Finding value of an integral Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Can someone help me to evaluate this integral:Calculus Question: Improper integral $int_0^inftyfraccos(2x+1)sqrt[3]xdx$Integral $int_pi/2+delta^3pi/2-delta x^R cos varphi d varphi$ boundedEvaluate $int_0^1 fraclog(x)sqrt1 - x^2$ complex integrationIntegral of $e^2sin x$Definite integral (exact value): Help solving this definite integralIntegral of log over a square rootMIT 2015 Integration QuestionLooking for idea to solve an integralDefinite integral with logarithm and sine
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Finding value of an integral
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Can someone help me to evaluate this integral:Calculus Question: Improper integral $int_0^inftyfraccos(2x+1)sqrt[3]xdx$Integral $int_pi/2+delta^3pi/2-delta x^R cos varphi d varphi$ boundedEvaluate $int_0^1 fraclog(x)sqrt1 - x^2$ complex integrationIntegral of $e^2sin x$Definite integral (exact value): Help solving this definite integralIntegral of log over a square rootMIT 2015 Integration QuestionLooking for idea to solve an integralDefinite integral with logarithm and sine
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I was trying to find $int_0^1sqrtt^4+t^2+1dt$.
I’ve tried substitution $u=tan x$ but end with unpleasant integral. If someone have an idea, even complex integration, I’ll take
real-analysis calculus integration complex-analysis
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|
show 1 more comment
$begingroup$
I was trying to find $int_0^1sqrtt^4+t^2+1dt$.
I’ve tried substitution $u=tan x$ but end with unpleasant integral. If someone have an idea, even complex integration, I’ll take
real-analysis calculus integration complex-analysis
$endgroup$
$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
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By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27
|
show 1 more comment
$begingroup$
I was trying to find $int_0^1sqrtt^4+t^2+1dt$.
I’ve tried substitution $u=tan x$ but end with unpleasant integral. If someone have an idea, even complex integration, I’ll take
real-analysis calculus integration complex-analysis
$endgroup$
I was trying to find $int_0^1sqrtt^4+t^2+1dt$.
I’ve tried substitution $u=tan x$ but end with unpleasant integral. If someone have an idea, even complex integration, I’ll take
real-analysis calculus integration complex-analysis
real-analysis calculus integration complex-analysis
asked Apr 2 at 16:40
HAMIDINE SOUMAREHAMIDINE SOUMARE
2,8831420
2,8831420
$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
$begingroup$
By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27
|
show 1 more comment
$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
$begingroup$
By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27
$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
$begingroup$
By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27
|
show 1 more comment
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$begingroup$
Only a numerical solution is possible.
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 16:58
$begingroup$
By numerical do you mean approximative solution???
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 16:59
$begingroup$
Yes that is what i mean
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:05
$begingroup$
Can you provide a numerical one.
$endgroup$
– HAMIDINE SOUMARE
Apr 2 at 17:13
$begingroup$
See here $$1/3,frac 2,iit EllipticF left( 1/2+i/2sqrt 3,1/2+i/2sqrt 3 right) sqrt 3-sqrt 3+3,i+2,it EllipticE left( 1/2+i/2 sqrt 3,1/2+i/2sqrt 3 right) -1+isqrt 3 $$
$endgroup$
– Dr. Sonnhard Graubner
Apr 2 at 17:27