Show that for all n ∈ N, L(n) < $2^n$ The Next CEO of Stack OverflowProof that $sqrt5$ is irrationalHow do I show that two sets are equal.Show that if $f:Ato B$ is a bijection then $f^-1$ is a surjectionShow root of unity and orderLet $G$ be a group of order 1210 with a subgroup $H$ of order 121. Show that every element of order 11 is in $H$How to show that the fabius function is nowhere analytic?Period of the decimal expression for the rational number $frac1n$ is at most $n-1$Show that variable lies in specific intervalProof: Well defined multiplication in groupsShow that $gcd(a, 0)$ exists and equals $|a|$ for all $a$ in $mathbb Z$
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Show that for all n ∈ N, L(n)
The Next CEO of Stack OverflowProof that $sqrt5$ is irrationalHow do I show that two sets are equal.Show that if $f:Ato B$ is a bijection then $f^-1$ is a surjectionShow root of unity and orderLet $G$ be a group of order 1210 with a subgroup $H$ of order 121. Show that every element of order 11 is in $H$How to show that the fabius function is nowhere analytic?Period of the decimal expression for the rational number $frac1n$ is at most $n-1$Show that variable lies in specific intervalProof: Well defined multiplication in groupsShow that $gcd(a, 0)$ exists and equals $|a|$ for all $a$ in $mathbb Z$
$begingroup$
Im confused at what this question means and how to answer it.
Also unsure on how to do the following question
Show that L(n) $geq fracn2$· $(fracn2 −1)$ for $n ∈ N$
The $L(n)$ confuses me.
Thanks !
Edit: $L(n)$ (Landau’s function) is defined for every $n ∈ N$ to be the largest order of an element of Sn.
proof-writing
New contributor
$endgroup$
add a comment |
$begingroup$
Im confused at what this question means and how to answer it.
Also unsure on how to do the following question
Show that L(n) $geq fracn2$· $(fracn2 −1)$ for $n ∈ N$
The $L(n)$ confuses me.
Thanks !
Edit: $L(n)$ (Landau’s function) is defined for every $n ∈ N$ to be the largest order of an element of Sn.
proof-writing
New contributor
$endgroup$
2
$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday
add a comment |
$begingroup$
Im confused at what this question means and how to answer it.
Also unsure on how to do the following question
Show that L(n) $geq fracn2$· $(fracn2 −1)$ for $n ∈ N$
The $L(n)$ confuses me.
Thanks !
Edit: $L(n)$ (Landau’s function) is defined for every $n ∈ N$ to be the largest order of an element of Sn.
proof-writing
New contributor
$endgroup$
Im confused at what this question means and how to answer it.
Also unsure on how to do the following question
Show that L(n) $geq fracn2$· $(fracn2 −1)$ for $n ∈ N$
The $L(n)$ confuses me.
Thanks !
Edit: $L(n)$ (Landau’s function) is defined for every $n ∈ N$ to be the largest order of an element of Sn.
proof-writing
proof-writing
New contributor
New contributor
edited yesterday
Anirban Niloy
8411318
8411318
New contributor
asked yesterday
AnonymousAnonymous
11
11
New contributor
New contributor
2
$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday
add a comment |
2
$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday
2
2
$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday
add a comment |
1 Answer
1
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oldest
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$begingroup$
For the second question: If $n=2k$ one can do the product of two disjoint cycles, one of length $k$ and one of length $k-1.$ (fix remaining spot.) Since order is lcm of cycle lengths this has order $k(k-1)=(n/2)(n/2-1).$
If $n=2k+1$ one can do the product of two cycles, one of length k and one of length $k+1.$ This has order $k(k+1)>(n/2)(n/2-1).$
I don't see how to do the first question, but the bound seems relatively high, I'd expect a better bound but don't see how to get it.
$endgroup$
add a comment |
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$begingroup$
For the second question: If $n=2k$ one can do the product of two disjoint cycles, one of length $k$ and one of length $k-1.$ (fix remaining spot.) Since order is lcm of cycle lengths this has order $k(k-1)=(n/2)(n/2-1).$
If $n=2k+1$ one can do the product of two cycles, one of length k and one of length $k+1.$ This has order $k(k+1)>(n/2)(n/2-1).$
I don't see how to do the first question, but the bound seems relatively high, I'd expect a better bound but don't see how to get it.
$endgroup$
add a comment |
$begingroup$
For the second question: If $n=2k$ one can do the product of two disjoint cycles, one of length $k$ and one of length $k-1.$ (fix remaining spot.) Since order is lcm of cycle lengths this has order $k(k-1)=(n/2)(n/2-1).$
If $n=2k+1$ one can do the product of two cycles, one of length k and one of length $k+1.$ This has order $k(k+1)>(n/2)(n/2-1).$
I don't see how to do the first question, but the bound seems relatively high, I'd expect a better bound but don't see how to get it.
$endgroup$
add a comment |
$begingroup$
For the second question: If $n=2k$ one can do the product of two disjoint cycles, one of length $k$ and one of length $k-1.$ (fix remaining spot.) Since order is lcm of cycle lengths this has order $k(k-1)=(n/2)(n/2-1).$
If $n=2k+1$ one can do the product of two cycles, one of length k and one of length $k+1.$ This has order $k(k+1)>(n/2)(n/2-1).$
I don't see how to do the first question, but the bound seems relatively high, I'd expect a better bound but don't see how to get it.
$endgroup$
For the second question: If $n=2k$ one can do the product of two disjoint cycles, one of length $k$ and one of length $k-1.$ (fix remaining spot.) Since order is lcm of cycle lengths this has order $k(k-1)=(n/2)(n/2-1).$
If $n=2k+1$ one can do the product of two cycles, one of length k and one of length $k+1.$ This has order $k(k+1)>(n/2)(n/2-1).$
I don't see how to do the first question, but the bound seems relatively high, I'd expect a better bound but don't see how to get it.
answered yesterday
coffeemathcoffeemath
2,9071415
2,9071415
add a comment |
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$begingroup$
How is $L(n)$ defined?
$endgroup$
– Dietrich Burde
yesterday
$begingroup$
I can't see some characters in your question, they look like empty boxes in my browser: i.stack.imgur.com/362ag.png What are they?
$endgroup$
– CiaPan
yesterday
$begingroup$
should be fine now, I can see the characters in the question clearly on mine, where can you see the boxes ?
$endgroup$
– Anonymous
yesterday
$begingroup$
Boxes still there on my feed.
$endgroup$
– coffeemath
yesterday
$begingroup$
where are the boxes
$endgroup$
– Anonymous
yesterday