multiplier algebra of a non-unital $C^*$ algebra The 2019 Stack Overflow Developer Survey Results Are InUnital C*-Algebras: Multiplier AlgebraQuasi-unital maps between multiplier algebras$*$ homomorphism $phi$ from $A$ to multiplier algebra $M(I)$state on a non-unital $C^*$ algebracommutant of a non unital $C^*$ algebratracial state on a non-unital $C^*$ algebrainfinite dimensional quotient of a $C^*$ algebratracial state on a unital infinite dimensional simple $C^*$ algebrainfinite dimensional representation of a $C^*$ algebraconnection between unital $C^*$ algebra and finite von neumann algebra
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multiplier algebra of a non-unital $C^*$ algebra
The 2019 Stack Overflow Developer Survey Results Are InUnital C*-Algebras: Multiplier AlgebraQuasi-unital maps between multiplier algebras$*$ homomorphism $phi$ from $A$ to multiplier algebra $M(I)$state on a non-unital $C^*$ algebracommutant of a non unital $C^*$ algebratracial state on a non-unital $C^*$ algebrainfinite dimensional quotient of a $C^*$ algebratracial state on a unital infinite dimensional simple $C^*$ algebrainfinite dimensional representation of a $C^*$ algebraconnection between unital $C^*$ algebra and finite von neumann algebra
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Given any infinite dimensional unital $C^*$ algebra $A$,does there must exist a non-unital $C^*$ algebra $B$ such that the multiplier algebra $M(B)$ of $B$ is $A$?
operator-theory operator-algebras c-star-algebras
asked Mar 30 at 17:27
mathrookiemathrookie
936512
$endgroup$
add a comment |
$begingroup$
Given any infinite dimensional unital $C^*$ algebra $A$,does there must exist a non-unital $C^*$ algebra $B$ such that the multiplier algebra $M(B)$ of $B$ is $A$?
operator-theory operator-algebras c-star-algebras
asked Mar 30 at 17:27
mathrookiemathrookie
936512
$endgroup$
add a comment |
$begingroup$
Given any infinite dimensional unital $C^*$ algebra $A$,does there must exist a non-unital $C^*$ algebra $B$ such that the multiplier algebra $M(B)$ of $B$ is $A$?
operator-theory operator-algebras c-star-algebras
asked Mar 30 at 17:27
mathrookiemathrookie
936512
$endgroup$
Given any infinite dimensional unital $C^*$ algebra $A$,does there must exist a non-unital $C^*$ algebra $B$ such that the multiplier algebra $M(B)$ of $B$ is $A$?
operator-theory operator-algebras c-star-algebras
operator-theory operator-algebras c-star-algebras
asked Mar 30 at 17:27
mathrookiemathrookie
936512
asked Mar 30 at 17:27
mathrookiemathrookie
936512
asked Mar 30 at 17:27
mathrookiemathrookie
936512
asked Mar 30 at 17:27
mathrookiemathrookie
936512
asked Mar 30 at 17:27
mathrookiemathrookie
936512
936512
add a comment |
add a comment |
1 Answer
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No. The multiplier algebra of $M(B)$ of $B$ has $B$ as an essential ideal. So any simple $A$ will be a counterexample.
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
$endgroup$
add a comment |
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1 Answer
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$begingroup$
No. The multiplier algebra of $M(B)$ of $B$ has $B$ as an essential ideal. So any simple $A$ will be a counterexample.
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
$endgroup$
add a comment |
$begingroup$
No. The multiplier algebra of $M(B)$ of $B$ has $B$ as an essential ideal. So any simple $A$ will be a counterexample.
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
$endgroup$
add a comment |
$begingroup$
No. The multiplier algebra of $M(B)$ of $B$ has $B$ as an essential ideal. So any simple $A$ will be a counterexample.
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
$endgroup$
No. The multiplier algebra of $M(B)$ of $B$ has $B$ as an essential ideal. So any simple $A$ will be a counterexample.
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
answered Mar 30 at 19:19
Martin ArgeramiMartin Argerami
129k1184185
129k1184185
add a comment |
add a comment |
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