Need help with the convolution of two complex functions The Next CEO of Stack OverflowDefine uniform B-spline basis functions via continuous convolutionConvolution with sign functionHelp with a question on convolution?How to convolve two stair-case functions?Relation between Dirichlet convolution and Bell series and convolution of functions and the Fourier transform?convolution of non-zero functionsApproximating two-dimensional convolution“Analytic Continuation” of the Convolution Operator?Convolution of two square pulses and the fourier transform of a triangular pulseConvolution with unusual limits
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Need help with the convolution of two complex functions
The Next CEO of Stack OverflowDefine uniform B-spline basis functions via continuous convolutionConvolution with sign functionHelp with a question on convolution?How to convolve two stair-case functions?Relation between Dirichlet convolution and Bell series and convolution of functions and the Fourier transform?convolution of non-zero functionsApproximating two-dimensional convolution“Analytic Continuation” of the Convolution Operator?Convolution of two square pulses and the fourier transform of a triangular pulseConvolution with unusual limits
$begingroup$
Could someone start me off with how to find the convolution of these two functions?
Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.
complex-analysis fourier-analysis convolution
$endgroup$
|
show 1 more comment
$begingroup$
Could someone start me off with how to find the convolution of these two functions?
Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.
complex-analysis fourier-analysis convolution
$endgroup$
$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41
|
show 1 more comment
$begingroup$
Could someone start me off with how to find the convolution of these two functions?
Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.
complex-analysis fourier-analysis convolution
$endgroup$
Could someone start me off with how to find the convolution of these two functions?
Using the normal equation for convolution seems impossible as a common overlap interval is required for integration. The Fourier convolution theorems also seems inapplicable here.
complex-analysis fourier-analysis convolution
complex-analysis fourier-analysis convolution
edited Mar 27 at 18:59
Glorfindel
3,41581830
3,41581830
asked Mar 6 '14 at 15:27
user2802349user2802349
2416
2416
$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41
|
show 1 more comment
$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41
$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41
|
show 1 more comment
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$begingroup$
$$(f_1ast f_2)(x) = int_mathbbR f_1(x-y)f_2(y),dy$$ is well-defined for these two functions. They both belong to $L^2(mathbbR)$.
$endgroup$
– Daniel Fischer
Mar 6 '14 at 15:29
$begingroup$
I'm still a first year undergrad student, so the whole L^2 functions are new to me. Could you explain the process a little further for me?
$endgroup$
– user2802349
Mar 6 '14 at 16:14
$begingroup$
Sorry, I thought that you knew a little bit of that since you spoke of the Fourier convolution theorems, at least one of which has its natural home in $L^2$. Anyway, for any fixed $x$, the function $h_x(y) = f_1(x-y)f_2(y)$ is defined on all of $mathbbR$ and integrable. Thus the function $xmapsto int_mathbbR h_x(y),dy$ is well-defined (and continuous, but that needs some argument to prove).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:21
$begingroup$
Oh I meant the theorems that go with the Fourier Transform and stuff. These: mathworld.wolfram.com/ConvolutionTheorem.html This question is from an assignment from my course. It's way over what we actually learned in class. I've been piecing together my assignment by asking a lot of questions on this place. I'm supposed to find the convolution of these and actually obtain a result. The variable of integration ('y' in your equation) of the convolution equation is the overlap of the two functions, right? If they both have infinite limits, what would that variable be for this instance?
$endgroup$
– user2802349
Mar 6 '14 at 16:33
$begingroup$
I'm not sure what you mean with "overlap". Both functions are defined on all of $mathbbR$ (and square-integrable), so the convolution is given by the formula above. Computing it may be quite hard (depends on what you can use; if you know the residue theorem, it's easy, but I don't think first year undergraduates have that yet).
$endgroup$
– Daniel Fischer
Mar 6 '14 at 16:41