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Proving what failed a simple inequality test?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Proving Absolute Value InequalityProving the Power Mean Inequality using Chebyshev's sum inequalityProving Jensen's inequality.A peculiar quadratic inequality--Has it been seen before?Proving Inequality with the Greatest Integer FunctionProving a simple Algebraic InequalityHow to get from this inequality to the next?Simple Inequality Proof Seems BafflingAristarchus' Inequality - algebraic proofProving the following quadratic inequality?
$begingroup$
Prove that:
$fracb-a1+b^2<tan^-1b-tan^-1a<fracb-a1+a^2$
If $a < b$
Inequality test:
Let $a=15$, $b=20$ then $15 < 20$
$frac20-151+20^2<tan^-120-tan^-115<frac20-151+15^2$
$0.012<0.9516<0.022$
of course this is completely out of context...
could there have been something I missed or the question itself is completely erroneous??
inequality
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
$endgroup$
add a comment |
$begingroup$
Prove that:
$fracb-a1+b^2<tan^-1b-tan^-1a<fracb-a1+a^2$
If $a < b$
Inequality test:
Let $a=15$, $b=20$ then $15 < 20$
$frac20-151+20^2<tan^-120-tan^-115<frac20-151+15^2$
$0.012<0.9516<0.022$
of course this is completely out of context...
could there have been something I missed or the question itself is completely erroneous??
inequality
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
$endgroup$
$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47
add a comment |
$begingroup$
Prove that:
$fracb-a1+b^2<tan^-1b-tan^-1a<fracb-a1+a^2$
If $a < b$
Inequality test:
Let $a=15$, $b=20$ then $15 < 20$
$frac20-151+20^2<tan^-120-tan^-115<frac20-151+15^2$
$0.012<0.9516<0.022$
of course this is completely out of context...
could there have been something I missed or the question itself is completely erroneous??
inequality
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
$endgroup$
Prove that:
$fracb-a1+b^2<tan^-1b-tan^-1a<fracb-a1+a^2$
If $a < b$
Inequality test:
Let $a=15$, $b=20$ then $15 < 20$
$frac20-151+20^2<tan^-120-tan^-115<frac20-151+15^2$
$0.012<0.9516<0.022$
of course this is completely out of context...
could there have been something I missed or the question itself is completely erroneous??
inequality
inequality
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
asked Mar 31 at 22:43
Orestes DanteOrestes Dante
526
526
$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47
add a comment |
$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47
$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47
$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
What you missed: you should have used radians instead of degrees.
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
$endgroup$
add a comment |
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$begingroup$
What you missed: you should have used radians instead of degrees.
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
$endgroup$
add a comment |
$begingroup$
What you missed: you should have used radians instead of degrees.
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
$endgroup$
add a comment |
$begingroup$
What you missed: you should have used radians instead of degrees.
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
$endgroup$
What you missed: you should have used radians instead of degrees.
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
answered Mar 31 at 23:05
J. W. TannerJ. W. Tanner
4,7971420
4,7971420
add a comment |
add a comment |
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$begingroup$
Try to divide by (b-a) the middle term is similar to the slope of the bisection between (a,f(a)),(b,f(b)).
$endgroup$
– Ameryr
Mar 31 at 22:47