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Python is coming up with this error for my code and don't understand why. Any help would be great. [on hold]

0

$begingroup$

import math

import numpy as np

import matplotlib.pyplot as plt

def f(theta):

l1=3
l2=*math.sprt(2)
l3=3
p1=5
p2=5
p3=3
gamma=(math.pi)/4
x1=5
x2=0
y2=6
a2 =(13*(math.cos(theta)))-x1
b2=12*(math.sin(theta))
a3=(13*(math.cos(theta+gamma)))-x2
b3=12*(math.sin(theta+gamma))-y2
n1=b3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))-(b2*(np.square(p3)-np.square(p1)-np.square(a2)-np.square(b3)))
n2=-a3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))+(a2*(np.square(p3)-np.square(p1)-np.square(a3)-np.square(b3)))
d=2*((a2*b3)-(b2*a3))
out=np.square(n1)+np.square(n2)-np.square(p1)*np.square(d)
return out

plt.plot(f(2),f(3))

The error is

File "", line 9
p2=5

^
SyntaxError: can't use starred expression here

python

share|cite|improve this question

asked Mar 27 at 19:01

Kris LetangKris Letang

1

$endgroup$

put on hold as off-topic by Javi, YiFan, Cesareo, Eevee Trainer, Parcly Taxel 2 days ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is not about mathematics, within the scope defined in the help center." – YiFan, Cesareo, Eevee Trainer, Parcly Taxel

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

0

$begingroup$

import math

import numpy as np

import matplotlib.pyplot as plt

def f(theta):

l1=3
l2=*math.sprt(2)
l3=3
p1=5
p2=5
p3=3
gamma=(math.pi)/4
x1=5
x2=0
y2=6
a2 =(13*(math.cos(theta)))-x1
b2=12*(math.sin(theta))
a3=(13*(math.cos(theta+gamma)))-x2
b3=12*(math.sin(theta+gamma))-y2
n1=b3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))-(b2*(np.square(p3)-np.square(p1)-np.square(a2)-np.square(b3)))
n2=-a3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))+(a2*(np.square(p3)-np.square(p1)-np.square(a3)-np.square(b3)))
d=2*((a2*b3)-(b2*a3))
out=np.square(n1)+np.square(n2)-np.square(p1)*np.square(d)
return out

plt.plot(f(2),f(3))

The error is

File "", line 9
p2=5

^
SyntaxError: can't use starred expression here

python

share|cite|improve this question

asked Mar 27 at 19:01

Kris LetangKris Letang

1

$endgroup$

put on hold as off-topic by Javi, YiFan, Cesareo, Eevee Trainer, Parcly Taxel 2 days ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is not about mathematics, within the scope defined in the help center." – YiFan, Cesareo, Eevee Trainer, Parcly Taxel

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

$begingroup$

import math

import numpy as np

import matplotlib.pyplot as plt

def f(theta):

l1=3
l2=*math.sprt(2)
l3=3
p1=5
p2=5
p3=3
gamma=(math.pi)/4
x1=5
x2=0
y2=6
a2 =(13*(math.cos(theta)))-x1
b2=12*(math.sin(theta))
a3=(13*(math.cos(theta+gamma)))-x2
b3=12*(math.sin(theta+gamma))-y2
n1=b3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))-(b2*(np.square(p3)-np.square(p1)-np.square(a2)-np.square(b3)))
n2=-a3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))+(a2*(np.square(p3)-np.square(p1)-np.square(a3)-np.square(b3)))
d=2*((a2*b3)-(b2*a3))
out=np.square(n1)+np.square(n2)-np.square(p1)*np.square(d)
return out

plt.plot(f(2),f(3))

The error is

File "", line 9
p2=5

^
SyntaxError: can't use starred expression here

python

share|cite|improve this question

asked Mar 27 at 19:01

Kris LetangKris Letang

1

$endgroup$

l1=3
l2=*math.sprt(2)
l3=3
p1=5
p2=5
p3=3
gamma=(math.pi)/4
x1=5
x2=0
y2=6
a2 =(13*(math.cos(theta)))-x1
b2=12*(math.sin(theta))
a3=(13*(math.cos(theta+gamma)))-x2
b3=12*(math.sin(theta+gamma))-y2
n1=b3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))-(b2*(np.square(p3)-np.square(p1)-np.square(a2)-np.square(b3)))
n2=-a3*((np.square(p2))-np.square(p1)-np.square(a2)-np.square(b2))+(a2*(np.square(p3)-np.square(p1)-np.square(a3)-np.square(b3)))
d=2*((a2*b3)-(b2*a3))
out=np.square(n1)+np.square(n2)-np.square(p1)*np.square(d)
return out

share|cite|improve this question

asked Mar 27 at 19:01

Kris LetangKris Letang

1

share|cite|improve this question

asked Mar 27 at 19:01

Kris LetangKris Letang

1

asked Mar 27 at 19:01

Kris LetangKris Letang

1

asked Mar 27 at 19:01

Kris LetangKris Letang

1

2 Answers
2

active

oldest

votes

0

$begingroup$

I guess you could change l2 =*math.sprt(2) to l2 *= math.sqrt(2) and see what happens.

share|cite|improve this answer

edited Mar 27 at 19:11

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  And presumably sprt should be sqrt.
  $endgroup$
  – Théophile
  Mar 27 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yeah of course.
  $endgroup$
  – model_checker
  Mar 27 at 19:11
  

  
  
  
  

add a comment | 

0

$begingroup$

The error clearly isn't happening where it claimed - so we look earlier. That line

l2=*math.sprt(2)

is the post obvious source of trouble. For one thing, it's a typo; "sprt" is not a function in the "math" library.

For another, " =* " is not something the grammar recognizes. " *= " would make sense multiplying a preexisting value by whatever comes after the symbol, but you haven't defined l2 yet, so more likely that's just supposed to be

l2 = math.sqrt(2)

share|cite|improve this answer

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

$endgroup$

add a comment | 

0

$begingroup$

I guess you could change l2 =*math.sprt(2) to l2 *= math.sqrt(2) and see what happens.

share|cite|improve this answer

edited Mar 27 at 19:11

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  And presumably sprt should be sqrt.
  $endgroup$
  – Théophile
  Mar 27 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yeah of course.
  $endgroup$
  – model_checker
  Mar 27 at 19:11
  

  
  
  
  

add a comment | 

0

$begingroup$

I guess you could change l2 =*math.sprt(2) to l2 *= math.sqrt(2) and see what happens.

share|cite|improve this answer

edited Mar 27 at 19:11

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  And presumably sprt should be sqrt.
  $endgroup$
  – Théophile
  Mar 27 at 19:10
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Yeah of course.
  $endgroup$
  – model_checker
  Mar 27 at 19:11
  

  
  
  
  

add a comment | 

$begingroup$

I guess you could change l2 =*math.sprt(2) to l2 *= math.sqrt(2) and see what happens.

share|cite|improve this answer

edited Mar 27 at 19:11

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

$endgroup$

share|cite|improve this answer

edited Mar 27 at 19:11

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

answered Mar 27 at 19:09

model_checkermodel_checker

4,41621931

0

$begingroup$

The error clearly isn't happening where it claimed - so we look earlier. That line

l2=*math.sprt(2)

is the post obvious source of trouble. For one thing, it's a typo; "sprt" is not a function in the "math" library.

For another, " =* " is not something the grammar recognizes. " *= " would make sense multiplying a preexisting value by whatever comes after the symbol, but you haven't defined l2 yet, so more likely that's just supposed to be

l2 = math.sqrt(2)

share|cite|improve this answer

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

$endgroup$

add a comment | 

0

$begingroup$

The error clearly isn't happening where it claimed - so we look earlier. That line

l2=*math.sprt(2)

is the post obvious source of trouble. For one thing, it's a typo; "sprt" is not a function in the "math" library.

For another, " =* " is not something the grammar recognizes. " *= " would make sense multiplying a preexisting value by whatever comes after the symbol, but you haven't defined l2 yet, so more likely that's just supposed to be

l2 = math.sqrt(2)

share|cite|improve this answer

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

$endgroup$

add a comment | 

$begingroup$

The error clearly isn't happening where it claimed - so we look earlier. That line

l2=*math.sprt(2)

is the post obvious source of trouble. For one thing, it's a typo; "sprt" is not a function in the "math" library.

For another, " =* " is not something the grammar recognizes. " *= " would make sense multiplying a preexisting value by whatever comes after the symbol, but you haven't defined l2 yet, so more likely that's just supposed to be

l2 = math.sqrt(2)

share|cite|improve this answer

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

$endgroup$

l2=*math.sprt(2)

l2 = math.sqrt(2)

share|cite|improve this answer

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633

answered Mar 27 at 19:16

jmerryjmerry

16.9k11633