prime number (diophantine equation) The Next CEO of Stack Overflownumber theory Diophantine equationFind the smallest number with four factorizations in the $mathbbE$-zone.If $n$ is a positive integer, does $n^3-1$ always have a prime factor that's 1 more than a multiple of 3?Exponential diophantine equation involving a prime numberProperty of $n$th Lucas numberApplication of Lagrange's theorem for the number of roots of a polynonial modulo a primeIf p is an odd prime, then any prime that divides $2^p-1$ is congruent to $pm 1$ (mod 8).Proof that if $n$ is the sum of squares and $p^2k+1$ is in its prime factorization, then $pnotequiv 3mod4$Proof of an infinite number of primes of the form 8k+3.Congruences modulo non-Chen primes

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prime number (diophantine equation)



The Next CEO of Stack Overflownumber theory Diophantine equationFind the smallest number with four factorizations in the $mathbbE$-zone.If $n$ is a positive integer, does $n^3-1$ always have a prime factor that's 1 more than a multiple of 3?Exponential diophantine equation involving a prime numberProperty of $n$th Lucas numberApplication of Lagrange's theorem for the number of roots of a polynonial modulo a primeIf p is an odd prime, then any prime that divides $2^p-1$ is congruent to $pm 1$ (mod 8).Proof that if $n$ is the sum of squares and $p^2k+1$ is in its prime factorization, then $pnotequiv 3mod4$Proof of an infinite number of primes of the form 8k+3.Congruences modulo non-Chen primes










0












$begingroup$


143 is semi prime number. 143 to power any odd is congruent to 3 mod 4 and 143 to power any even is congruent to 1 mod 4. Is it correct to write this way?










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$endgroup$











  • $begingroup$
    Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
    $endgroup$
    – lulu
    yesterday






  • 1




    $begingroup$
    Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
    $endgroup$
    – Dietrich Burde
    yesterday















0












$begingroup$


143 is semi prime number. 143 to power any odd is congruent to 3 mod 4 and 143 to power any even is congruent to 1 mod 4. Is it correct to write this way?










share|cite|improve this question







New contributor




Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
    $endgroup$
    – lulu
    yesterday






  • 1




    $begingroup$
    Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
    $endgroup$
    – Dietrich Burde
    yesterday













0












0








0





$begingroup$


143 is semi prime number. 143 to power any odd is congruent to 3 mod 4 and 143 to power any even is congruent to 1 mod 4. Is it correct to write this way?










share|cite|improve this question







New contributor




Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




143 is semi prime number. 143 to power any odd is congruent to 3 mod 4 and 143 to power any even is congruent to 1 mod 4. Is it correct to write this way?







number-theory






share|cite|improve this question







New contributor




Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






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Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked yesterday









Shivangi AsthanaShivangi Asthana

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New contributor





Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Shivangi Asthana is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
    $endgroup$
    – lulu
    yesterday






  • 1




    $begingroup$
    Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
    $endgroup$
    – Dietrich Burde
    yesterday
















  • $begingroup$
    Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
    $endgroup$
    – lulu
    yesterday






  • 1




    $begingroup$
    Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
    $endgroup$
    – Dietrich Burde
    yesterday















$begingroup$
Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
$endgroup$
– lulu
yesterday




$begingroup$
Sure....may be simpler to write $143equiv -1 pmod 4implies 143^nequiv (-1)^npmod 4$.
$endgroup$
– lulu
yesterday




1




1




$begingroup$
Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
$endgroup$
– Dietrich Burde
yesterday




$begingroup$
Why do you have "Diophantine equation" in the title? I only see modulo $4$ calculation.
$endgroup$
– Dietrich Burde
yesterday










0






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