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How do I get all objects in a nested array after performing a calculation in JavaScript?
The Next CEO of Stack OverflowHow do I remove a property from a JavaScript object?How do you get a timestamp in JavaScript?How do I check if an array includes an object in JavaScript?How to insert an item into an array at a specific index (JavaScript)?How do I correctly clone a JavaScript object?How to replace all occurrences of a string in JavaScriptHow do I empty an array in JavaScript?How to check if an object is an array?How do I remove a particular element from an array in JavaScript?Find object by id in an array of JavaScript objects
6
I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
],
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
let send_amount = querydata.sourceamount.replace(/,/g,"");
let fee = objectdata.fee;
let rate = objectdata.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
return result_data;
result = config(obj, query);
Expected Output:
result = [
name: "insta",
fees: "2",
ratevalue: "2.00",
amountvalue: "3998",
receive: "7976"
country: "SG",
sourceamount: "4,000"
,
name: "transfer",
fees: "1",
ratevalue: "3.00",
amountvalue: "3997",
receive: "11,991"
country: "SG",
sourceamount: "4,000"
]
javascript jquery arrays object
edited yesterday
Boann
37.4k1290121
asked yesterday
SenthilSenthil
443
add a comment |
6
I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
],
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
let send_amount = querydata.sourceamount.replace(/,/g,"");
let fee = objectdata.fee;
let rate = objectdata.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
return result_data;
result = config(obj, query);
Expected Output:
result = [
name: "insta",
fees: "2",
ratevalue: "2.00",
amountvalue: "3998",
receive: "7976"
country: "SG",
sourceamount: "4,000"
,
name: "transfer",
fees: "1",
ratevalue: "3.00",
amountvalue: "3997",
receive: "11,991"
country: "SG",
sourceamount: "4,000"
]
javascript jquery arrays object
edited yesterday
Boann
37.4k1290121
asked yesterday
SenthilSenthil
443
where did you iterate it?
– M.Hemant
yesterday
add a comment |
6
6
6
I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
],
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
let send_amount = querydata.sourceamount.replace(/,/g,"");
let fee = objectdata.fee;
let rate = objectdata.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
return result_data;
result = config(obj, query);
Expected Output:
result = [
name: "insta",
fees: "2",
ratevalue: "2.00",
amountvalue: "3998",
receive: "7976"
country: "SG",
sourceamount: "4,000"
,
name: "transfer",
fees: "1",
ratevalue: "3.00",
amountvalue: "3997",
receive: "11,991"
country: "SG",
sourceamount: "4,000"
]
javascript jquery arrays object
edited yesterday
Boann
37.4k1290121
asked yesterday
SenthilSenthil
443
I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
],
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
let send_amount = querydata.sourceamount.replace(/,/g,"");
let fee = objectdata.fee;
let rate = objectdata.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
return result_data;
result = config(obj, query);
Expected Output:
result = [
name: "insta",
fees: "2",
ratevalue: "2.00",
amountvalue: "3998",
receive: "7976"
country: "SG",
sourceamount: "4,000"
,
name: "transfer",
fees: "1",
ratevalue: "3.00",
amountvalue: "3997",
receive: "11,991"
country: "SG",
sourceamount: "4,000"
]
javascript jquery arrays object
javascript jquery arrays object
edited yesterday
Boann
37.4k1290121
asked yesterday
SenthilSenthil
443
edited yesterday
Boann
37.4k1290121
asked yesterday
SenthilSenthil
443
edited yesterday
Boann
37.4k1290121
edited yesterday
Boann
37.4k1290121
edited yesterday
Boann
37.4k1290121
37.4k1290121
asked yesterday
SenthilSenthil
443
asked yesterday
SenthilSenthil
443
asked yesterday
SenthilSenthil
443
443
where did you iterate it?
– M.Hemant
yesterday
add a comment |
where did you iterate it?
– M.Hemant
yesterday
where did you iterate it?
– M.Hemant
yesterday
where did you iterate it?
– M.Hemant
yesterday
add a comment |
3 Answers
3
active
oldest
votes
3
You can use .map to loop your array and construct all your object.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)answered yesterday
R3tepR3tep
8,13882962
3
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From wheresendproperty come. Andsourceamountwhich is expected output and4000should be"4,000"
– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for"4,000"
– R3tep
yesterday
I mistypedsourceamountthere wassendproperty in old code. But now its fine so +1
– Maheer Ali
yesterday
add a comment |
7
You need to map through the obj array and construct your output.
NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
add a comment |
3
const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)answered yesterday
Francis LeighFrancis Leigh
901313
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You can use .map to loop your array and construct all your object.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)answered yesterday
R3tepR3tep
8,13882962
3
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From wheresendproperty come. Andsourceamountwhich is expected output and4000should be"4,000"
– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for"4,000"
– R3tep
yesterday
I mistypedsourceamountthere wassendproperty in old code. But now its fine so +1
– Maheer Ali
yesterday
add a comment |
3
You can use .map to loop your array and construct all your object.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)answered yesterday
R3tepR3tep
8,13882962
3
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From wheresendproperty come. Andsourceamountwhich is expected output and4000should be"4,000"
– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for"4,000"
– R3tep
yesterday
I mistypedsourceamountthere wassendproperty in old code. But now its fine so +1
– Maheer Ali
yesterday
add a comment |
3
3
3
You can use .map to loop your array and construct all your object.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)answered yesterday
R3tepR3tep
8,13882962
You can use .map to loop your array and construct all your object.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
function config(objectdata, querydata)
return objectdata.map(function(obj)
let send_amount = +querydata.sourceamount.replace(/,/g, "");
let fee = +obj.fee;
let rate = +obj.rate;
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
...querydata
);
result = config(obj, query);
console.log(result)answered yesterday
R3tepR3tep
8,13882962
edited yesterday
answered yesterday
R3tepR3tep
8,13882962
answered yesterday
R3tepR3tep
8,13882962
answered yesterday
R3tepR3tep
8,13882962
8,13882962
3
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From wheresendproperty come. Andsourceamountwhich is expected output and4000should be"4,000"
– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for"4,000"
– R3tep
yesterday
I mistypedsourceamountthere wassendproperty in old code. But now its fine so +1
– Maheer Ali
yesterday
add a comment |
3
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From wheresendproperty come. Andsourceamountwhich is expected output and4000should be"4,000"
– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for"4,000"
– R3tep
yesterday
I mistypedsourceamountthere wassendproperty in old code. But now its fine so +1
– Maheer Ali
yesterday
3
3
doesnot match the expected output..
– Maheer Ali
yesterday
doesnot match the expected output..
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
Still doesnot match expected output.
– Maheer Ali
yesterday
From where
send property come. And sourceamount which is expected output and 4000 should be "4,000"– Maheer Ali
yesterday
From where
send property come. And sourceamount which is expected output and 4000 should be "4,000"– Maheer Ali
yesterday
@MaheerAli Come from the OP example code. And thanks for
"4,000"– R3tep
yesterday
@MaheerAli Come from the OP example code. And thanks for
"4,000"– R3tep
yesterday
I mistyped
sourceamount there was send property in old code. But now its fine so +1– Maheer Ali
yesterday
I mistyped
sourceamount there was send property in old code. But now its fine so +1– Maheer Ali
yesterday
add a comment |
7
You need to map through the obj array and construct your output.
NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
add a comment |
7
You need to map through the obj array and construct your output.
NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
add a comment |
7
7
7
You need to map through the obj array and construct your output.
NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
You need to map through the obj array and construct your output.
NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.
var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));var obj = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
];
var query =
country: "SG",
sourceamount: "4,000"
;
function config(objectdata, querydata)
let result_data = objectdata.map(function(obj)
let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
let fee = parseInt(obj.fee);
let rate = parseInt(obj.rate);
let amount_to_convert = send_amount - fee;
let receive_amount = amount_to_convert * rate;
return
name: obj.name,
fees: fee,
ratevalue: rate,
amountvalue: amount_to_convert,
receive: receive_amount,
country: querydata.country,
sourceamount: send_amount,
);
return result_data;
console.log(config(obj, query));answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
edited yesterday
answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
answered yesterday
Zakaria AcharkiZakaria Acharki
56.4k134471
56.4k134471
add a comment |
add a comment |
3
const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)answered yesterday
Francis LeighFrancis Leigh
901313
add a comment |
3
const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)answered yesterday
Francis LeighFrancis Leigh
901313
add a comment |
3
3
3
const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)answered yesterday
Francis LeighFrancis Leigh
901313
const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)const array = [
name: "insta",
fee: "2",
rate: "2.00"
,
name: "transfer",
fee: "1",
rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000"
function config (data, querydata)
const send_amount = querydata.sourceamount.replace(/,/g,"")
return data.map(( fee, rate, ...rest ) => (
fees: fee,
ratevalue: rate,
amountvalue: +send_amount - +fee,
receive: (+send_amount - +fee) * +rate,
...rest,
...querydata
))
result = config(array, query)
console.log(result)answered yesterday
Francis LeighFrancis Leigh
901313
edited yesterday
answered yesterday
Francis LeighFrancis Leigh
901313
answered yesterday
Francis LeighFrancis Leigh
901313
answered yesterday
Francis LeighFrancis Leigh
901313
901313
add a comment |
add a comment |
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where did you iterate it?
– M.Hemant
yesterday