



          Increasing $p_0$ above that threshold will decrease the subtractor, thus increasing $P(p_0)$, which follows the intuition. Decreasing $p_0$ will decrease the whole expression, thus making $P$ monotonically increasing in $p_0$.



          I can't really see a clear transition here. Still curious if you can use that.






          share|cite|improve this answer











          $endgroup$













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            1 Answer
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            1 Answer
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            active

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            active

            oldest

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            1












            $begingroup$

            I have no final answer but this is my progress:



            Here is an explicit formula for $P(p)$:
            $$P(p) = 1 - (1-p^M-1)^N^M-2$$



            Here $1 - p^M-1$ is the probability that a complete path from $v_1$ to $v_M$ is not completely connected and $N^M-2$ is the number of possible paths from $v_1$ to $v_M$. (Where $v_i$ is some node in generation $i$).



            Inserting $M=3$ and $p_0 = N^frac-12$ gives you:
            $$P(p_0) = 1 - left(fracN-1Nright)^N.$$



            Your general formula for $p_0$ will give you:
            $$P(p_0) = 1 - left( fracK-1K right)^K$$
            where $K := N^M-2$



            Increasing $p_0$ above that threshold will decrease the subtractor, thus increasing $P(p_0)$, which follows the intuition. Decreasing $p_0$ will decrease the whole expression, thus making $P$ monotonically increasing in $p_0$.



            I can't really see a clear transition here. Still curious if you can use that.






            share|cite|improve this answer











            $endgroup$

















              1












              $begingroup$

              I have no final answer but this is my progress:



              Here is an explicit formula for $P(p)$:
              $$P(p) = 1 - (1-p^M-1)^N^M-2$$



              Here $1 - p^M-1$ is the probability that a complete path from $v_1$ to $v_M$ is not completely connected and $N^M-2$ is the number of possible paths from $v_1$ to $v_M$. (Where $v_i$ is some node in generation $i$).



              Inserting $M=3$ and $p_0 = N^frac-12$ gives you:
              $$P(p_0) = 1 - left(fracN-1Nright)^N.$$



              Your general formula for $p_0$ will give you:
              $$P(p_0) = 1 - left( fracK-1K right)^K$$
              where $K := N^M-2$



              Increasing $p_0$ above that threshold will decrease the subtractor, thus increasing $P(p_0)$, which follows the intuition. Decreasing $p_0$ will decrease the whole expression, thus making $P$ monotonically increasing in $p_0$.



              I can't really see a clear transition here. Still curious if you can use that.






              share|cite|improve this answer











              $endgroup$















                1












                1








                1





                $begingroup$

                I have no final answer but this is my progress:



                Here is an explicit formula for $P(p)$:
                $$P(p) = 1 - (1-p^M-1)^N^M-2$$



                Here $1 - p^M-1$ is the probability that a complete path from $v_1$ to $v_M$ is not completely connected and $N^M-2$ is the number of possible paths from $v_1$ to $v_M$. (Where $v_i$ is some node in generation $i$).



                Inserting $M=3$ and $p_0 = N^frac-12$ gives you:
                $$P(p_0) = 1 - left(fracN-1Nright)^N.$$



                Your general formula for $p_0$ will give you:
                $$P(p_0) = 1 - left( fracK-1K right)^K$$
                where $K := N^M-2$



                Increasing $p_0$ above that threshold will decrease the subtractor, thus increasing $P(p_0)$, which follows the intuition. Decreasing $p_0$ will decrease the whole expression, thus making $P$ monotonically increasing in $p_0$.



                I can't really see a clear transition here. Still curious if you can use that.






                share|cite|improve this answer











                $endgroup$



                I have no final answer but this is my progress:



                Here is an explicit formula for $P(p)$:
                $$P(p) = 1 - (1-p^M-1)^N^M-2$$



                Here $1 - p^M-1$ is the probability that a complete path from $v_1$ to $v_M$ is not completely connected and $N^M-2$ is the number of possible paths from $v_1$ to $v_M$. (Where $v_i$ is some node in generation $i$).



                Inserting $M=3$ and $p_0 = N^frac-12$ gives you:
                $$P(p_0) = 1 - left(fracN-1Nright)^N.$$



                Your general formula for $p_0$ will give you:
                $$P(p_0) = 1 - left( fracK-1K right)^K$$
                where $K := N^M-2$



                Increasing $p_0$ above that threshold will decrease the subtractor, thus increasing $P(p_0)$, which follows the intuition. Decreasing $p_0$ will decrease the whole expression, thus making $P$ monotonically increasing in $p_0$.



                I can't really see a clear transition here. Still curious if you can use that.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Mar 30 at 16:52









                Alan Muniz

                2,61311030




                2,61311030










                answered Mar 30 at 16:44









                Lennart ScharmannLennart Scharmann

                112




                112



























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