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Increase and concavity of the function (derivatives)



The Next CEO of Stack OverflowWhich function increase faster?Judging function based on its first and second derivativesGraphing derivatives of non-function equationsFinding inflection points and concavity for given functionVarying definitions for concavity of a functionProving concavity of a functionFind the derivatives given function and derivative valuesCondition for function to increase.Proving the existence of Pi with Derivatives and Sequences OnlyDerivatives of composition function for increase rate










-1












$begingroup$


Given $2$ functions:



$(a) $ $U(x) = -(b-x)^c$



$(b) $ $U(x) = ln(2+ln (x+5))$



For that $x, b$ or $c$ $$U'(x) > 0$$ and $$U''(x)<0?$$



(The answer may be, $f.$ ex. $a>0, b> x$ etc.)



My solution $:$



$(a) U'(x) = c(b-x)^c-1$ and



$U''(x) = -(c-1)c(b-x)^c-2.$










share|cite|improve this question











$endgroup$











  • $begingroup$
    What is you question?
    $endgroup$
    – Maria Mazur
    Mar 27 at 18:38










  • $begingroup$
    I edited my question
    $endgroup$
    – Philip
    Mar 27 at 18:39















-1












$begingroup$


Given $2$ functions:



$(a) $ $U(x) = -(b-x)^c$



$(b) $ $U(x) = ln(2+ln (x+5))$



For that $x, b$ or $c$ $$U'(x) > 0$$ and $$U''(x)<0?$$



(The answer may be, $f.$ ex. $a>0, b> x$ etc.)



My solution $:$



$(a) U'(x) = c(b-x)^c-1$ and



$U''(x) = -(c-1)c(b-x)^c-2.$










share|cite|improve this question











$endgroup$











  • $begingroup$
    What is you question?
    $endgroup$
    – Maria Mazur
    Mar 27 at 18:38










  • $begingroup$
    I edited my question
    $endgroup$
    – Philip
    Mar 27 at 18:39













-1












-1








-1





$begingroup$


Given $2$ functions:



$(a) $ $U(x) = -(b-x)^c$



$(b) $ $U(x) = ln(2+ln (x+5))$



For that $x, b$ or $c$ $$U'(x) > 0$$ and $$U''(x)<0?$$



(The answer may be, $f.$ ex. $a>0, b> x$ etc.)



My solution $:$



$(a) U'(x) = c(b-x)^c-1$ and



$U''(x) = -(c-1)c(b-x)^c-2.$










share|cite|improve this question











$endgroup$




Given $2$ functions:



$(a) $ $U(x) = -(b-x)^c$



$(b) $ $U(x) = ln(2+ln (x+5))$



For that $x, b$ or $c$ $$U'(x) > 0$$ and $$U''(x)<0?$$



(The answer may be, $f.$ ex. $a>0, b> x$ etc.)



My solution $:$



$(a) U'(x) = c(b-x)^c-1$ and



$U''(x) = -(c-1)c(b-x)^c-2.$







functions derivatives






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 27 at 18:42









Dbchatto67

2,419422




2,419422










asked Mar 27 at 18:36









PhilipPhilip

877




877











  • $begingroup$
    What is you question?
    $endgroup$
    – Maria Mazur
    Mar 27 at 18:38










  • $begingroup$
    I edited my question
    $endgroup$
    – Philip
    Mar 27 at 18:39
















  • $begingroup$
    What is you question?
    $endgroup$
    – Maria Mazur
    Mar 27 at 18:38










  • $begingroup$
    I edited my question
    $endgroup$
    – Philip
    Mar 27 at 18:39















$begingroup$
What is you question?
$endgroup$
– Maria Mazur
Mar 27 at 18:38




$begingroup$
What is you question?
$endgroup$
– Maria Mazur
Mar 27 at 18:38












$begingroup$
I edited my question
$endgroup$
– Philip
Mar 27 at 18:39




$begingroup$
I edited my question
$endgroup$
– Philip
Mar 27 at 18:39










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