How to differentiate, for example, f(r,t ) wrt r without knowing in what way f depends on r and t? The 2019 Stack Overflow Developer Survey Results Are InFinding the Derivative Of $f(x) = 7ln(5xe^-x)$Chain rule and matrices - I'm confusedWirtinger derivative of composition of functionsNotation regarding different derivativesImplicit Second Derivatives using Partial Derivativeswhat is $fracdd(ax)f(x)$ and $fracdd(ax)f(x)$Chain rule for equations of multiple variablesDifferentiation of partial derivativesHow to compute this derivative of a square root of a sum?Partial derivative of a definite integral
Why is the Constellation's nose gear so long?
What is the accessibility of a package's `Private` context variables?
Did 3000BC Egyptians use meteoric iron weapons?
Did Scotland spend $250,000 for the slogan "Welcome to Scotland"?
Loose spokes after only a few rides
For what reasons would an animal species NOT cross a *horizontal* land bridge?
What is the most effective way of iterating a std::vector and why?
Why didn't the Event Horizon Telescope team mention Sagittarius A*?
How to support a colleague who finds meetings extremely tiring?
How technical should a Scrum Master be to effectively remove impediments?
Do these rules for Critical Successes and Critical Failures seem Fair?
How come people say “Would of”?
Why isn't airport relocation done gradually?
Multiply Two Integer Polynomials
Why do we hear so much about the Trump administration deciding to impose and then remove tariffs?
How to deal with fear of taking dependencies
One word riddle: Vowel in the middle
Is flight data recorder erased after every flight?
Is a "Democratic" Oligarchy-Style System Possible?
Should I use my personal e-mail address, or my workplace one, when registering to external websites for work purposes?
How are circuits which use complex ICs normally simulated?
Can a rogue use sneak attack with weapons that have the thrown property even if they are not thrown?
Why do UK politicians seemingly ignore opinion polls on Brexit?
A poker game description that does not feel gimmicky
How to differentiate, for example, f(r,t ) wrt r without knowing in what way f depends on r and t?
The 2019 Stack Overflow Developer Survey Results Are InFinding the Derivative Of $f(x) = 7ln(5xe^-x)$Chain rule and matrices - I'm confusedWirtinger derivative of composition of functionsNotation regarding different derivativesImplicit Second Derivatives using Partial Derivativeswhat is $fracdd(ax)f(x)$ and $fracdd(ax)f(x)$Chain rule for equations of multiple variablesDifferentiation of partial derivativesHow to compute this derivative of a square root of a sum?Partial derivative of a definite integral
$begingroup$
Say we have some function $psi'(r,t)$, given by $psi'(r,t)=e^af(r,t)psi(r,t)$
and we want to calculate $nabla^2psi'(r,t)$.
I obviously know how to do all the basic steps of this product rule , chain rule and all that but there's one part I'm a little unsure of ( I always found it a little confusing , I used to know how to do it but I forgot )
Basically in the parts of the equation where we have $tfracpartial f(r,t)partial r,tfracpartial f(r,t) partial t, tfracpartial psi(r,t)partial r,tfracpartialpsi(r,t)partial t$, I want to know how we can deal with these ?
(If what I'm asking isn't clear , please ask me to elucidate and I'll write more about what it is specifically that confuses me )
derivatives implicit-differentiation
$endgroup$
add a comment |
$begingroup$
Say we have some function $psi'(r,t)$, given by $psi'(r,t)=e^af(r,t)psi(r,t)$
and we want to calculate $nabla^2psi'(r,t)$.
I obviously know how to do all the basic steps of this product rule , chain rule and all that but there's one part I'm a little unsure of ( I always found it a little confusing , I used to know how to do it but I forgot )
Basically in the parts of the equation where we have $tfracpartial f(r,t)partial r,tfracpartial f(r,t) partial t, tfracpartial psi(r,t)partial r,tfracpartialpsi(r,t)partial t$, I want to know how we can deal with these ?
(If what I'm asking isn't clear , please ask me to elucidate and I'll write more about what it is specifically that confuses me )
derivatives implicit-differentiation
$endgroup$
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25
add a comment |
$begingroup$
Say we have some function $psi'(r,t)$, given by $psi'(r,t)=e^af(r,t)psi(r,t)$
and we want to calculate $nabla^2psi'(r,t)$.
I obviously know how to do all the basic steps of this product rule , chain rule and all that but there's one part I'm a little unsure of ( I always found it a little confusing , I used to know how to do it but I forgot )
Basically in the parts of the equation where we have $tfracpartial f(r,t)partial r,tfracpartial f(r,t) partial t, tfracpartial psi(r,t)partial r,tfracpartialpsi(r,t)partial t$, I want to know how we can deal with these ?
(If what I'm asking isn't clear , please ask me to elucidate and I'll write more about what it is specifically that confuses me )
derivatives implicit-differentiation
$endgroup$
Say we have some function $psi'(r,t)$, given by $psi'(r,t)=e^af(r,t)psi(r,t)$
and we want to calculate $nabla^2psi'(r,t)$.
I obviously know how to do all the basic steps of this product rule , chain rule and all that but there's one part I'm a little unsure of ( I always found it a little confusing , I used to know how to do it but I forgot )
Basically in the parts of the equation where we have $tfracpartial f(r,t)partial r,tfracpartial f(r,t) partial t, tfracpartial psi(r,t)partial r,tfracpartialpsi(r,t)partial t$, I want to know how we can deal with these ?
(If what I'm asking isn't clear , please ask me to elucidate and I'll write more about what it is specifically that confuses me )
derivatives implicit-differentiation
derivatives implicit-differentiation
asked Mar 30 at 17:23
can'tcauchycan'tcauchy
1,022417
1,022417
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25
add a comment |
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
WLOG, we can parameterize r and t by some parameter $tau$. We then have $$fracd fd tau = fracpartial fpartial rfracdrdtau+fracpartial fpartial tfracdtdtau$$
From here, you should be able to re-arrange the equation and use identities similar to the Maxwell relations to have your formula depend only on full derivatives instead of partials, which in my opinion, would be a simplified version.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3168549%2fhow-to-differentiate-for-example-fr-t-wrt-r-without-knowing-in-what-way-f-d%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
WLOG, we can parameterize r and t by some parameter $tau$. We then have $$fracd fd tau = fracpartial fpartial rfracdrdtau+fracpartial fpartial tfracdtdtau$$
From here, you should be able to re-arrange the equation and use identities similar to the Maxwell relations to have your formula depend only on full derivatives instead of partials, which in my opinion, would be a simplified version.
$endgroup$
add a comment |
$begingroup$
WLOG, we can parameterize r and t by some parameter $tau$. We then have $$fracd fd tau = fracpartial fpartial rfracdrdtau+fracpartial fpartial tfracdtdtau$$
From here, you should be able to re-arrange the equation and use identities similar to the Maxwell relations to have your formula depend only on full derivatives instead of partials, which in my opinion, would be a simplified version.
$endgroup$
add a comment |
$begingroup$
WLOG, we can parameterize r and t by some parameter $tau$. We then have $$fracd fd tau = fracpartial fpartial rfracdrdtau+fracpartial fpartial tfracdtdtau$$
From here, you should be able to re-arrange the equation and use identities similar to the Maxwell relations to have your formula depend only on full derivatives instead of partials, which in my opinion, would be a simplified version.
$endgroup$
WLOG, we can parameterize r and t by some parameter $tau$. We then have $$fracd fd tau = fracpartial fpartial rfracdrdtau+fracpartial fpartial tfracdtdtau$$
From here, you should be able to re-arrange the equation and use identities similar to the Maxwell relations to have your formula depend only on full derivatives instead of partials, which in my opinion, would be a simplified version.
answered Apr 1 at 10:37
Polly M.Polly M.
1
1
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3168549%2fhow-to-differentiate-for-example-fr-t-wrt-r-without-knowing-in-what-way-f-d%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
If you know what $f$ and $psi$ are, then you can evaluate those derivatives; otherwise, you just leave them like that. Or are you asking how to evaluate the partial derivatives of a multi-variable function?
$endgroup$
– Sambo
Mar 30 at 17:27
$begingroup$
@Sambo I was just asking is there a way to reduce them further than what I wrote above if we don't know anything about the form of the function except that they depend on r and t
$endgroup$
– can'tcauchy
Mar 30 at 17:32
$begingroup$
Then no, there is no way to reduce them further. Similar to how you can't reduce $df(x)/dx$ further.
$endgroup$
– Sambo
Mar 31 at 4:25