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Show that the dual of $min c^Tx+d^Tx^'$ and $max a^Tx+b^Tx^'$ are equivalent
The Next CEO of Stack OverflowDuality. Is this the correct Dual to this Primal L.P.?Show that the dual of the dual is the primal for a min problemHow can I derive the following dual problem?Find the dual of the lp problemLinear optimization and the dualPrimal-dual problems of LP'sWrite down the dual LP and show that $y$ is a feasible solution to the dual LP.Deriving the dual of the minimum cost flow problem.How do I derive the Dual problem of a Primal LP with equality constraints?How to find the dual of max flow using bounding?
$begingroup$
Show that $(1)$ can be written in the form $(2)$
$(1)$
$min c^Tx+d^Tx^'$
$operatornames.t.$
$Ax+Bx^'geq a$
$Cx+Dx^'= b$
where $x, x^' geq 0$ and
and
$(2)$ $max a^Ty+b^Ty^'$
$operatornames.t.$
$A^Ty+C^Ty^'leq c$
$By+Dy^'= d$
where $y,y^' geq 0$
My idea:
The restrictions $(1)$ can be written in the form:
$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$
Then the dual LP to $(1)$ can be written as:
$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$
$operatornames.t.$
$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$
But how do I get to writing this in the form of $(2)$
Any help is greatly appreciated.
optimization linear-programming duality-theorems
$endgroup$
This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.
Looking for an answer drawing from credible and/or official sources.
add a comment |
$begingroup$
Show that $(1)$ can be written in the form $(2)$
$(1)$
$min c^Tx+d^Tx^'$
$operatornames.t.$
$Ax+Bx^'geq a$
$Cx+Dx^'= b$
where $x, x^' geq 0$ and
and
$(2)$ $max a^Ty+b^Ty^'$
$operatornames.t.$
$A^Ty+C^Ty^'leq c$
$By+Dy^'= d$
where $y,y^' geq 0$
My idea:
The restrictions $(1)$ can be written in the form:
$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$
Then the dual LP to $(1)$ can be written as:
$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$
$operatornames.t.$
$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$
But how do I get to writing this in the form of $(2)$
Any help is greatly appreciated.
optimization linear-programming duality-theorems
$endgroup$
This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.
Looking for an answer drawing from credible and/or official sources.
$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago
add a comment |
$begingroup$
Show that $(1)$ can be written in the form $(2)$
$(1)$
$min c^Tx+d^Tx^'$
$operatornames.t.$
$Ax+Bx^'geq a$
$Cx+Dx^'= b$
where $x, x^' geq 0$ and
and
$(2)$ $max a^Ty+b^Ty^'$
$operatornames.t.$
$A^Ty+C^Ty^'leq c$
$By+Dy^'= d$
where $y,y^' geq 0$
My idea:
The restrictions $(1)$ can be written in the form:
$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$
Then the dual LP to $(1)$ can be written as:
$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$
$operatornames.t.$
$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$
But how do I get to writing this in the form of $(2)$
Any help is greatly appreciated.
optimization linear-programming duality-theorems
$endgroup$
Show that $(1)$ can be written in the form $(2)$
$(1)$
$min c^Tx+d^Tx^'$
$operatornames.t.$
$Ax+Bx^'geq a$
$Cx+Dx^'= b$
where $x, x^' geq 0$ and
and
$(2)$ $max a^Ty+b^Ty^'$
$operatornames.t.$
$A^Ty+C^Ty^'leq c$
$By+Dy^'= d$
where $y,y^' geq 0$
My idea:
The restrictions $(1)$ can be written in the form:
$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$
Then the dual LP to $(1)$ can be written as:
$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$
$operatornames.t.$
$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$
But how do I get to writing this in the form of $(2)$
Any help is greatly appreciated.
optimization linear-programming duality-theorems
optimization linear-programming duality-theorems
edited Mar 28 at 11:33
SABOY
asked Mar 28 at 11:10
SABOYSABOY
592311
592311
This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.
Looking for an answer drawing from credible and/or official sources.
This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.
Looking for an answer drawing from credible and/or official sources.
$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago
add a comment |
$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago
$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago
add a comment |
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$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32
$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33
$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago