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Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$
The Next CEO of Stack OverflowProve that $EX=E(E(X|Y))$Given $X$ and $Y$ are independent N(0,1) random variables and $Z = sqrtX^2+Y^2$ from the marginal pdf of $Z$Evaluate $mathbbE[e^e^x] =int_mathbbRe^e^xf(x)dx$, where $f(x)$ is Gaussian kernel.Given Max has probability p to win each game, compute the expected number of runs* after n gamesProbability Question. Prove that P(A|B) = P(A) given that P(A|B)= 0.52 and P(B)= 0.43Compute factorized and marginalized distribution of the graphFind $limsup_ntoinfty Y_n$ given the value of $mathbbE(limsup_ntoinfty Y_n)$Variance of random sum of random i.i.d. variables - spot the mistake?Conditional expectation with a third random variableConditional expectation of minimum of exponential random variablesConditional Expectation of a Sum of Random Variables and a Random Integer
$begingroup$
Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.
I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!
probability probability-theory conditional-expectation conditional-probability expected-value
New contributor
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add a comment |
$begingroup$
Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.
I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!
probability probability-theory conditional-expectation conditional-probability expected-value
New contributor
$endgroup$
$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
Mar 27 at 20:26
add a comment |
$begingroup$
Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.
I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!
probability probability-theory conditional-expectation conditional-probability expected-value
New contributor
$endgroup$
Given $mathbb E(5X+2)=12$ and $mathbb E(X|Y)=Y^3$ compute $mathbb E(Y^3)$.
I've been trying this a million different ways and can't seem to reach a final answer, I would love any suggestions!
probability probability-theory conditional-expectation conditional-probability expected-value
probability probability-theory conditional-expectation conditional-probability expected-value
New contributor
New contributor
edited Mar 27 at 20:31
callculus
18.6k31428
18.6k31428
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asked Mar 27 at 20:23
LnicksLnicks
161
161
New contributor
New contributor
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Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
Mar 27 at 20:26
add a comment |
$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
Mar 27 at 20:26
$begingroup$
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
Mar 27 at 20:26
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Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
Mar 27 at 20:26
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2 Answers
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$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$
$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$
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2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
add a comment |
$begingroup$
$E[X] = 2$.
Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.
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2 Answers
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2 Answers
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$begingroup$
$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$
$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$
$endgroup$
2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
add a comment |
$begingroup$
$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$
$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$
$endgroup$
2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
add a comment |
$begingroup$
$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$
$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$
$endgroup$
$$mathbb E(5X+2)=5,mathbb E(X)+2=12 implies mathbb E(X)=2$$
$$mathbb E(Y^3)=mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)=2$$
edited Mar 27 at 21:08
Chase Ryan Taylor
4,46521531
4,46521531
answered Mar 27 at 20:31
Fareed AFFareed AF
63212
63212
2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
add a comment |
2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
2
2
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
$begingroup$
For any readers: Reference this answer to see that $mathbb Ebigl(mathbb E(X|Y)bigr)=mathbb E(X)$.
$endgroup$
– Chase Ryan Taylor
Mar 27 at 21:13
add a comment |
$begingroup$
$E[X] = 2$.
Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.
$endgroup$
add a comment |
$begingroup$
$E[X] = 2$.
Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.
$endgroup$
add a comment |
$begingroup$
$E[X] = 2$.
Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.
$endgroup$
$E[X] = 2$.
Since $E[ X|Y] = Y^3$, then $E[Y^3] = E[ E[X|Y]] = E[X] = 2$.
answered Mar 27 at 20:34
dnqxtdnqxt
3994
3994
add a comment |
add a comment |
Lnicks is a new contributor. Be nice, and check out our Code of Conduct.
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Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial, and equation editing how-to
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– Fareed AF
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