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Why is the likelihood for bayesian liner regression in that form?
The Next CEO of Stack OverflowQueries on the Bayesian methodAssessing goodness of fit in Bayesian frameworkConfusion about Notation for Bayesian StatisticsBayesian information criterion derivation for linear regressionUsing the linear regression equation in the Bayesian Model Averaging with RHow to optimize the log likelihood to obtain parameters for the maximum likelihood estimate?Bayesian Regression Simplifying the posteriorBayesian Interpretation for Ridge Regression and the LassoBayesian Linear RegressionWhy Bayesian Approach don't use test data for model validation?
$begingroup$
Let's say we have a linear model $Y = bX + e$ where $b$ represents the parameter.
Normally, the posterior is written like this for data $X_n$ and $Y_n: P(B|Y_n, X_n) = P(Y_n|X_n,b)P(b|X_n)/P(Y_n|X_n)$
Also, look at the following equation where D represents the data and L represents the parameters. The posterior is normally written like $P(L|D) = P(D|L)P(L)/P(D)$.
But if you do a direct substitution where $D = X_n,Y_n$ and $L = B$ you get:
$P(B|X_n,Y_n) = P(Y_n,X_n|b)P(b)/P(Y_n,X_n)$
Why is the second equation not used? What am I missing?
statistics regression bayesian
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
Let's say we have a linear model $Y = bX + e$ where $b$ represents the parameter.
Normally, the posterior is written like this for data $X_n$ and $Y_n: P(B|Y_n, X_n) = P(Y_n|X_n,b)P(b|X_n)/P(Y_n|X_n)$
Also, look at the following equation where D represents the data and L represents the parameters. The posterior is normally written like $P(L|D) = P(D|L)P(L)/P(D)$.
But if you do a direct substitution where $D = X_n,Y_n$ and $L = B$ you get:
$P(B|X_n,Y_n) = P(Y_n,X_n|b)P(b)/P(Y_n,X_n)$
Why is the second equation not used? What am I missing?
statistics regression bayesian
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Let's say we have a linear model $Y = bX + e$ where $b$ represents the parameter.
Normally, the posterior is written like this for data $X_n$ and $Y_n: P(B|Y_n, X_n) = P(Y_n|X_n,b)P(b|X_n)/P(Y_n|X_n)$
Also, look at the following equation where D represents the data and L represents the parameters. The posterior is normally written like $P(L|D) = P(D|L)P(L)/P(D)$.
But if you do a direct substitution where $D = X_n,Y_n$ and $L = B$ you get:
$P(B|X_n,Y_n) = P(Y_n,X_n|b)P(b)/P(Y_n,X_n)$
Why is the second equation not used? What am I missing?
statistics regression bayesian
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Let's say we have a linear model $Y = bX + e$ where $b$ represents the parameter.
Normally, the posterior is written like this for data $X_n$ and $Y_n: P(B|Y_n, X_n) = P(Y_n|X_n,b)P(b|X_n)/P(Y_n|X_n)$
Also, look at the following equation where D represents the data and L represents the parameters. The posterior is normally written like $P(L|D) = P(D|L)P(L)/P(D)$.
But if you do a direct substitution where $D = X_n,Y_n$ and $L = B$ you get:
$P(B|X_n,Y_n) = P(Y_n,X_n|b)P(b)/P(Y_n,X_n)$
Why is the second equation not used? What am I missing?
statistics regression bayesian
statistics regression bayesian
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
YuiTo Cheng
2,1612937
2,1612937
New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Anirudh SharmaAnirudh Sharma
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1
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New contributor
Anirudh Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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