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Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$



The Next CEO of Stack OverflowProve that $EX=E(E(X|Y))$Given $X$ and $Y$ are independent N(0,1) random variables and $Z = sqrtX^2+Y^2$ from the marginal pdf of $Z$Evaluate $mathbbE[e^e^x] =int_mathbbRe^e^xf(x)dx$, where $f(x)$ is Gaussian kernel.Given Max has probability p to win each game, compute the expected number of runs* after n gamesProbability Question. Prove that P(A|B) = P(A) given that P(A|B)= 0.52 and P(B)= 0.43Compute factorized and marginalized distribution of the graphFind $limsup_ntoinfty Y_n$ given the value of $mathbbE(limsup_ntoinfty Y_n)$Variance of random sum of random i.i.d. variables - spot the mistake?Conditional expectation with a third random variableConditional expectation of minimum of exponential random variablesConditional Expectation of a Sum of Random Variables and a Random Integer










3












$begingroup$


Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.



I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!










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  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
    $endgroup$
    – Fareed AF
    Mar 27 at 20:26















3












$begingroup$


Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.



I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!










share|cite|improve this question









New contributor




Lnicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
    $endgroup$
    – Fareed AF
    Mar 27 at 20:26













3












3








3


1



$begingroup$


Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.



I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!










share|cite|improve this question









New contributor




Lnicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.



I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!







probability probability-theory conditional-expectation conditional-probability expected-value






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Lnicks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited Mar 27 at 20:31









callculus

18.6k31428




18.6k31428






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asked Mar 27 at 20:23









LnicksLnicks

161




161




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  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
    $endgroup$
    – Fareed AF
    Mar 27 at 20:26
















  • $begingroup$
    Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
    $endgroup$
    – Fareed AF
    Mar 27 at 20:26















$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
$endgroup$
– Fareed AF
Mar 27 at 20:26




$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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Mar 27 at 20:26










2 Answers
2






active

oldest

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6












$begingroup$

$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$



$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$






share|cite|improve this answer











$endgroup$








  • 2




    $begingroup$
    For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
    $endgroup$
    – Chase Ryan Taylor
    Mar 27 at 21:13



















2












$begingroup$

$E[X] = 2$.



Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.






share|cite|improve this answer









$endgroup$













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    2 Answers
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    2 Answers
    2






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    6












    $begingroup$

    $$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$



    $$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$






    share|cite|improve this answer











    $endgroup$








    • 2




      $begingroup$
      For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
      $endgroup$
      – Chase Ryan Taylor
      Mar 27 at 21:13
















    6












    $begingroup$

    $$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$



    $$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$






    share|cite|improve this answer











    $endgroup$








    • 2




      $begingroup$
      For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
      $endgroup$
      – Chase Ryan Taylor
      Mar 27 at 21:13














    6












    6








    6





    $begingroup$

    $$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$



    $$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$






    share|cite|improve this answer











    $endgroup$



    $$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$



    $$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited Mar 27 at 21:08









    Chase Ryan Taylor

    4,46521531




    4,46521531










    answered Mar 27 at 20:31









    Fareed AFFareed AF

    63212




    63212







    • 2




      $begingroup$
      For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
      $endgroup$
      – Chase Ryan Taylor
      Mar 27 at 21:13













    • 2




      $begingroup$
      For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
      $endgroup$
      – Chase Ryan Taylor
      Mar 27 at 21:13








    2




    2




    $begingroup$
    For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
    $endgroup$
    – Chase Ryan Taylor
    Mar 27 at 21:13





    $begingroup$
    For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
    $endgroup$
    – Chase Ryan Taylor
    Mar 27 at 21:13












    2












    $begingroup$

    $E[X] = 2$.



    Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.






    share|cite|improve this answer









    $endgroup$

















      2












      $begingroup$

      $E[X] = 2$.



      Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.






      share|cite|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        $E[X] = 2$.



        Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.






        share|cite|improve this answer









        $endgroup$



        $E[X] = 2$.



        Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 27 at 20:34









        dnqxtdnqxt

        3994




        3994




















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