Permutations with identical objects 10 [closed] The 2019 Stack Overflow Developer Survey Results Are InPermutations with identical objectsHow to calculate Permutations if you have more places than distinct objectsPermute “aaaaabbbbbccccc” so that no two identical letters are adjacentPermutations with repeating digitsPermutation and combination of identical objectsHow many 4-letter “words” have no two consecutive letters identical - clarification needed on answerNumber of ways of selecting $N$ items from $k$ different types of identical itemsIn what number of “fallah” word's permutations we see identical letters next to each other?Permutations with repetitions, when you're not picking all the objects?permutation with repeated identical elements
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Permutations with identical objects 10 [closed]
The 2019 Stack Overflow Developer Survey Results Are InPermutations with identical objectsHow to calculate Permutations if you have more places than distinct objectsPermute “aaaaabbbbbccccc” so that no two identical letters are adjacentPermutations with repeating digitsPermutation and combination of identical objectsHow many 4-letter “words” have no two consecutive letters identical - clarification needed on answerNumber of ways of selecting $N$ items from $k$ different types of identical itemsIn what number of “fallah” word's permutations we see identical letters next to each other?Permutations with repetitions, when you're not picking all the objects?permutation with repeated identical elements
$begingroup$
new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!
combinatorics permutations
asked Mar 30 at 17:29
gkoutgkout
51
$endgroup$
closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus
add a comment |
$begingroup$
new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!
combinatorics permutations
asked Mar 30 at 17:29
gkoutgkout
51
$endgroup$
closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus
1
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02
add a comment |
$begingroup$
new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!
combinatorics permutations
asked Mar 30 at 17:29
gkoutgkout
51
$endgroup$
new to MSE :) I am confused with permutation problems involving identical objects.For example set = GGGBP how many 2-letter strings can be produced?
Thanks in advance!
combinatorics permutations
combinatorics permutations
asked Mar 30 at 17:29
gkoutgkout
51
asked Mar 30 at 17:29
gkoutgkout
51
asked Mar 30 at 17:29
gkoutgkout
51
asked Mar 30 at 17:29
gkoutgkout
51
asked Mar 30 at 17:29
gkoutgkout
51
51
closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus
closed as off-topic by Paul Frost, max_zorn, Leucippus, Javi, Lord Shark the Unknown Mar 31 at 4:54
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Paul Frost, max_zorn, Leucippus
1
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02
add a comment |
1
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02
1
1
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
$endgroup$
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
$endgroup$
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
add a comment |
$begingroup$
There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
$endgroup$
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
add a comment |
$begingroup$
There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
$endgroup$
There are $3$ different characters to select, so the number of length $2$ strings is
$$3cdot3-2=7$$
As this counts every combination of the $3$ letters ($3cdot3$) except where the letters $B, P$ are selected twice ($-2$).
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
answered Mar 30 at 17:49
Peter ForemanPeter Foreman
6,9401318
6,9401318
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
add a comment |
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
$begingroup$
Thank you !! :)
$endgroup$
– gkout
Mar 30 at 17:58
add a comment |
1
$begingroup$
What have you tried? Where are you getting confused? Have you tried writing out all the possibilities and looking for patterns?
$endgroup$
– jgon
Mar 30 at 18:02