Sections of a locally free sheaf The Next CEO of Stack OverflowSections of locally free sheavesDescribing a locally free sheaf sitting between two locally free sheaves which are given as extensionsQuotient of locally free sheaf is locally free?Sheaf of sections vanishing at a point is $Gamma(E) otimes I_p$Sheaf of sections of vector bundle over a manifold is an $mathcal O_M$-moduleRegular sections of an invertible sheafTotal space of a finite rank locally free sheaf, Vakil's 17.1.4 & 17.1.GVector Bundle Locally Free SheafSection of pullback bundle isomorphic to the sheaf pullback of sectionsSheaf Hom between locally free sheaves

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Sections of a locally free sheaf



The Next CEO of Stack OverflowSections of locally free sheavesDescribing a locally free sheaf sitting between two locally free sheaves which are given as extensionsQuotient of locally free sheaf is locally free?Sheaf of sections vanishing at a point is $Gamma(E) otimes I_p$Sheaf of sections of vector bundle over a manifold is an $mathcal O_M$-moduleRegular sections of an invertible sheafTotal space of a finite rank locally free sheaf, Vakil's 17.1.4 & 17.1.GVector Bundle Locally Free SheafSection of pullback bundle isomorphic to the sheaf pullback of sectionsSheaf Hom between locally free sheaves










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Let $mathcalF$ be a locally free sheaf of rank $n$ on a scheme $X$. We know that we can associate to it a vector bundle $F$ on $X$ such that $F_x simeq mathcalF(x)$, where with $mathcalF(x)$ I mean the fibre of the sheaf over the point $x$. We also know that the sheaf of sections of the vector bundle $F$ is isomorphic to the locally free sheaf we started with.
My question is the following: a section of $F$ is by definition a regular map $sigma : X rightarrow F$ such that $sigma(x) in F_x$ for any $x in X$, whereas a section of $mathcalF$ can be interpreted as a regular map $psi : X rightarrow sqcup_x in X mathcalF_x$. I can see a natural map from “sections of $mathcalF$” to “sections of $F$”, but how can one claim this is an isomorphism? Am I mixing something up?










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    $begingroup$


    Let $mathcalF$ be a locally free sheaf of rank $n$ on a scheme $X$. We know that we can associate to it a vector bundle $F$ on $X$ such that $F_x simeq mathcalF(x)$, where with $mathcalF(x)$ I mean the fibre of the sheaf over the point $x$. We also know that the sheaf of sections of the vector bundle $F$ is isomorphic to the locally free sheaf we started with.
    My question is the following: a section of $F$ is by definition a regular map $sigma : X rightarrow F$ such that $sigma(x) in F_x$ for any $x in X$, whereas a section of $mathcalF$ can be interpreted as a regular map $psi : X rightarrow sqcup_x in X mathcalF_x$. I can see a natural map from “sections of $mathcalF$” to “sections of $F$”, but how can one claim this is an isomorphism? Am I mixing something up?










    share|cite|improve this question









    $endgroup$














      0












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      0





      $begingroup$


      Let $mathcalF$ be a locally free sheaf of rank $n$ on a scheme $X$. We know that we can associate to it a vector bundle $F$ on $X$ such that $F_x simeq mathcalF(x)$, where with $mathcalF(x)$ I mean the fibre of the sheaf over the point $x$. We also know that the sheaf of sections of the vector bundle $F$ is isomorphic to the locally free sheaf we started with.
      My question is the following: a section of $F$ is by definition a regular map $sigma : X rightarrow F$ such that $sigma(x) in F_x$ for any $x in X$, whereas a section of $mathcalF$ can be interpreted as a regular map $psi : X rightarrow sqcup_x in X mathcalF_x$. I can see a natural map from “sections of $mathcalF$” to “sections of $F$”, but how can one claim this is an isomorphism? Am I mixing something up?










      share|cite|improve this question









      $endgroup$




      Let $mathcalF$ be a locally free sheaf of rank $n$ on a scheme $X$. We know that we can associate to it a vector bundle $F$ on $X$ such that $F_x simeq mathcalF(x)$, where with $mathcalF(x)$ I mean the fibre of the sheaf over the point $x$. We also know that the sheaf of sections of the vector bundle $F$ is isomorphic to the locally free sheaf we started with.
      My question is the following: a section of $F$ is by definition a regular map $sigma : X rightarrow F$ such that $sigma(x) in F_x$ for any $x in X$, whereas a section of $mathcalF$ can be interpreted as a regular map $psi : X rightarrow sqcup_x in X mathcalF_x$. I can see a natural map from “sections of $mathcalF$” to “sections of $F$”, but how can one claim this is an isomorphism? Am I mixing something up?







      sheaf-theory vector-bundles schemes






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      FedericoFederico

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