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Connection between Rayleigh's formula and solution of the Steklov eigenvalue problem



The Next CEO of Stack OverflowFirst Weighted Eigenvalue of the LaplacianWeak formulation for nonhomogeneous problem $-Delta u = 0$rayleigh quotient of eigenvalue problem (sturm liouville theory and partial differential equations)Does the solution of my variational problem satisfy a specific Neumann boundary condition?Calculation of $fracdlambdadt$ under volume preserving mean curvature flowSecond Steklov operator and Dirichet-to-Neumann operator for a diskEnergy functional of Poisson equationProof that Poisson formula solves the Neumann Problem for Laplace Equation in Unit DiskLaplace equation with the Robin's boundary problemAbout positivity of a solution to a sub-critical semilinear elliptic problem










0












$begingroup$


Given the Steklov eigenvalue problem
$$
beginalign*
Delta u &= 0 ~~~textin B_r \
partial_nu u &= lambda u ~~~textin partial B_r.
endalign*
$$



Then we can express the first positiv eigenvalue $lambda_1$ of this problem via Rayleigh's formula



$$
lambda_1 :=min_uin C^infty(B_R) leftlbrace fracint_B_R int_partial B_R u^2~~|~~int_partial B_R u = 0 rightrbrace.
$$



Say now that this minimum is obtained at $u^*$.
My Question now is, if $u^*$ also solves the Steklov Prolem?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
    $endgroup$
    – Bara
    2 days ago











  • $begingroup$
    Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
    $endgroup$
    – amsmath
    2 days ago
















0












$begingroup$


Given the Steklov eigenvalue problem
$$
beginalign*
Delta u &= 0 ~~~textin B_r \
partial_nu u &= lambda u ~~~textin partial B_r.
endalign*
$$



Then we can express the first positiv eigenvalue $lambda_1$ of this problem via Rayleigh's formula



$$
lambda_1 :=min_uin C^infty(B_R) leftlbrace fracint_B_R int_partial B_R u^2~~|~~int_partial B_R u = 0 rightrbrace.
$$



Say now that this minimum is obtained at $u^*$.
My Question now is, if $u^*$ also solves the Steklov Prolem?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
    $endgroup$
    – Bara
    2 days ago











  • $begingroup$
    Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
    $endgroup$
    – amsmath
    2 days ago














0












0








0





$begingroup$


Given the Steklov eigenvalue problem
$$
beginalign*
Delta u &= 0 ~~~textin B_r \
partial_nu u &= lambda u ~~~textin partial B_r.
endalign*
$$



Then we can express the first positiv eigenvalue $lambda_1$ of this problem via Rayleigh's formula



$$
lambda_1 :=min_uin C^infty(B_R) leftlbrace fracint_B_R int_partial B_R u^2~~|~~int_partial B_R u = 0 rightrbrace.
$$



Say now that this minimum is obtained at $u^*$.
My Question now is, if $u^*$ also solves the Steklov Prolem?










share|cite|improve this question









$endgroup$




Given the Steklov eigenvalue problem
$$
beginalign*
Delta u &= 0 ~~~textin B_r \
partial_nu u &= lambda u ~~~textin partial B_r.
endalign*
$$



Then we can express the first positiv eigenvalue $lambda_1$ of this problem via Rayleigh's formula



$$
lambda_1 :=min_uin C^infty(B_R) leftlbrace fracint_B_R int_partial B_R u^2~~|~~int_partial B_R u = 0 rightrbrace.
$$



Say now that this minimum is obtained at $u^*$.
My Question now is, if $u^*$ also solves the Steklov Prolem?







functional-analysis analysis pde






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 2 days ago









BaraBara

6510




6510







  • 1




    $begingroup$
    What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
    $endgroup$
    – Bara
    2 days ago











  • $begingroup$
    Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
    $endgroup$
    – amsmath
    2 days ago













  • 1




    $begingroup$
    What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
    $endgroup$
    – Bara
    2 days ago











  • $begingroup$
    Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
    $endgroup$
    – amsmath
    2 days ago










  • $begingroup$
    Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
    $endgroup$
    – amsmath
    2 days ago








1




1




$begingroup$
What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
$endgroup$
– amsmath
2 days ago




$begingroup$
What you have there is the lowest eigenvalue of the Laplacian $-Delta$ with Dirichlet boundary conditions. I don't see how this is related to your problem.
$endgroup$
– amsmath
2 days ago












$begingroup$
The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
$endgroup$
– Bara
2 days ago





$begingroup$
The Dirichlet eigenvalue problem should pop up if the denominator would be an integral over $B_R$ not $partial B_R$ or am I mistaken there?
$endgroup$
– Bara
2 days ago













$begingroup$
Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
$endgroup$
– amsmath
2 days ago




$begingroup$
Oh, correct. Missed that, sorry. But how do you get this minimum? What is your operator?
$endgroup$
– amsmath
2 days ago












$begingroup$
Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
$endgroup$
– amsmath
2 days ago





$begingroup$
Just read your actual question. If $A$ is a self-adjoint operator which is bounded below by $lambda_1$ and $(Au,u) = lambda_1|u|^2$, then $Au = lambda_1 u$.
$endgroup$
– amsmath
2 days ago











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