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Laplace functional for given process.
“Paradox” of a Poisson process on $mathbb R$Spectral process for the Ornstein-Uhlenbeck processDistribution of stochastic integral w.r.t. to centered Poisson processConditional distribution of compounded Poisson processProve that a process has independent incrementsDistribution of the increments of a Compound Poisson processCompute $Eleft[fracW_N(t)+1N(t) + 1right]$ where $(N(t))$ is a homogenous Poisson processHow to compute the integral of a renewal process?How to construct a Poisson process not based on Lebesgue measure?Compound Binomial - Exponential process
$begingroup$
Consider $X_1 dots $ i.r.v with $Exp(lambda)$ distribution. Let's consider $S_n = X_1 + dots + X_n$.
So we may construct a point process $Y = Y(B) = sum mathbb1_B(S_n) , Bin mathfrakB(mathbbR) $.
No we need to find $mathfrakL(f) = mathbbE(exp[-sum_n f(S_n)])$,
My attempt :
First of all let's suppose that we have $xi $~$Gamma(n,frac1lambda)$ , when $mathbbE(exp[-sxi]) = left(dfraclambdalambda + sright)^n$.
Let's consider $f = sum_k = 1^m a_kmathbb1_B_k$, hence we have :
$mathfrakL(f) = mathbbEexp[-sum_n^infty sum_k^m a_k mathbb1_B_k(S_n)]$ replace sum sign due to positive terms.
$mathfrakL(f) = prod mathbbE exp[-a_k Y(B_k)]$, but there is the stuck problem.
What should I do now?
probability stochastic-processes expected-value
$endgroup$
This question has an open bounty worth +100
reputation from openspace ending ending at 2019-04-03 07:12:38Z">in 6 days.
The question is widely applicable to a large audience. A detailed canonical answer is required to address all the concerns.
add a comment |
$begingroup$
Consider $X_1 dots $ i.r.v with $Exp(lambda)$ distribution. Let's consider $S_n = X_1 + dots + X_n$.
So we may construct a point process $Y = Y(B) = sum mathbb1_B(S_n) , Bin mathfrakB(mathbbR) $.
No we need to find $mathfrakL(f) = mathbbE(exp[-sum_n f(S_n)])$,
My attempt :
First of all let's suppose that we have $xi $~$Gamma(n,frac1lambda)$ , when $mathbbE(exp[-sxi]) = left(dfraclambdalambda + sright)^n$.
Let's consider $f = sum_k = 1^m a_kmathbb1_B_k$, hence we have :
$mathfrakL(f) = mathbbEexp[-sum_n^infty sum_k^m a_k mathbb1_B_k(S_n)]$ replace sum sign due to positive terms.
$mathfrakL(f) = prod mathbbE exp[-a_k Y(B_k)]$, but there is the stuck problem.
What should I do now?
probability stochastic-processes expected-value
$endgroup$
This question has an open bounty worth +100
reputation from openspace ending ending at 2019-04-03 07:12:38Z">in 6 days.
The question is widely applicable to a large audience. A detailed canonical answer is required to address all the concerns.
$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago
add a comment |
$begingroup$
Consider $X_1 dots $ i.r.v with $Exp(lambda)$ distribution. Let's consider $S_n = X_1 + dots + X_n$.
So we may construct a point process $Y = Y(B) = sum mathbb1_B(S_n) , Bin mathfrakB(mathbbR) $.
No we need to find $mathfrakL(f) = mathbbE(exp[-sum_n f(S_n)])$,
My attempt :
First of all let's suppose that we have $xi $~$Gamma(n,frac1lambda)$ , when $mathbbE(exp[-sxi]) = left(dfraclambdalambda + sright)^n$.
Let's consider $f = sum_k = 1^m a_kmathbb1_B_k$, hence we have :
$mathfrakL(f) = mathbbEexp[-sum_n^infty sum_k^m a_k mathbb1_B_k(S_n)]$ replace sum sign due to positive terms.
$mathfrakL(f) = prod mathbbE exp[-a_k Y(B_k)]$, but there is the stuck problem.
What should I do now?
probability stochastic-processes expected-value
$endgroup$
Consider $X_1 dots $ i.r.v with $Exp(lambda)$ distribution. Let's consider $S_n = X_1 + dots + X_n$.
So we may construct a point process $Y = Y(B) = sum mathbb1_B(S_n) , Bin mathfrakB(mathbbR) $.
No we need to find $mathfrakL(f) = mathbbE(exp[-sum_n f(S_n)])$,
My attempt :
First of all let's suppose that we have $xi $~$Gamma(n,frac1lambda)$ , when $mathbbE(exp[-sxi]) = left(dfraclambdalambda + sright)^n$.
Let's consider $f = sum_k = 1^m a_kmathbb1_B_k$, hence we have :
$mathfrakL(f) = mathbbEexp[-sum_n^infty sum_k^m a_k mathbb1_B_k(S_n)]$ replace sum sign due to positive terms.
$mathfrakL(f) = prod mathbbE exp[-a_k Y(B_k)]$, but there is the stuck problem.
What should I do now?
probability stochastic-processes expected-value
probability stochastic-processes expected-value
asked Mar 17 at 21:31
openspaceopenspace
3,3512822
3,3512822
This question has an open bounty worth +100
reputation from openspace ending ending at 2019-04-03 07:12:38Z">in 6 days.
The question is widely applicable to a large audience. A detailed canonical answer is required to address all the concerns.
This question has an open bounty worth +100
reputation from openspace ending ending at 2019-04-03 07:12:38Z">in 6 days.
The question is widely applicable to a large audience. A detailed canonical answer is required to address all the concerns.
$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago
add a comment |
$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago
$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago
add a comment |
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$begingroup$
What is the domain of f? Is it a generic measurable real function? And where the definition of Y enters in the question?
$endgroup$
– Thomas
21 hours ago
$begingroup$
@Thomas $f$ should be a Borel-function
$endgroup$
– openspace
21 hours ago
$begingroup$
@Thomas I mean Borel-measurable function
$endgroup$
– openspace
21 hours ago
$begingroup$
Thx. What role instead plays Y? It seems that it is not necessary to define the laplace functional? I am asking to be sure that I am getting the problem...
$endgroup$
– Thomas
18 hours ago
$begingroup$
@Thomas Y is a point process.
$endgroup$
– openspace
16 hours ago