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What do these sets mean? [on hold]



The Next CEO of Stack OverflowWhat does the following mean for sets?Equinumerosity of infinite setsWhat is the difference between these two simple sets?Find the cardinality of these setsNotation for a subset of a powersetWhat does $^(L)K$ mean?What do these sets mean? Relational AlgebraWhat Does the Logical Equivalence Symbol Mean Between Two Sets?Finite families of finite sets closed under union and intersectionWhat is the name of this operation between sets?










0












$begingroup$


What is the difference between A=1,2,3,4 and B=1,2,3,4?
why C=1,2,3,1 exists? what does these sets mean ?



In C, 1 is repeated...



Thank you so much










share|cite|improve this question











$endgroup$



put on hold as off-topic by José Carlos Santos, Shailesh, user21820, Saad, RRL yesterday


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Shailesh, user21820, Saad, RRL
If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    $begingroup$
    1 is a set containing 1; it is not the same as 1 itself
    $endgroup$
    – J. W. Tanner
    2 days ago










  • $begingroup$
    The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
    $endgroup$
    – drhab
    2 days ago















0












$begingroup$


What is the difference between A=1,2,3,4 and B=1,2,3,4?
why C=1,2,3,1 exists? what does these sets mean ?



In C, 1 is repeated...



Thank you so much










share|cite|improve this question











$endgroup$



put on hold as off-topic by José Carlos Santos, Shailesh, user21820, Saad, RRL yesterday


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Shailesh, user21820, Saad, RRL
If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    $begingroup$
    1 is a set containing 1; it is not the same as 1 itself
    $endgroup$
    – J. W. Tanner
    2 days ago










  • $begingroup$
    The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
    $endgroup$
    – drhab
    2 days ago













0












0








0


1



$begingroup$


What is the difference between A=1,2,3,4 and B=1,2,3,4?
why C=1,2,3,1 exists? what does these sets mean ?



In C, 1 is repeated...



Thank you so much










share|cite|improve this question











$endgroup$




What is the difference between A=1,2,3,4 and B=1,2,3,4?
why C=1,2,3,1 exists? what does these sets mean ?



In C, 1 is repeated...



Thank you so much







elementary-set-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 days ago









StackTD

24.3k2254




24.3k2254










asked 2 days ago









WwwWww

112




112




put on hold as off-topic by José Carlos Santos, Shailesh, user21820, Saad, RRL yesterday


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Shailesh, user21820, Saad, RRL
If this question can be reworded to fit the rules in the help center, please edit the question.







put on hold as off-topic by José Carlos Santos, Shailesh, user21820, Saad, RRL yesterday


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Shailesh, user21820, Saad, RRL
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 2




    $begingroup$
    1 is a set containing 1; it is not the same as 1 itself
    $endgroup$
    – J. W. Tanner
    2 days ago










  • $begingroup$
    The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
    $endgroup$
    – drhab
    2 days ago












  • 2




    $begingroup$
    1 is a set containing 1; it is not the same as 1 itself
    $endgroup$
    – J. W. Tanner
    2 days ago










  • $begingroup$
    The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
    $endgroup$
    – drhab
    2 days ago







2




2




$begingroup$
1 is a set containing 1; it is not the same as 1 itself
$endgroup$
– J. W. Tanner
2 days ago




$begingroup$
1 is a set containing 1; it is not the same as 1 itself
$endgroup$
– J. W. Tanner
2 days ago












$begingroup$
The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
$endgroup$
– drhab
2 days ago




$begingroup$
The set $C$ has $3$ elements: $1,2$, $3$ and $1$. None of them is mentioned twice. Two of the elements contain $1$ as an element.
$endgroup$
– drhab
2 days ago










3 Answers
3






active

oldest

votes


















4












$begingroup$

In a nutshell: "the number x" and "the set with $x$ as an element", written $leftxright$, are not the same.




what is the difference between A=1,2,3,4 and B=1,2,3,4?
why C=1,2,3,1 exists? what does these sets mean ?





  • $B$ is a set with four elements, those elements are the numbers $1$, $2$, $3$ and $4$;


  • $A$ is a set with four elements: those elements are the three numbers $2$, $3$ and $4$ and the set containing $1$ (written $left1right$);


  • $C=leftcolorblueleft1,left2rightright,colorgreen3,colorpurpleleft1rightright$ is a set with three elements:

    • the number $3$ (in green);

    • the set containing $1$ (in purple);

    • the set containing: the number $1$ and the set $left2right$ (in blue).






share|cite|improve this answer









$endgroup$












  • $begingroup$
    one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
    $endgroup$
    – Www
    2 days ago










  • $begingroup$
    What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
    $endgroup$
    – StackTD
    2 days ago










  • $begingroup$
    I mean Can I delete one of the 2 in set C=1,2,3,2
    $endgroup$
    – Www
    yesterday










  • $begingroup$
    Since 2 is repeated 2 times . thank you
    $endgroup$
    – Www
    yesterday










  • $begingroup$
    In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
    $endgroup$
    – StackTD
    yesterday


















0












$begingroup$

A contains one set; B contains none.



C contains two sets, and one of these sets contains a set.






share|cite|improve this answer









$endgroup$












  • $begingroup$
    What if $2,3,4$ are also sets (which is quite common in set-theory)?
    $endgroup$
    – drhab
    2 days ago










  • $begingroup$
    @drhab then you argue with the fact that the sets are distinct
    $endgroup$
    – B.Swan
    2 days ago










  • $begingroup$
    What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
    $endgroup$
    – drhab
    2 days ago



















0












$begingroup$

A lot of the answers here just answer the question in a way that I'm sure the OP has seen or read before. So I would like to explain in a way that would explain sets to say a 10-year-old. Say you have three cases, the first where you have $2$ bags, the second case where you have $1$ bag and the third case where you have $4$. Now in the first case say you put all of your objects into one bag and then you decide that some of the objects in the bag have common properties and you can group them together, but they still belong to the larger bag, so you take your second bag, put all the common items in and then put that inside the bigger bag.



Now take your second case where you just dump all the objects into one bag and don't bother with any inter-grouping. This is the second set in your question.



Third, you take the $4$ bags and put all the items in one giant bag and then take one item out that does not share any properties with the other but you still feel is important enough to have its own category. Then you find that you can have another one where multiple items can be grouped together and you put these in another bag, inside which you see one thing is important enough once again to have its own place but still belong to this larger group. Now you place the two bags, one with only one special item inside and the other with some items and one special item kept inside that bag in its own bag.

I know, got a little confusing there but if you understood what I was trying to do then you'll know what I'm talking about, This is analogous to sets and just common elements. The common elements are like all things just placed inside a big bag and the ones that have set brackets around them within the sets are the ones that are placed inside smaller bags and put inside the larger bag along with the rest of the items.






share|cite|improve this answer









$endgroup$



















    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4












    $begingroup$

    In a nutshell: "the number x" and "the set with $x$ as an element", written $leftxright$, are not the same.




    what is the difference between A=1,2,3,4 and B=1,2,3,4?
    why C=1,2,3,1 exists? what does these sets mean ?





    • $B$ is a set with four elements, those elements are the numbers $1$, $2$, $3$ and $4$;


    • $A$ is a set with four elements: those elements are the three numbers $2$, $3$ and $4$ and the set containing $1$ (written $left1right$);


    • $C=leftcolorblueleft1,left2rightright,colorgreen3,colorpurpleleft1rightright$ is a set with three elements:

      • the number $3$ (in green);

      • the set containing $1$ (in purple);

      • the set containing: the number $1$ and the set $left2right$ (in blue).






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
      $endgroup$
      – Www
      2 days ago










    • $begingroup$
      What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
      $endgroup$
      – StackTD
      2 days ago










    • $begingroup$
      I mean Can I delete one of the 2 in set C=1,2,3,2
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      Since 2 is repeated 2 times . thank you
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
      $endgroup$
      – StackTD
      yesterday















    4












    $begingroup$

    In a nutshell: "the number x" and "the set with $x$ as an element", written $leftxright$, are not the same.




    what is the difference between A=1,2,3,4 and B=1,2,3,4?
    why C=1,2,3,1 exists? what does these sets mean ?





    • $B$ is a set with four elements, those elements are the numbers $1$, $2$, $3$ and $4$;


    • $A$ is a set with four elements: those elements are the three numbers $2$, $3$ and $4$ and the set containing $1$ (written $left1right$);


    • $C=leftcolorblueleft1,left2rightright,colorgreen3,colorpurpleleft1rightright$ is a set with three elements:

      • the number $3$ (in green);

      • the set containing $1$ (in purple);

      • the set containing: the number $1$ and the set $left2right$ (in blue).






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
      $endgroup$
      – Www
      2 days ago










    • $begingroup$
      What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
      $endgroup$
      – StackTD
      2 days ago










    • $begingroup$
      I mean Can I delete one of the 2 in set C=1,2,3,2
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      Since 2 is repeated 2 times . thank you
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
      $endgroup$
      – StackTD
      yesterday













    4












    4








    4





    $begingroup$

    In a nutshell: "the number x" and "the set with $x$ as an element", written $leftxright$, are not the same.




    what is the difference between A=1,2,3,4 and B=1,2,3,4?
    why C=1,2,3,1 exists? what does these sets mean ?





    • $B$ is a set with four elements, those elements are the numbers $1$, $2$, $3$ and $4$;


    • $A$ is a set with four elements: those elements are the three numbers $2$, $3$ and $4$ and the set containing $1$ (written $left1right$);


    • $C=leftcolorblueleft1,left2rightright,colorgreen3,colorpurpleleft1rightright$ is a set with three elements:

      • the number $3$ (in green);

      • the set containing $1$ (in purple);

      • the set containing: the number $1$ and the set $left2right$ (in blue).






    share|cite|improve this answer









    $endgroup$



    In a nutshell: "the number x" and "the set with $x$ as an element", written $leftxright$, are not the same.




    what is the difference between A=1,2,3,4 and B=1,2,3,4?
    why C=1,2,3,1 exists? what does these sets mean ?





    • $B$ is a set with four elements, those elements are the numbers $1$, $2$, $3$ and $4$;


    • $A$ is a set with four elements: those elements are the three numbers $2$, $3$ and $4$ and the set containing $1$ (written $left1right$);


    • $C=leftcolorblueleft1,left2rightright,colorgreen3,colorpurpleleft1rightright$ is a set with three elements:

      • the number $3$ (in green);

      • the set containing $1$ (in purple);

      • the set containing: the number $1$ and the set $left2right$ (in blue).







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 2 days ago









    StackTDStackTD

    24.3k2254




    24.3k2254











    • $begingroup$
      one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
      $endgroup$
      – Www
      2 days ago










    • $begingroup$
      What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
      $endgroup$
      – StackTD
      2 days ago










    • $begingroup$
      I mean Can I delete one of the 2 in set C=1,2,3,2
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      Since 2 is repeated 2 times . thank you
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
      $endgroup$
      – StackTD
      yesterday
















    • $begingroup$
      one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
      $endgroup$
      – Www
      2 days ago










    • $begingroup$
      What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
      $endgroup$
      – StackTD
      2 days ago










    • $begingroup$
      I mean Can I delete one of the 2 in set C=1,2,3,2
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      Since 2 is repeated 2 times . thank you
      $endgroup$
      – Www
      yesterday










    • $begingroup$
      In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
      $endgroup$
      – StackTD
      yesterday















    $begingroup$
    one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
    $endgroup$
    – Www
    2 days ago




    $begingroup$
    one more question: C=1,2,3,2 then 2 should not exists two times right ? thank you btw, very clear
    $endgroup$
    – Www
    2 days ago












    $begingroup$
    What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
    $endgroup$
    – StackTD
    2 days ago




    $begingroup$
    What do you mean with "exist"? The set containing (only) 2, written 2, is an element of C. Another element of C, the set 1,2, has that same set containing (only) 2, written 2, as one of its (two) elements.
    $endgroup$
    – StackTD
    2 days ago












    $begingroup$
    I mean Can I delete one of the 2 in set C=1,2,3,2
    $endgroup$
    – Www
    yesterday




    $begingroup$
    I mean Can I delete one of the 2 in set C=1,2,3,2
    $endgroup$
    – Www
    yesterday












    $begingroup$
    Since 2 is repeated 2 times . thank you
    $endgroup$
    – Www
    yesterday




    $begingroup$
    Since 2 is repeated 2 times . thank you
    $endgroup$
    – Www
    yesterday












    $begingroup$
    In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
    $endgroup$
    – StackTD
    yesterday




    $begingroup$
    In your question above that last number is a 1, not a 2...? But in both cases: no, you can't. In 1,2,2, you can delete a 2; in 1,2,2 you can't because there's only one element which is 2, since it's not the same as the element 2. See the first line of my answer.
    $endgroup$
    – StackTD
    yesterday











    0












    $begingroup$

    A contains one set; B contains none.



    C contains two sets, and one of these sets contains a set.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      What if $2,3,4$ are also sets (which is quite common in set-theory)?
      $endgroup$
      – drhab
      2 days ago










    • $begingroup$
      @drhab then you argue with the fact that the sets are distinct
      $endgroup$
      – B.Swan
      2 days ago










    • $begingroup$
      What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
      $endgroup$
      – drhab
      2 days ago
















    0












    $begingroup$

    A contains one set; B contains none.



    C contains two sets, and one of these sets contains a set.






    share|cite|improve this answer









    $endgroup$












    • $begingroup$
      What if $2,3,4$ are also sets (which is quite common in set-theory)?
      $endgroup$
      – drhab
      2 days ago










    • $begingroup$
      @drhab then you argue with the fact that the sets are distinct
      $endgroup$
      – B.Swan
      2 days ago










    • $begingroup$
      What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
      $endgroup$
      – drhab
      2 days ago














    0












    0








    0





    $begingroup$

    A contains one set; B contains none.



    C contains two sets, and one of these sets contains a set.






    share|cite|improve this answer









    $endgroup$



    A contains one set; B contains none.



    C contains two sets, and one of these sets contains a set.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 2 days ago









    Jossie CalderonJossie Calderon

    291111




    291111











    • $begingroup$
      What if $2,3,4$ are also sets (which is quite common in set-theory)?
      $endgroup$
      – drhab
      2 days ago










    • $begingroup$
      @drhab then you argue with the fact that the sets are distinct
      $endgroup$
      – B.Swan
      2 days ago










    • $begingroup$
      What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
      $endgroup$
      – drhab
      2 days ago

















    • $begingroup$
      What if $2,3,4$ are also sets (which is quite common in set-theory)?
      $endgroup$
      – drhab
      2 days ago










    • $begingroup$
      @drhab then you argue with the fact that the sets are distinct
      $endgroup$
      – B.Swan
      2 days ago










    • $begingroup$
      What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
      $endgroup$
      – drhab
      2 days ago
















    $begingroup$
    What if $2,3,4$ are also sets (which is quite common in set-theory)?
    $endgroup$
    – drhab
    2 days ago




    $begingroup$
    What if $2,3,4$ are also sets (which is quite common in set-theory)?
    $endgroup$
    – drhab
    2 days ago












    $begingroup$
    @drhab then you argue with the fact that the sets are distinct
    $endgroup$
    – B.Swan
    2 days ago




    $begingroup$
    @drhab then you argue with the fact that the sets are distinct
    $endgroup$
    – B.Swan
    2 days ago












    $begingroup$
    What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
    $endgroup$
    – drhab
    2 days ago





    $begingroup$
    What I mean is that - if $2,3,4$ are sets - then e.g. $A$ contains $4$ sets as elements (not just one as you state). From the question on its own it cannot be deduced that $A$ contains one set as element (or that $B$ contains none).
    $endgroup$
    – drhab
    2 days ago












    0












    $begingroup$

    A lot of the answers here just answer the question in a way that I'm sure the OP has seen or read before. So I would like to explain in a way that would explain sets to say a 10-year-old. Say you have three cases, the first where you have $2$ bags, the second case where you have $1$ bag and the third case where you have $4$. Now in the first case say you put all of your objects into one bag and then you decide that some of the objects in the bag have common properties and you can group them together, but they still belong to the larger bag, so you take your second bag, put all the common items in and then put that inside the bigger bag.



    Now take your second case where you just dump all the objects into one bag and don't bother with any inter-grouping. This is the second set in your question.



    Third, you take the $4$ bags and put all the items in one giant bag and then take one item out that does not share any properties with the other but you still feel is important enough to have its own category. Then you find that you can have another one where multiple items can be grouped together and you put these in another bag, inside which you see one thing is important enough once again to have its own place but still belong to this larger group. Now you place the two bags, one with only one special item inside and the other with some items and one special item kept inside that bag in its own bag.

    I know, got a little confusing there but if you understood what I was trying to do then you'll know what I'm talking about, This is analogous to sets and just common elements. The common elements are like all things just placed inside a big bag and the ones that have set brackets around them within the sets are the ones that are placed inside smaller bags and put inside the larger bag along with the rest of the items.






    share|cite|improve this answer









    $endgroup$

















      0












      $begingroup$

      A lot of the answers here just answer the question in a way that I'm sure the OP has seen or read before. So I would like to explain in a way that would explain sets to say a 10-year-old. Say you have three cases, the first where you have $2$ bags, the second case where you have $1$ bag and the third case where you have $4$. Now in the first case say you put all of your objects into one bag and then you decide that some of the objects in the bag have common properties and you can group them together, but they still belong to the larger bag, so you take your second bag, put all the common items in and then put that inside the bigger bag.



      Now take your second case where you just dump all the objects into one bag and don't bother with any inter-grouping. This is the second set in your question.



      Third, you take the $4$ bags and put all the items in one giant bag and then take one item out that does not share any properties with the other but you still feel is important enough to have its own category. Then you find that you can have another one where multiple items can be grouped together and you put these in another bag, inside which you see one thing is important enough once again to have its own place but still belong to this larger group. Now you place the two bags, one with only one special item inside and the other with some items and one special item kept inside that bag in its own bag.

      I know, got a little confusing there but if you understood what I was trying to do then you'll know what I'm talking about, This is analogous to sets and just common elements. The common elements are like all things just placed inside a big bag and the ones that have set brackets around them within the sets are the ones that are placed inside smaller bags and put inside the larger bag along with the rest of the items.






      share|cite|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        A lot of the answers here just answer the question in a way that I'm sure the OP has seen or read before. So I would like to explain in a way that would explain sets to say a 10-year-old. Say you have three cases, the first where you have $2$ bags, the second case where you have $1$ bag and the third case where you have $4$. Now in the first case say you put all of your objects into one bag and then you decide that some of the objects in the bag have common properties and you can group them together, but they still belong to the larger bag, so you take your second bag, put all the common items in and then put that inside the bigger bag.



        Now take your second case where you just dump all the objects into one bag and don't bother with any inter-grouping. This is the second set in your question.



        Third, you take the $4$ bags and put all the items in one giant bag and then take one item out that does not share any properties with the other but you still feel is important enough to have its own category. Then you find that you can have another one where multiple items can be grouped together and you put these in another bag, inside which you see one thing is important enough once again to have its own place but still belong to this larger group. Now you place the two bags, one with only one special item inside and the other with some items and one special item kept inside that bag in its own bag.

        I know, got a little confusing there but if you understood what I was trying to do then you'll know what I'm talking about, This is analogous to sets and just common elements. The common elements are like all things just placed inside a big bag and the ones that have set brackets around them within the sets are the ones that are placed inside smaller bags and put inside the larger bag along with the rest of the items.






        share|cite|improve this answer









        $endgroup$



        A lot of the answers here just answer the question in a way that I'm sure the OP has seen or read before. So I would like to explain in a way that would explain sets to say a 10-year-old. Say you have three cases, the first where you have $2$ bags, the second case where you have $1$ bag and the third case where you have $4$. Now in the first case say you put all of your objects into one bag and then you decide that some of the objects in the bag have common properties and you can group them together, but they still belong to the larger bag, so you take your second bag, put all the common items in and then put that inside the bigger bag.



        Now take your second case where you just dump all the objects into one bag and don't bother with any inter-grouping. This is the second set in your question.



        Third, you take the $4$ bags and put all the items in one giant bag and then take one item out that does not share any properties with the other but you still feel is important enough to have its own category. Then you find that you can have another one where multiple items can be grouped together and you put these in another bag, inside which you see one thing is important enough once again to have its own place but still belong to this larger group. Now you place the two bags, one with only one special item inside and the other with some items and one special item kept inside that bag in its own bag.

        I know, got a little confusing there but if you understood what I was trying to do then you'll know what I'm talking about, This is analogous to sets and just common elements. The common elements are like all things just placed inside a big bag and the ones that have set brackets around them within the sets are the ones that are placed inside smaller bags and put inside the larger bag along with the rest of the items.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 2 days ago









        Prakhar NagpalPrakhar Nagpal

        752318




        752318













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