Dgdrxrt

How can I create a character who can assume the widest possible range of creature sizes?

Can I write a for loop that iterates over both collections and arrays?

On the insanity of kings as an argument against Monarchy

Is domain driven design an anti-SQL pattern?

What tool would a Roman-age civilisation use to reduce/breakup silver and other metals?

Can't find the latex code for the ⍎ (down tack jot) symbol

JSON.serialize: is it possible to suppress null values of a map?

Springs with some finite mass

What is this 4-propeller plane?

Evaluating number of iteration with a certain map with While

Extreme, unacceptable situation and I can't attend work tomorrow morning

I looked up a future colleague on linkedin before I started a job. I told my colleague about it and he seemed surprised. Should I apologize?

Spanish for "widget"

Inversion Puzzle

A poker game description that does not feel gimmicky

What do the Banks children have against barley water?

What does "sndry explns" mean in one of the Hitchhiker's guide books?

What is the use of option -o in the useradd command?

Fractional alignment

Output the Arecibo Message

"What time...?" or "At what time...?" - what is more grammatically correct?

Feasability of miniature nuclear reactors for humanoid cyborgs

Families of ordered set partitions with disjoint blocks

Poison Arrows Piercing damage reduced to 0, do you still get poisoned?

Using L'Hospital's Rule on $cos (2x)^frac 1 x^2.$ [closed]

-3

1

$begingroup$

How might one evaluate the following limit using L'Hopital's Rule:$$lim_xrightarrow0cos(2x)^frac1x^2$$

limits analysis

share|cite|improve this question

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

$endgroup$

closed as off-topic by RRL, Eevee Trainer, mrtaurho, Cesareo, Javi Apr 1 at 10:33

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Eevee Trainer, mrtaurho, Cesareo, Javi

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  What have you tried?
  $endgroup$
  – Kezer
  Mar 30 at 9:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Arrived at $e^-2$ using $e^lim_xrightarrow0 fracln(cos(2x))x^2$
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:57
  
  

  
  
  
  

add a comment | 

-3

1

$begingroup$

How might one evaluate the following limit using L'Hopital's Rule:$$lim_xrightarrow0cos(2x)^frac1x^2$$

limits analysis

share|cite|improve this question

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

$endgroup$

closed as off-topic by RRL, Eevee Trainer, mrtaurho, Cesareo, Javi Apr 1 at 10:33

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Eevee Trainer, mrtaurho, Cesareo, Javi

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  What have you tried?
  $endgroup$
  – Kezer
  Mar 30 at 9:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Arrived at $e^-2$ using $e^lim_xrightarrow0 fracln(cos(2x))x^2$
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:57
  
  

  
  
  
  

add a comment | 

$begingroup$

How might one evaluate the following limit using L'Hopital's Rule:$$lim_xrightarrow0cos(2x)^frac1x^2$$

limits analysis

share|cite|improve this question

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

$endgroup$

share|cite|improve this question

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

share|cite|improve this question

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

edited Mar 30 at 10:19

Bernard

124k741117

edited Mar 30 at 10:19

Bernard

124k741117

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

asked Mar 30 at 9:29

Ali LodhiAli Lodhi

383

2 Answers
2

active

oldest

votes

0

$begingroup$

Hint: Write $$e^lim_xto 0fracln(cos(2x)x^2$$

share|cite|improve this answer

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Right, thankyou.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:33
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Want you to know the result?
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, I want to know the result.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:48
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is $$e^-2$$
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, arrived at that. Thank you.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:53
  

  
  
  
  

add a comment | 

0

$begingroup$

Hint:

$$y=cos(2x)^1/x^2Rightarrow ln y=4fraclncos(2x)(2x)^2\
1-frac1zleqln zleq z-1$$

share|cite|improve this answer

answered Mar 30 at 9:58

JamJam

5,01921432

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Proof of bounds: proofwiki.org/wiki/Bounds_of_Natural_Logarithm
  $endgroup$
  – Jam
  Mar 30 at 9:59
  

  
  
  
  

add a comment | 

0

$begingroup$

Hint: Write $$e^lim_xto 0fracln(cos(2x)x^2$$

share|cite|improve this answer

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Right, thankyou.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:33
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Want you to know the result?
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, I want to know the result.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:48
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is $$e^-2$$
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, arrived at that. Thank you.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:53
  

  
  
  
  

add a comment | 

0

$begingroup$

Hint: Write $$e^lim_xto 0fracln(cos(2x)x^2$$

share|cite|improve this answer

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Right, thankyou.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:33
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Want you to know the result?
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:34
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, I want to know the result.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:48
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It is $$e^-2$$
  $endgroup$
  – Dr. Sonnhard Graubner
  Mar 30 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yes, arrived at that. Thank you.
  $endgroup$
  – Ali Lodhi
  Mar 30 at 9:53
  

  
  
  
  

add a comment | 

$begingroup$

Hint: Write $$e^lim_xto 0fracln(cos(2x)x^2$$

share|cite|improve this answer

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

$endgroup$

share|cite|improve this answer

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

answered Mar 30 at 9:31

Dr. Sonnhard GraubnerDr. Sonnhard Graubner

78.8k42867

0

$begingroup$

Hint:

$$y=cos(2x)^1/x^2Rightarrow ln y=4fraclncos(2x)(2x)^2\
1-frac1zleqln zleq z-1$$

share|cite|improve this answer

answered Mar 30 at 9:58

JamJam

5,01921432

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Proof of bounds: proofwiki.org/wiki/Bounds_of_Natural_Logarithm
  $endgroup$
  – Jam
  Mar 30 at 9:59
  

  
  
  
  

add a comment | 

0

$begingroup$

Hint:

$$y=cos(2x)^1/x^2Rightarrow ln y=4fraclncos(2x)(2x)^2\
1-frac1zleqln zleq z-1$$

share|cite|improve this answer

answered Mar 30 at 9:58

JamJam

5,01921432

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Proof of bounds: proofwiki.org/wiki/Bounds_of_Natural_Logarithm
  $endgroup$
  – Jam
  Mar 30 at 9:59
  

  
  
  
  

add a comment | 

$begingroup$

Hint:

$$y=cos(2x)^1/x^2Rightarrow ln y=4fraclncos(2x)(2x)^2\
1-frac1zleqln zleq z-1$$

share|cite|improve this answer

answered Mar 30 at 9:58

JamJam

5,01921432

$endgroup$

share|cite|improve this answer

answered Mar 30 at 9:58

JamJam

5,01921432

answered Mar 30 at 9:58

JamJam

5,01921432

answered Mar 30 at 9:58

JamJam

5,01921432