Why is sine opposite over hypotenuse? [closed] The 2019 Stack Overflow Developer Survey Results Are InWhy was the inverse sine ratio used? and not sine?Adjacent versus Opposite Angles in Right Triangles (Trigonometry)Sine of an obtuse angleWhy can $(x,y)$ coordinates be defined as $(costheta,sintheta)$ for the unit circle?Why do trigonometric functions work?If trigonometric ratios are just ratios of length of sides, then why do they become negative?Find the coordinates of the vector in quadrant 4, in terms of $sin(theta)$ and $cos(theta)$. Assume the hypotenuse is equal to 1.Relationship Between Sine as a Series and Sine in TrianglesIf sin = opposite/hypotenuse, then why we need theta (angle)Entry level questions about the trig function sine
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Why is sine opposite over hypotenuse? [closed]
The 2019 Stack Overflow Developer Survey Results Are InWhy was the inverse sine ratio used? and not sine?Adjacent versus Opposite Angles in Right Triangles (Trigonometry)Sine of an obtuse angleWhy can $(x,y)$ coordinates be defined as $(costheta,sintheta)$ for the unit circle?Why do trigonometric functions work?If trigonometric ratios are just ratios of length of sides, then why do they become negative?Find the coordinates of the vector in quadrant 4, in terms of $sin(theta)$ and $cos(theta)$. Assume the hypotenuse is equal to 1.Relationship Between Sine as a Series and Sine in TrianglesIf sin = opposite/hypotenuse, then why we need theta (angle)Entry level questions about the trig function sine
$begingroup$
How can I prove that the sine of θ is opposite over hypotenuse?
$$sintheta = fractextoppositetexthypotenuse $$
trigonometry
edited Mar 30 at 10:01
Infiaria
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
$endgroup$
closed as off-topic by Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician Apr 2 at 6:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician
add a comment |
$begingroup$
How can I prove that the sine of θ is opposite over hypotenuse?
$$sintheta = fractextoppositetexthypotenuse $$
trigonometry
edited Mar 30 at 10:01
Infiaria
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
$endgroup$
closed as off-topic by Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician Apr 2 at 6:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician
4
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
1
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04
add a comment |
$begingroup$
How can I prove that the sine of θ is opposite over hypotenuse?
$$sintheta = fractextoppositetexthypotenuse $$
trigonometry
edited Mar 30 at 10:01
Infiaria
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
$endgroup$
How can I prove that the sine of θ is opposite over hypotenuse?
$$sintheta = fractextoppositetexthypotenuse $$
trigonometry
trigonometry
edited Mar 30 at 10:01
Infiaria
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
edited Mar 30 at 10:01
Infiaria
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
edited Mar 30 at 10:01
Infiaria
46811
edited Mar 30 at 10:01
Infiaria
46811
edited Mar 30 at 10:01
Infiaria
46811
46811
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
asked Mar 30 at 9:57
David SalgadoDavid Salgado
1
1
closed as off-topic by Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician Apr 2 at 6:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician
closed as off-topic by Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician Apr 2 at 6:41
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Hans Lundmark, NCh, Leucippus, Tianlalu, ancientmathematician
4
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
1
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04
add a comment |
4
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
1
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04
4
4
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
1
1
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04
add a comment |
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4
$begingroup$
That is a definiton, there is nothing to prove.
$endgroup$
– Maria Mazur
Mar 30 at 9:58
$begingroup$
@MariaMazur How is it known to be true for all cases in which the definition is established?
$endgroup$
– David Salgado
Mar 30 at 10:00
$begingroup$
$sin(cdot)$ is a function that refers to dividing the opposite by the hypotenuse. Why? Because we just so happened to define it that way for simplicity. Why is $x$ the most commonly used variable in algebra? Same ordeal.
$endgroup$
– user477343
Mar 30 at 10:03
1
$begingroup$
Maybe your definition of $sin x$ is in terms of power series? As it currently stands, this question is lacking context.
$endgroup$
– YuiTo Cheng
Mar 30 at 10:04
$begingroup$
I understand, thank you.
$endgroup$
– David Salgado
Mar 30 at 10:04