How to do implicit differentiation to get an ODE Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Laplace question continued (partial fractions)How to differentiate the equation under the integral signFind the solution to the initial value problem $overlinex' = Aoverlinex, x(0) = beginbmatrix2 \ 28endbmatrix $How to solve this implicit differentiation problem concerning arcsin?inhomogeneous second order odeSolving a simple system of odeDetermine the Eigen values and Eigen functions of the problem $y''+μy=0$; $y(0)=0$,$y'(L)=0$Solve ODE with exactnessRearranging terms in an ODEWhat is a 'reasonable' ordinary differential equation question?

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How to do implicit differentiation to get an ODE



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Laplace question continued (partial fractions)How to differentiate the equation under the integral signFind the solution to the initial value problem $overlinex' = Aoverlinex, x(0) = beginbmatrix2 \ 28endbmatrix $How to solve this implicit differentiation problem concerning arcsin?inhomogeneous second order odeSolving a simple system of odeDetermine the Eigen values and Eigen functions of the problem $y''+μy=0$; $y(0)=0$,$y'(L)=0$Solve ODE with exactnessRearranging terms in an ODEWhat is a 'reasonable' ordinary differential equation question?










0












$begingroup$


enter image description here



$$ye^y^2 = x + q $$



Hi I was following a similar question as an example to answer this one and although I have got the answer I don't think my working is correct as I sort of made one part up and I don't fully understand it. I was hoping someone could help and check to see if my working is correct.



Line $1$ is the question and the Last Line is the correct answer but I don't get line $4$ and $5$. I just followed an example I was looking at but I don't actually understand it and I'm pretty sure it's not correct either.



Any help will be appreciated thank you.










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    enter image description here



    $$ye^y^2 = x + q $$



    Hi I was following a similar question as an example to answer this one and although I have got the answer I don't think my working is correct as I sort of made one part up and I don't fully understand it. I was hoping someone could help and check to see if my working is correct.



    Line $1$ is the question and the Last Line is the correct answer but I don't get line $4$ and $5$. I just followed an example I was looking at but I don't actually understand it and I'm pretty sure it's not correct either.



    Any help will be appreciated thank you.










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      enter image description here



      $$ye^y^2 = x + q $$



      Hi I was following a similar question as an example to answer this one and although I have got the answer I don't think my working is correct as I sort of made one part up and I don't fully understand it. I was hoping someone could help and check to see if my working is correct.



      Line $1$ is the question and the Last Line is the correct answer but I don't get line $4$ and $5$. I just followed an example I was looking at but I don't actually understand it and I'm pretty sure it's not correct either.



      Any help will be appreciated thank you.










      share|cite|improve this question











      $endgroup$




      enter image description here



      $$ye^y^2 = x + q $$



      Hi I was following a similar question as an example to answer this one and although I have got the answer I don't think my working is correct as I sort of made one part up and I don't fully understand it. I was hoping someone could help and check to see if my working is correct.



      Line $1$ is the question and the Last Line is the correct answer but I don't get line $4$ and $5$. I just followed an example I was looking at but I don't actually understand it and I'm pretty sure it's not correct either.



      Any help will be appreciated thank you.







      ordinary-differential-equations






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Apr 1 at 1:45









      John Doe

      12.1k11339




      12.1k11339










      asked Apr 1 at 1:26









      CinnaCinna

      193




      193




















          1 Answer
          1






          active

          oldest

          votes


















          0












          $begingroup$

          The step you seem to be confused over is computing $fracddx(y^2)$. This is $$fracddxy^2=fracdydxfrac ddy(y^2)=y'times 2y=2yy'$$ Then the rest of the working follows fine.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            That makes a lot more sense thank you so much :)
            $endgroup$
            – Cinna
            Apr 1 at 1:43











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          1 Answer
          1






          active

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          active

          oldest

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          active

          oldest

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          0












          $begingroup$

          The step you seem to be confused over is computing $fracddx(y^2)$. This is $$fracddxy^2=fracdydxfrac ddy(y^2)=y'times 2y=2yy'$$ Then the rest of the working follows fine.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            That makes a lot more sense thank you so much :)
            $endgroup$
            – Cinna
            Apr 1 at 1:43















          0












          $begingroup$

          The step you seem to be confused over is computing $fracddx(y^2)$. This is $$fracddxy^2=fracdydxfrac ddy(y^2)=y'times 2y=2yy'$$ Then the rest of the working follows fine.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            That makes a lot more sense thank you so much :)
            $endgroup$
            – Cinna
            Apr 1 at 1:43













          0












          0








          0





          $begingroup$

          The step you seem to be confused over is computing $fracddx(y^2)$. This is $$fracddxy^2=fracdydxfrac ddy(y^2)=y'times 2y=2yy'$$ Then the rest of the working follows fine.






          share|cite|improve this answer









          $endgroup$



          The step you seem to be confused over is computing $fracddx(y^2)$. This is $$fracddxy^2=fracdydxfrac ddy(y^2)=y'times 2y=2yy'$$ Then the rest of the working follows fine.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Apr 1 at 1:32









          John DoeJohn Doe

          12.1k11339




          12.1k11339











          • $begingroup$
            That makes a lot more sense thank you so much :)
            $endgroup$
            – Cinna
            Apr 1 at 1:43
















          • $begingroup$
            That makes a lot more sense thank you so much :)
            $endgroup$
            – Cinna
            Apr 1 at 1:43















          $begingroup$
          That makes a lot more sense thank you so much :)
          $endgroup$
          – Cinna
          Apr 1 at 1:43




          $begingroup$
          That makes a lot more sense thank you so much :)
          $endgroup$
          – Cinna
          Apr 1 at 1:43

















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