Need help with the convolution of two complex functions The Next CEO of Stack OverflowDefine uniform B-spline basis functions via continuous convolutionConvolution with sign functionHelp with a question on convolution?How to convolve two stair-case functions?Relation between Dirichlet convolution and Bell series and convolution of functions and the Fourier transform?convolution of non-zero functionsApproximating two-dimensional convolution“Analytic Continuation” of the Convolution Operator?Convolution of two square pulses and the fourier transform of a triangular pulseConvolution with unusual limits

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Need help with the convolution of two complex functions



The Next CEO of Stack OverflowDefine uniform B-spline basis functions via continuous convolutionConvolution with sign functionHelp with a question on convolution?How to convolve two stair-case functions?Relation between Dirichlet convolution and Bell series and convolution of functions and the Fourier transform?convolution of non-zero functionsApproximating two-dimensional convolution“Analytic Continuation” of the Convolution Operator?Convolution of two square pulses and the fourier transform of a triangular pulseConvolution with unusual limits










2












$begingroup$


Could someone start me off with how to find the convolution of these two functions?



convolution



Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.










share|cite|improve this question











$endgroup$











  • $begingroup$
    $$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 15:29










  • $begingroup$
    I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:14










  • $begingroup$
    Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:21










  • $begingroup$
    Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:33










  • $begingroup$
    I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:41















2












$begingroup$


Could someone start me off with how to find the convolution of these two functions?



convolution



Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.










share|cite|improve this question











$endgroup$











  • $begingroup$
    $$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 15:29










  • $begingroup$
    I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:14










  • $begingroup$
    Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:21










  • $begingroup$
    Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:33










  • $begingroup$
    I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:41













2












2








2





$begingroup$


Could someone start me off with how to find the convolution of these two functions?



convolution



Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.










share|cite|improve this question











$endgroup$




Could someone start me off with how to find the convolution of these two functions?



convolution



Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.







complex-analysis fourier-analysis convolution






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 27 at 18:59









Glorfindel

3,41581830




3,41581830










asked Mar 6 '14 at 15:27









user2802349user2802349

2416




2416











  • $begingroup$
    $$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 15:29










  • $begingroup$
    I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:14










  • $begingroup$
    Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:21










  • $begingroup$
    Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:33










  • $begingroup$
    I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:41
















  • $begingroup$
    $$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 15:29










  • $begingroup$
    I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:14










  • $begingroup$
    Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:21










  • $begingroup$
    Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
    $endgroup$
    – user2802349
    Mar 6 '14 at 16:33










  • $begingroup$
    I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
    $endgroup$
    – Daniel Fischer
    Mar 6 '14 at 16:41















$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29




$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29












$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14




$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14












$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21




$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21












$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33




$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33












$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41




$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41










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Population.Datos básicos de Montenegro, historia y evolución política.Serbia y Montenegro. Indicador: Tasa global de fecundidad (por 1000 habitantes).Serbia y Montenegro. Indicador: Tasa bruta de mortalidad (por 1000 habitantes).Population.Falleció el patriarca de la Iglesia Ortodoxa serbia.Atacan en Kosovo autobuses con peregrinos tras la investidura del patriarca serbio IrinejSerbian in Hungary.Tasas de cambio."Kosovo es de todos sus ciudadanos".Report for Serbia.Country groups by income.GROSS DOMESTIC PRODUCT (GDP) OF THE REPUBLIC OF SERBIA 1997–2007.Economic Trends in the Republic of Serbia 2006.National Accounts Statitics.Саопштења за јавност.GDP per inhabitant varied by one to six across the EU27 Member States.Un pacto de estabilidad para Serbia.Unemployment rate rises in Serbia.Serbia, Belarus agree free trade to woo investors.Serbia, Turkey call investors to Serbia.Success Stories.U.S. Private Investment in Serbia and Montenegro.Positive trend.Banks in Serbia.La Cámara de Comercio acompaña a empresas madrileñas a Serbia y Croacia.Serbia Industries.Energy and mining.Agriculture.Late crops, fruit and grapes output, 2008.Rebranding Serbia: A Hobby Shortly to Become a Full-Time Job.Final data on livestock statistics, 2008.Serbian cell-phone users.U Srbiji sve više računara.Телекомуникације.U Srbiji 27 odsto gradjana koristi Internet.Serbia and Montenegro.Тренд гледаности програма РТС-а у 2008. и 2009.години.Serbian railways.General Terms.El mercado del transporte aéreo en Serbia.Statistics.Vehículos de motor registrados.Planes ambiciosos para el transporte fluvial.Turismo.Turistički promet u Republici Srbiji u periodu januar-novembar 2007. godine.Your Guide to Culture.Novi Sad - city of culture.Nis - european crossroads.Serbia. Properties inscribed on the World Heritage List .Stari Ras and Sopoćani.Studenica Monastery.Medieval Monuments in Kosovo.Gamzigrad-Romuliana, Palace of Galerius.Skiing and snowboarding in Kopaonik.Tara.New7Wonders of Nature Finalists.Pilgrimage of Saint Sava.Exit Festival: Best european festival.Banje u Srbiji.«The Encyclopedia of world history»Culture.Centenario del arte serbio.«Djordje Andrejevic Kun: el único pintor de los brigadistas yugoslavos de la guerra civil española»About the museum.The collections.Miroslav Gospel – Manuscript from 1180.Historicity in the Serbo-Croatian Heroic Epic.Culture and Sport.Conversación con el rector del Seminario San Sava.'Reina Margot' funde drama, historia y gesto con música de Goran Bregovic.Serbia gana Eurovisión y España decepciona de nuevo con un vigésimo puesto.Home.Story.Emir Kusturica.Tercer oro para Paskaljevic.Nikola Tesla Year.Home.Tesla, un genio tomado por loco.Aniversario de la muerte de Nikola Tesla.El Museo Nikola Tesla en Belgrado.El inventor del mundo actual.República de Serbia.University of Belgrade official statistics.University of Novi Sad.University of Kragujevac.University of Nis.Comida. Cocina serbia.Cooking.Montenegro se convertirá en el miembro 204 del movimiento olímpico.España, campeona de Europa de baloncesto.El Partizan de Belgrado se corona campeón por octava vez consecutiva.Serbia se clasifica para el Mundial de 2010 de Sudáfrica.Serbia Name Squad For Northern Ireland And South Korea Tests.Fútbol.- El Partizán de Belgrado se proclama campeón de la Liga serbia.Clasificacion final Mundial de balonmano Croacia 2009.Serbia vence a España y se consagra campeón mundial de waterpolo.Novak Djokovic no convence pero gana en Australia.Gana Ana Ivanovic el Roland Garros.Serena Williams gana el US Open por tercera vez.Biography.Bradt Travel Guide SerbiaThe Encyclopedia of World War IGobierno de SerbiaPortal del Gobierno de SerbiaPresidencia de SerbiaAsamblea Nacional SerbiaMinisterio de Asuntos exteriores de SerbiaBanco Nacional de SerbiaAgencia Serbia para la Promoción de la Inversión y la ExportaciónOficina de Estadísticas de SerbiaCIA. Factbook 2008Organización nacional de turismo de SerbiaDiscover SerbiaConoce SerbiaNoticias de SerbiaSerbiaWorldCat1512028760000 0000 9526 67094054598-2n8519591900570825ge1309191004530741010url17413117006669D055771Serbia