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If $f=g/h$ and $g, h$ differentiable, then is $f$ pseudoconvex?



The Next CEO of Stack OverflowCan one define the derivative of a function using tangent cones? Does such a notion already exist?Strictly Convex and Differentiable ImpliesDifferentiable Strictly Convex Function on IntervalExistence of a continuously differentiable function from the projection of a convex setIs the ratio of a convex and linear function pseudoconvex?Convex and continuous function on compact set implies LipschitzContinuously differentiable function injective on convex setIf $f$ is quasiconvex and differentiable then $f$ is convex?Relationship between $langle nabla f(overlinex), x - overlinexrangle > 0$ and the the minimality of $overlinex$.Show that f is both pseudoconvex and pseudoconcave










0












$begingroup$


Let $g:SrightarrowmathbbR$ and $h:SrightarrowmathbbR$, let $SsubsetmathbbR^n$ an open subset such that $Sneq0$.



If $f:Srightarrow mathbbR$ defined by $f(x)=g(x)/h(x)$, and $g$ and $f$ are differentiable, then show that f is pseudoconvex.










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  • $begingroup$
    Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
    $endgroup$
    – mwt
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0












$begingroup$


Let $g:SrightarrowmathbbR$ and $h:SrightarrowmathbbR$, let $SsubsetmathbbR^n$ an open subset such that $Sneq0$.



If $f:Srightarrow mathbbR$ defined by $f(x)=g(x)/h(x)$, and $g$ and $f$ are differentiable, then show that f is pseudoconvex.










share|cite|improve this question









New contributor




Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
    $endgroup$
    – mwt
    yesterday













0












0








0





$begingroup$


Let $g:SrightarrowmathbbR$ and $h:SrightarrowmathbbR$, let $SsubsetmathbbR^n$ an open subset such that $Sneq0$.



If $f:Srightarrow mathbbR$ defined by $f(x)=g(x)/h(x)$, and $g$ and $f$ are differentiable, then show that f is pseudoconvex.










share|cite|improve this question









New contributor




Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Let $g:SrightarrowmathbbR$ and $h:SrightarrowmathbbR$, let $SsubsetmathbbR^n$ an open subset such that $Sneq0$.



If $f:Srightarrow mathbbR$ defined by $f(x)=g(x)/h(x)$, and $g$ and $f$ are differentiable, then show that f is pseudoconvex.







convex-analysis






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Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









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Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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edited yesterday









Floris Claassens

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asked yesterday









Valentina SauValentina Sau

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Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Valentina Sau is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
    $endgroup$
    – mwt
    yesterday
















  • $begingroup$
    Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
    $endgroup$
    – mwt
    yesterday















$begingroup$
Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
$endgroup$
– mwt
yesterday




$begingroup$
Where did you get stuck? Show your attempt. Also, please follow the instructions from here when writing math.
$endgroup$
– mwt
yesterday










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