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Compass and straight-edge construction of a line



The Next CEO of Stack OverflowDynamic Geometry Software for Straight-edge and Compass ConstructionsCircles intersecting at A and B3D Dodecahedron model: Construction question.Find the length of a tangent line of a circleMoving Line Segment ProblemGeometry experts! Three equal tangential circles: What is the ratio of the blue line to the red line?What is the minimum radius $r$ of two intersecting circles that are spaced $x$ apart that completely enclose a square of length $w$?Construction of tangent circlesIs the small circle the straight line on the sphere?Find the angle of a tangent line between two circles










-4












$begingroup$


How to construct a line of given length L whose two ends lie on two fixed circles of radii b and c and centers of the circles being at a distance a from each other? Two different cases of construction required.

1. The required line is parallel to the line joining the centers.

2. The required line makes an angle $theta$ with the line joining the centers.



Assuming such a line exists in each case. Am trying to attach this diagram. But the description is complete without it.
https://www.geogebra.or/upload/5c9b620b11fd4










share|cite|improve this question







New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    The page is not accessible.
    $endgroup$
    – Yves Daoust
    yesterday










  • $begingroup$
    Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
    $endgroup$
    – Anirban
    yesterday















-4












$begingroup$


How to construct a line of given length L whose two ends lie on two fixed circles of radii b and c and centers of the circles being at a distance a from each other? Two different cases of construction required.

1. The required line is parallel to the line joining the centers.

2. The required line makes an angle $theta$ with the line joining the centers.



Assuming such a line exists in each case. Am trying to attach this diagram. But the description is complete without it.
https://www.geogebra.or/upload/5c9b620b11fd4










share|cite|improve this question







New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    The page is not accessible.
    $endgroup$
    – Yves Daoust
    yesterday










  • $begingroup$
    Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
    $endgroup$
    – Anirban
    yesterday













-4












-4








-4





$begingroup$


How to construct a line of given length L whose two ends lie on two fixed circles of radii b and c and centers of the circles being at a distance a from each other? Two different cases of construction required.

1. The required line is parallel to the line joining the centers.

2. The required line makes an angle $theta$ with the line joining the centers.



Assuming such a line exists in each case. Am trying to attach this diagram. But the description is complete without it.
https://www.geogebra.or/upload/5c9b620b11fd4










share|cite|improve this question







New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




How to construct a line of given length L whose two ends lie on two fixed circles of radii b and c and centers of the circles being at a distance a from each other? Two different cases of construction required.

1. The required line is parallel to the line joining the centers.

2. The required line makes an angle $theta$ with the line joining the centers.



Assuming such a line exists in each case. Am trying to attach this diagram. But the description is complete without it.
https://www.geogebra.or/upload/5c9b620b11fd4







geometry






share|cite|improve this question







New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









Anirban Anirban

132




132




New contributor




Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Anirban is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    The page is not accessible.
    $endgroup$
    – Yves Daoust
    yesterday










  • $begingroup$
    Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
    $endgroup$
    – Anirban
    yesterday
















  • $begingroup$
    The page is not accessible.
    $endgroup$
    – Yves Daoust
    yesterday










  • $begingroup$
    Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
    $endgroup$
    – Anirban
    yesterday















$begingroup$
The page is not accessible.
$endgroup$
– Yves Daoust
yesterday




$begingroup$
The page is not accessible.
$endgroup$
– Yves Daoust
yesterday












$begingroup$
Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
$endgroup$
– Anirban
yesterday




$begingroup$
Hi Yves, sorry - I am new to this site. Haven't yet learnt how to upload a picture. I bungled it this time. I hope to learn it quickly.
$endgroup$
– Anirban
yesterday










1 Answer
1






active

oldest

votes


















0












$begingroup$

First problem:



  1. Draw a line joining the centers. Suppose it intersects circles at points A and B respectively.


  2. Do a bisection of A and B, let it be point C.


  3. Put points D and E on AB (opposite sides of C), such that DC=L/2 and EC=L/2.


  4. Draw lines orthogonal to AB through points D and E. Suppose that these lines intersect circles at F and G.


  5. Connect F and G - you've got the answer.


All this assuming that solution exists.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
    $endgroup$
    – Anirban
    yesterday












Your Answer





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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0












$begingroup$

First problem:



  1. Draw a line joining the centers. Suppose it intersects circles at points A and B respectively.


  2. Do a bisection of A and B, let it be point C.


  3. Put points D and E on AB (opposite sides of C), such that DC=L/2 and EC=L/2.


  4. Draw lines orthogonal to AB through points D and E. Suppose that these lines intersect circles at F and G.


  5. Connect F and G - you've got the answer.


All this assuming that solution exists.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
    $endgroup$
    – Anirban
    yesterday
















0












$begingroup$

First problem:



  1. Draw a line joining the centers. Suppose it intersects circles at points A and B respectively.


  2. Do a bisection of A and B, let it be point C.


  3. Put points D and E on AB (opposite sides of C), such that DC=L/2 and EC=L/2.


  4. Draw lines orthogonal to AB through points D and E. Suppose that these lines intersect circles at F and G.


  5. Connect F and G - you've got the answer.


All this assuming that solution exists.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
    $endgroup$
    – Anirban
    yesterday














0












0








0





$begingroup$

First problem:



  1. Draw a line joining the centers. Suppose it intersects circles at points A and B respectively.


  2. Do a bisection of A and B, let it be point C.


  3. Put points D and E on AB (opposite sides of C), such that DC=L/2 and EC=L/2.


  4. Draw lines orthogonal to AB through points D and E. Suppose that these lines intersect circles at F and G.


  5. Connect F and G - you've got the answer.


All this assuming that solution exists.






share|cite|improve this answer









$endgroup$



First problem:



  1. Draw a line joining the centers. Suppose it intersects circles at points A and B respectively.


  2. Do a bisection of A and B, let it be point C.


  3. Put points D and E on AB (opposite sides of C), such that DC=L/2 and EC=L/2.


  4. Draw lines orthogonal to AB through points D and E. Suppose that these lines intersect circles at F and G.


  5. Connect F and G - you've got the answer.


All this assuming that solution exists.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered yesterday









AlexAlex

233




233











  • $begingroup$
    Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
    $endgroup$
    – Anirban
    yesterday

















  • $begingroup$
    Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
    $endgroup$
    – Anirban
    yesterday
















$begingroup$
Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
$endgroup$
– Anirban
yesterday





$begingroup$
Hi Alex, looks to me that your solution would work if the circles are of same radius. But if they are of different radius, then FG is not parallel to the line joining the centers and also does not have a length L. Correct me if I am wrong.
$endgroup$
– Anirban
yesterday











Anirban is a new contributor. Be nice, and check out our Code of Conduct.









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Anirban is a new contributor. Be nice, and check out our Code of Conduct.












Anirban is a new contributor. Be nice, and check out our Code of Conduct.











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