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Are these modified harmonic series divergent?
The Next CEO of Stack OverflowDifference of harmonic seriesDoes this modified harmonic series converge?Harmonic series principal valueA modification of the terms of the harmonic seriesSign fluctuation in the harmonic series (sum)Kempner's series vs harmonic series (convergent vs divergent series via exclusion)Is this a valid way to prove this modified harmonic series diverges?Prove that the harmonic series $sum_i=1^infty frac1i$ is divergent by using induction?Modified alternating harmonic seriesA question about divergent series related to the harmonic series
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If a new series is formed by taking every $nmathrmth$ term (eg for $n=3$, the 3rd, 6th, 9th etc terms) of the harmonic series$$sum_k=1^inftyfrac1k=frac11+frac12+frac13+cdots$$ is this new series divergent?
sequences-and-series
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add a comment |
$begingroup$
If a new series is formed by taking every $nmathrmth$ term (eg for $n=3$, the 3rd, 6th, 9th etc terms) of the harmonic series$$sum_k=1^inftyfrac1k=frac11+frac12+frac13+cdots$$ is this new series divergent?
sequences-and-series
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3
$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
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– Crostul
2 days ago
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Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
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– Peter4075
2 days ago
add a comment |
$begingroup$
If a new series is formed by taking every $nmathrmth$ term (eg for $n=3$, the 3rd, 6th, 9th etc terms) of the harmonic series$$sum_k=1^inftyfrac1k=frac11+frac12+frac13+cdots$$ is this new series divergent?
sequences-and-series
$endgroup$
If a new series is formed by taking every $nmathrmth$ term (eg for $n=3$, the 3rd, 6th, 9th etc terms) of the harmonic series$$sum_k=1^inftyfrac1k=frac11+frac12+frac13+cdots$$ is this new series divergent?
sequences-and-series
sequences-and-series
asked 2 days ago
Peter4075Peter4075
441521
441521
3
$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
$endgroup$
– Crostul
2 days ago
$begingroup$
Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
$endgroup$
– Peter4075
2 days ago
add a comment |
3
$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
$endgroup$
– Crostul
2 days ago
$begingroup$
Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
$endgroup$
– Peter4075
2 days ago
3
3
$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
$endgroup$
– Crostul
2 days ago
$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
$endgroup$
– Crostul
2 days ago
$begingroup$
Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
$endgroup$
– Peter4075
2 days ago
$begingroup$
Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
$endgroup$
– Peter4075
2 days ago
add a comment |
1 Answer
1
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$begingroup$
Yes, it is. For example, for $n=3$, you have
$$frac13+ frac16+ frac19+ frac112+ cdots = frac13 left(
frac11+ frac12+ frac13+ frac14+ cdotsright) = infty$$
$endgroup$
add a comment |
Your Answer
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1 Answer
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1 Answer
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$begingroup$
Yes, it is. For example, for $n=3$, you have
$$frac13+ frac16+ frac19+ frac112+ cdots = frac13 left(
frac11+ frac12+ frac13+ frac14+ cdotsright) = infty$$
$endgroup$
add a comment |
$begingroup$
Yes, it is. For example, for $n=3$, you have
$$frac13+ frac16+ frac19+ frac112+ cdots = frac13 left(
frac11+ frac12+ frac13+ frac14+ cdotsright) = infty$$
$endgroup$
add a comment |
$begingroup$
Yes, it is. For example, for $n=3$, you have
$$frac13+ frac16+ frac19+ frac112+ cdots = frac13 left(
frac11+ frac12+ frac13+ frac14+ cdotsright) = infty$$
$endgroup$
Yes, it is. For example, for $n=3$, you have
$$frac13+ frac16+ frac19+ frac112+ cdots = frac13 left(
frac11+ frac12+ frac13+ frac14+ cdotsright) = infty$$
answered 2 days ago
CrostulCrostul
28.2k22352
28.2k22352
add a comment |
add a comment |
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$begingroup$
Yes it is. For example, for $n=3$, you have $$frac13+frac16+frac19+frac112 +cdots = frac13 left( frac11+frac12+frac13+frac14+ cdots right) = infty $$
$endgroup$
– Crostul
2 days ago
$begingroup$
Whoops, I should have seen that coming. If you make that comment an answer, I'll happily accept it :-)
$endgroup$
– Peter4075
2 days ago