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For $p$ a prime larger than $2k+2$, is it possible that $p^2$ divides $B_2k$?



The Next CEO of Stack OverflowWhich is the greatest possible natural number that divides $(p+3)(p-7)$, where $p$ is a prime number greater than $3$?On the numerators of Bernoulli numbersPrime larger than a twin primeProve that for any natural number $n$ there exists a prime number $p$ greater than $n$Euclid's proof for the existence of infinitely many primeBernoulli number $B_fracp-12$What is the Largest Possible Prime Number? sic The largest possible prime set?Infiniteness of irregular primes $equiv3pmod4$Existence of $m in M subsetneq mathbbN$ such that $p nmid a+bm$, $p$ primeProve that every prime number divides some number in the sequence $ a_n = 2^n+3^n+6^n-1 $










2












$begingroup$


One characterization of the irregular primes is as follows:



For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.



Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?



References that provide an answer, or just deal with the question are welcome.










share|cite|improve this question











$endgroup$
















    2












    $begingroup$


    One characterization of the irregular primes is as follows:



    For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.



    Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?



    References that provide an answer, or just deal with the question are welcome.










    share|cite|improve this question











    $endgroup$














      2












      2








      2


      1



      $begingroup$


      One characterization of the irregular primes is as follows:



      For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.



      Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?



      References that provide an answer, or just deal with the question are welcome.










      share|cite|improve this question











      $endgroup$




      One characterization of the irregular primes is as follows:



      For an irregular prime $p$, there exists some natural number $kle fracp-32$ such that $p$ divides [the numerator of] $B_2k$ where $B_2k$ is a Bernoulli number.



      Question: Is there some prime $p$ for which there exists some natural number $kle fracp-32$, such that $p^2$ divides $B_2k$?



      References that provide an answer, or just deal with the question are welcome.







      number-theory elementary-number-theory reference-request prime-numbers bernoulli-numbers






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 27 at 21:21









      J. W. Tanner

      4,0611320




      4,0611320










      asked Mar 27 at 19:51









      René GyRené Gy

      1,168713




      1,168713




















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