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Confused with finding Y when using the 3rd step of FFT
The Next CEO of Stack OverflowRewriting matrix equation into terms of $t$How can you expand the adjoint of a matrix into a polynomial with matrix coefficients?What is the Permutation Matrix in FFT DFT Factorization?Doesn't the recursive Fast Fourier Transform violate f(-x) =/= f(x) for odd functions?Extracting vector containing the elements of the main diagonal of a matrixFinding a solution when the determinant is zeroSolving differential equation using FFT: dealing with zero frequenciesdifferent result of discrete fourier transformHow to solve matrix differential equation $dot P (t) = P(t) S(t) P(t) - Q$?Row reduction as matrix multiplication help?
$begingroup$
As far as I know, the 3 steps of FFT while solving $F_nc = y$ :
Split c into c', c'' such that c' contains elements with even indexes from c and c'' contains the odd ones.
Now we have $F_mc' = y'$ and $F_mc' = y''$ where $m = n/2$
To combine $y',y''$ we use the formula
but while I was solving a problem, the solution was just:
$beginbmatrix
y' \
y''
endbmatrix = y$
matrix-equations fourier-transform fast-fourier-transform
$endgroup$
add a comment |
$begingroup$
As far as I know, the 3 steps of FFT while solving $F_nc = y$ :
Split c into c', c'' such that c' contains elements with even indexes from c and c'' contains the odd ones.
Now we have $F_mc' = y'$ and $F_mc' = y''$ where $m = n/2$
To combine $y',y''$ we use the formula
but while I was solving a problem, the solution was just:
$beginbmatrix
y' \
y''
endbmatrix = y$
matrix-equations fourier-transform fast-fourier-transform
$endgroup$
add a comment |
$begingroup$
As far as I know, the 3 steps of FFT while solving $F_nc = y$ :
Split c into c', c'' such that c' contains elements with even indexes from c and c'' contains the odd ones.
Now we have $F_mc' = y'$ and $F_mc' = y''$ where $m = n/2$
To combine $y',y''$ we use the formula
but while I was solving a problem, the solution was just:
$beginbmatrix
y' \
y''
endbmatrix = y$
matrix-equations fourier-transform fast-fourier-transform
$endgroup$
As far as I know, the 3 steps of FFT while solving $F_nc = y$ :
Split c into c', c'' such that c' contains elements with even indexes from c and c'' contains the odd ones.
Now we have $F_mc' = y'$ and $F_mc' = y''$ where $m = n/2$
To combine $y',y''$ we use the formula
but while I was solving a problem, the solution was just:
$beginbmatrix
y' \
y''
endbmatrix = y$
matrix-equations fourier-transform fast-fourier-transform
matrix-equations fourier-transform fast-fourier-transform
asked Mar 27 at 19:21
Mohamad Ziad AlkabakibiMohamad Ziad Alkabakibi
11
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