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Permutations with identical objects 10 [closed]

0

$begingroup$

new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!

combinatorics permutations

share|cite|improve this question

asked Mar 30 at 17:29

gkoutgkout

51

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closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
  $endgroup$
  – jgon
  Mar 30 at 18:02
  

  
  
  
  

add a comment | 

0

$begingroup$

new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!

combinatorics permutations

share|cite|improve this question

asked Mar 30 at 17:29

gkoutgkout

51

$endgroup$

closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
  $endgroup$
  – jgon
  Mar 30 at 18:02
  

  
  
  
  

add a comment | 

$begingroup$

new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!

combinatorics permutations

share|cite|improve this question

asked Mar 30 at 17:29

gkoutgkout

51

$endgroup$

share|cite|improve this question

asked Mar 30 at 17:29

gkoutgkout

51

share|cite|improve this question

asked Mar 30 at 17:29

gkoutgkout

51

asked Mar 30 at 17:29

gkoutgkout

51

asked Mar 30 at 17:29

gkoutgkout

51

1 Answer
1

active

oldest

votes

1

$begingroup$

There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).

share|cite|improve this answer

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you !! :)
  $endgroup$
  – gkout
  Mar 30 at 17:58
  

  
  
  
  

add a comment | 

1

$begingroup$

There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).

share|cite|improve this answer

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you !! :)
  $endgroup$
  – gkout
  Mar 30 at 17:58
  

  
  
  
  

add a comment | 

1

$begingroup$

There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).

share|cite|improve this answer

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you !! :)
  $endgroup$
  – gkout
  Mar 30 at 17:58
  

  
  
  
  

add a comment | 

$begingroup$

There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).

share|cite|improve this answer

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

$endgroup$

share|cite|improve this answer

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318

answered Mar 30 at 17:49

Peter ForemanPeter Foreman

6,9401318