Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case The Next CEO of Stack OverflowDetermine the density function…$overlineX rightarrow c$ in probability $Rightarrow g(overlineX) rightarrow g(c)$ in probabilityHow to determine the Moment Gen Function of $overlineX$?Determining the efficiency of $2 overline X$.one to one transformation for the bivariate case.Determine the maximum-likelihood estimation for $lambda$Let X be the average of a sample of 16 independent normal random variables with mean 0 and variance 1. Determine c such that P(|X| < c) = .5Determine the convergence of $overlineX^2_n$Distribution of $fracoverline X - overline Y - (mu_1 -mu_2)sqrtfrac1m+n-2 [(m-1)*s_1^2+(n-1)*s_2^2](frac1m+frac1n)$Expected value and variance of $frac X - overline Xs$
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Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case
The Next CEO of Stack OverflowDetermine the density function…$overlineX rightarrow c$ in probability $Rightarrow g(overlineX) rightarrow g(c)$ in probabilityHow to determine the Moment Gen Function of $overlineX$?Determining the efficiency of $2 overline X$.one to one transformation for the bivariate case.Determine the maximum-likelihood estimation for $lambda$Let X be the average of a sample of 16 independent normal random variables with mean 0 and variance 1. Determine c such that P(|X| < c) = .5Determine the convergence of $overlineX^2_n$Distribution of $fracoverline X - overline Y - (mu_1 -mu_2)sqrtfrac1m+n-2 [(m-1)*s_1^2+(n-1)*s_2^2](frac1m+frac1n)$Expected value and variance of $frac X - overline Xs$
$begingroup$
Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case:
$A$, $B$ and $C$ are incompatible two by two and $P (A) = 3/8$
I did this:
$P (A ∪ (overlineoverlineB ∪ overlineC)) =P(A∪B)∩P(A∪C)=P(A∪B)+P(A∪C)-P(A∪B∪C)$
but I don't know how to go on.
probability statistics
asked 2 days ago
user649882user649882
144
$endgroup$
add a comment |
$begingroup$
Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case:
$A$, $B$ and $C$ are incompatible two by two and $P (A) = 3/8$
I did this:
$P (A ∪ (overlineoverlineB ∪ overlineC)) =P(A∪B)∩P(A∪C)=P(A∪B)+P(A∪C)-P(A∪B∪C)$
but I don't know how to go on.
probability statistics
asked 2 days ago
user649882user649882
144
$endgroup$
add a comment |
$begingroup$
Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case:
$A$, $B$ and $C$ are incompatible two by two and $P (A) = 3/8$
I did this:
$P (A ∪ (overlineoverlineB ∪ overlineC)) =P(A∪B)∩P(A∪C)=P(A∪B)+P(A∪C)-P(A∪B∪C)$
but I don't know how to go on.
probability statistics
asked 2 days ago
user649882user649882
144
$endgroup$
Determine $P (A ∪ (overlineoverlineB ∪ overlineC))$ in the following case:
$A$, $B$ and $C$ are incompatible two by two and $P (A) = 3/8$
I did this:
$P (A ∪ (overlineoverlineB ∪ overlineC)) =P(A∪B)∩P(A∪C)=P(A∪B)+P(A∪C)-P(A∪B∪C)$
but I don't know how to go on.
probability statistics
probability statistics
asked 2 days ago
user649882user649882
144
asked 2 days ago
user649882user649882
144
asked 2 days ago
user649882user649882
144
asked 2 days ago
user649882user649882
144
asked 2 days ago
user649882user649882
144
144
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Your notation is a bit confusing to me. I would do this:
beginalign*
Pleft(!Acupoverlineleft(overlineBcupoverlineCright),right)&=P(!Acup(Bcap C))\
&=P(Acupvarnothing)\
&=P(A)\
&=frac38.
endalign*
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
$endgroup$
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
|
show 9 more comments
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your notation is a bit confusing to me. I would do this:
beginalign*
Pleft(!Acupoverlineleft(overlineBcupoverlineCright),right)&=P(!Acup(Bcap C))\
&=P(Acupvarnothing)\
&=P(A)\
&=frac38.
endalign*
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
$endgroup$
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
|
show 9 more comments
$begingroup$
Your notation is a bit confusing to me. I would do this:
beginalign*
Pleft(!Acupoverlineleft(overlineBcupoverlineCright),right)&=P(!Acup(Bcap C))\
&=P(Acupvarnothing)\
&=P(A)\
&=frac38.
endalign*
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
$endgroup$
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
|
show 9 more comments
$begingroup$
Your notation is a bit confusing to me. I would do this:
beginalign*
Pleft(!Acupoverlineleft(overlineBcupoverlineCright),right)&=P(!Acup(Bcap C))\
&=P(Acupvarnothing)\
&=P(A)\
&=frac38.
endalign*
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
$endgroup$
Your notation is a bit confusing to me. I would do this:
beginalign*
Pleft(!Acupoverlineleft(overlineBcupoverlineCright),right)&=P(!Acup(Bcap C))\
&=P(Acupvarnothing)\
&=P(A)\
&=frac38.
endalign*
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
answered 2 days ago
Adrian KeisterAdrian Keister
5,28171933
5,28171933
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
|
show 9 more comments
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
$B∩C=∅$ because B and C are incompatible?
$endgroup$
– user649882
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
Exactly, that's how I read it.
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
if I have $something∩0$ what is it equal to?
$endgroup$
– user649882
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
The null set behaves like this: $Acupvarnothing=A$ for all sets $A,$ and $Acapvarnothing=varnothing$ for all sets $A.$
$endgroup$
– Adrian Keister
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
$begingroup$
If $P(A) = 1/2, P(B ∩ C) = 1/4, P(A ∩ C) = 0$ how do I find $P (A ∪ (overlineoverlineB ∪ overlineC))$?
$endgroup$
– user649882
2 days ago
|
show 9 more comments
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