I need to find a point “D” that lies on the line AB such that the angle between DA and DC is 90 degrees. Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Should/do parallel lines curve when rendered with perspective?What is the perspective projection of a 3d point relative to a quarternion encoded camera?How to calculate the quaternion from/and axis angle having parent and target position (camera and its target)?How to rotate a 3D object, using only local x-, y-, and z-rotations, so that it always faces a camera at the originCoordinate Transforms for Google Street View like UIMovement of a 3D point along its direction vectorOrthographic distance to projection distanceCalculating angle to aim at target results in over/under aim depending on whether target is below/aboveRotating cube with cameraDragging an object on a plane with respect to the camera
Most bit efficient text communication method?
How does the math work when buying airline miles?
What does it mean that physics no longer uses mechanical models to describe phenomena?
Are sorcerers unable to use the Careful Spell metamagic option on themselves?
What is the meaning of 'breadth' in breadth first search?
What are the discoveries that have been possible with the rejection of positivism?
How could we fake a moon landing now?
How to report t statistic from R
What does this say in Elvish?
Central Vacuuming: Is it worth it, and how does it compare to normal vacuuming?
What to do with repeated rejections for phd position
Getting prompted for verification code but where do I put it in?
What makes a man succeed?
Why are my pictures showing a dark band on one edge?
How to save space when writing equations with cases?
Amount of permutations on an NxNxN Rubik's Cube
What would you call this weird metallic apparatus that allows you to lift people?
How does Belgium enforce obligatory attendance in elections?
What is best way to wire a ceiling receptacle in this situation?
What does Turing mean by this statement?
Karn the great creator - 'card from outside the game' in sealed
Would it be easier to apply for a UK visa if there is a host family to sponsor for you in going there?
Why are vacuum tubes still used in amateur radios?
Girl Hackers - Logic Puzzle
I need to find a point “D” that lies on the line AB such that the angle between DA and DC is 90 degrees.
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Should/do parallel lines curve when rendered with perspective?What is the perspective projection of a 3d point relative to a quarternion encoded camera?How to calculate the quaternion from/and axis angle having parent and target position (camera and its target)?How to rotate a 3D object, using only local x-, y-, and z-rotations, so that it always faces a camera at the originCoordinate Transforms for Google Street View like UIMovement of a 3D point along its direction vectorOrthographic distance to projection distanceCalculating angle to aim at target results in over/under aim depending on whether target is below/aboveRotating cube with cameraDragging an object on a plane with respect to the camera
$begingroup$
I have 2 lines in 3d coordinate system AB and AC. I need to find a point "D" that lies on the line AB such that the angle between DA and DC is 90 degrees.
Next might be irrelevant information but:
A is position of a perspective camera.
B is the position where the camera is looking.
C is the position of an edge.
I'm making a 3d modeling a tool and I have to grab an edge and drag it in 3d space. To change the depth I'm going to use the mouse wheel which is nothing you just have to bring it closer or further to the camera. But I'm not understanding how to the horizontal and vertical movements according to the camera.
What is bothering me is that if the 3d point C according to the 2d view plane of the camera is (20,89) if I drag the mouse from (20,89) to say (30,50) what would the new 3d position be. My idea is to consider a flat screen in 3d on which C lies and the screen is parallel to the camera.
linear-algebra 3d
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
$endgroup$
|
show 2 more comments
$begingroup$
I have 2 lines in 3d coordinate system AB and AC. I need to find a point "D" that lies on the line AB such that the angle between DA and DC is 90 degrees.
Next might be irrelevant information but:
A is position of a perspective camera.
B is the position where the camera is looking.
C is the position of an edge.
I'm making a 3d modeling a tool and I have to grab an edge and drag it in 3d space. To change the depth I'm going to use the mouse wheel which is nothing you just have to bring it closer or further to the camera. But I'm not understanding how to the horizontal and vertical movements according to the camera.
What is bothering me is that if the 3d point C according to the 2d view plane of the camera is (20,89) if I drag the mouse from (20,89) to say (30,50) what would the new 3d position be. My idea is to consider a flat screen in 3d on which C lies and the screen is parallel to the camera.
linear-algebra 3d
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
$endgroup$
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09
|
show 2 more comments
$begingroup$
I have 2 lines in 3d coordinate system AB and AC. I need to find a point "D" that lies on the line AB such that the angle between DA and DC is 90 degrees.
Next might be irrelevant information but:
A is position of a perspective camera.
B is the position where the camera is looking.
C is the position of an edge.
I'm making a 3d modeling a tool and I have to grab an edge and drag it in 3d space. To change the depth I'm going to use the mouse wheel which is nothing you just have to bring it closer or further to the camera. But I'm not understanding how to the horizontal and vertical movements according to the camera.
What is bothering me is that if the 3d point C according to the 2d view plane of the camera is (20,89) if I drag the mouse from (20,89) to say (30,50) what would the new 3d position be. My idea is to consider a flat screen in 3d on which C lies and the screen is parallel to the camera.
linear-algebra 3d
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
$endgroup$
I have 2 lines in 3d coordinate system AB and AC. I need to find a point "D" that lies on the line AB such that the angle between DA and DC is 90 degrees.
Next might be irrelevant information but:
A is position of a perspective camera.
B is the position where the camera is looking.
C is the position of an edge.
I'm making a 3d modeling a tool and I have to grab an edge and drag it in 3d space. To change the depth I'm going to use the mouse wheel which is nothing you just have to bring it closer or further to the camera. But I'm not understanding how to the horizontal and vertical movements according to the camera.
What is bothering me is that if the 3d point C according to the 2d view plane of the camera is (20,89) if I drag the mouse from (20,89) to say (30,50) what would the new 3d position be. My idea is to consider a flat screen in 3d on which C lies and the screen is parallel to the camera.
linear-algebra 3d
linear-algebra 3d
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
edited Apr 2 at 15:50
John Wayland Bales
15.3k21238
15.3k21238
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
asked Apr 2 at 2:03
AgentX4000AgentX4000
1
1
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09
|
show 2 more comments
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09
|
show 2 more comments
0
active
oldest
votes
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3171372%2fi-need-to-find-a-point-d-that-lies-on-the-line-ab-such-that-the-angle-between%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3171372%2fi-need-to-find-a-point-d-that-lies-on-the-line-ab-such-that-the-angle-between%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Find the midpoint of $AC$, call it $M$, draw a sphere centered at $M$ going through $A$. The other point where $AB$ meets the sphere is $D$.
$endgroup$
– Gerry Myerson
Apr 2 at 2:37
$begingroup$
Does this image capture the situation you are trying to describe?
$endgroup$
– John Wayland Bales
Apr 2 at 6:46
$begingroup$
@JohnWaylandBales Yes sir.
$endgroup$
– AgentX4000
Apr 2 at 7:01
$begingroup$
The camera image plane is perpendicular to the line of sight. So if point $C$ lies at the edge of the image plane, then point $D$ will lie in the center of the image plane.
$endgroup$
– John Wayland Bales
Apr 2 at 15:49
$begingroup$
@JohnWaylandBales Sir. I need to find the 3d point of that center.
$endgroup$
– AgentX4000
Apr 3 at 19:09