Is this a right solution?Linear Algebra: Least-Squares Approximation & “Normal Equation”Approximating the solution of an overdetermined system helpWhy can't two vectors span $Bbb R^3$?Partitioned matrix of partitioned matricesFind a matrix given a span for nullspace and rangeHave do i get 2nd equation from 3 equation 2 variable system answer?Finding a solution when the determinant is zeroFind a vector $winmathbbR^3$ so that $u, v, w$ spans $mathbbR^3$.solving for a matrix A for Ax = 0Which of the following sets of vectors span R^3?
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Is this a right solution?
Linear Algebra: Least-Squares Approximation & “Normal Equation”Approximating the solution of an overdetermined system helpWhy can't two vectors span $Bbb R^3$?Partitioned matrix of partitioned matricesFind a matrix given a span for nullspace and rangeHave do i get 2nd equation from 3 equation 2 variable system answer?Finding a solution when the determinant is zeroFind a vector $winmathbbR^3$ so that $u, v, w$ spans $mathbbR^3$.solving for a matrix A for Ax = 0Which of the following sets of vectors span R^3?
$begingroup$
This is a question in my mock math test. On the square box is the question and below is the answer.
I think that the solution below is wrong, because the 2nd equation should be x1+2x2+2x3 instead of x1+2x2 +2x3.
But if I assume that the equation is correct, I still do not know how do you solve the equation to generate the solution. I thought that the solution for Ax=b is p+nullA, in this case p is (-1 3/2 0) but I don't know what is the A in this case to calculate the null of it, therefore I also do not understand the meaning of span(1 -1 1).
Can anyone explain to me about this answer?
Many thanks.
linear-algebra
edited Mar 28 at 23:07
jgon
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
This is a question in my mock math test. On the square box is the question and below is the answer.
I think that the solution below is wrong, because the 2nd equation should be x1+2x2+2x3 instead of x1+2x2 +2x3.
But if I assume that the equation is correct, I still do not know how do you solve the equation to generate the solution. I thought that the solution for Ax=b is p+nullA, in this case p is (-1 3/2 0) but I don't know what is the A in this case to calculate the null of it, therefore I also do not understand the meaning of span(1 -1 1).
Can anyone explain to me about this answer?
Many thanks.
linear-algebra
edited Mar 28 at 23:07
jgon
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– Mohammad Zuhair Khan
Mar 28 at 16:02
add a comment |
$begingroup$
This is a question in my mock math test. On the square box is the question and below is the answer.
I think that the solution below is wrong, because the 2nd equation should be x1+2x2+2x3 instead of x1+2x2 +2x3.
But if I assume that the equation is correct, I still do not know how do you solve the equation to generate the solution. I thought that the solution for Ax=b is p+nullA, in this case p is (-1 3/2 0) but I don't know what is the A in this case to calculate the null of it, therefore I also do not understand the meaning of span(1 -1 1).
Can anyone explain to me about this answer?
Many thanks.
linear-algebra
edited Mar 28 at 23:07
jgon
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
This is a question in my mock math test. On the square box is the question and below is the answer.
I think that the solution below is wrong, because the 2nd equation should be x1+2x2+2x3 instead of x1+2x2 +2x3.
But if I assume that the equation is correct, I still do not know how do you solve the equation to generate the solution. I thought that the solution for Ax=b is p+nullA, in this case p is (-1 3/2 0) but I don't know what is the A in this case to calculate the null of it, therefore I also do not understand the meaning of span(1 -1 1).
Can anyone explain to me about this answer?
Many thanks.
linear-algebra
linear-algebra
edited Mar 28 at 23:07
jgon
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 28 at 23:07
jgon
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 28 at 23:07
jgon
16.4k32143
edited Mar 28 at 23:07
jgon
16.4k32143
edited Mar 28 at 23:07
jgon
16.4k32143
16.4k32143
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
asked Mar 28 at 15:58
Hung NguyenHung Nguyen
1
1
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hung Nguyen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– Mohammad Zuhair Khan
Mar 28 at 16:02
add a comment |
1
$begingroup$
For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– Mohammad Zuhair Khan
Mar 28 at 16:02
1
1
$begingroup$
For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– Mohammad Zuhair Khan
Mar 28 at 16:02
$begingroup$
For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
$endgroup$
– Mohammad Zuhair Khan
Mar 28 at 16:02
add a comment |
1 Answer
1
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oldest
votes
$begingroup$
First, subtract the third equation from the second one like as follows:
$$(x_1+2x_2+2x_3)-(2x_2+2x_3)=2-3 \ x_1=-1$$
Then,we can find $x_2$ by replacing $x_1$ in the first equation:
$$2x_1+2x_2=1 \ 2(-1)+2x_2=1 \ 2x_2-2=1 \ 2x_2=1+2=3 \ x_2= frac 3 2$$
Finally, using any of the second or the third equation will help in finding $x_3$:
$$2x_2+2x_3=3 \ 2 left( frac 3 2 right)+2x_3=3 \ 2x_3=3-3=0 \ x_3=0$$
That's how you solve the equation, but you asked what "span" means, so I hope you find what you are looking for on this Wikipedia article: Linear span
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
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oldest
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active
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$begingroup$
First, subtract the third equation from the second one like as follows:
$$(x_1+2x_2+2x_3)-(2x_2+2x_3)=2-3 \ x_1=-1$$
Then,we can find $x_2$ by replacing $x_1$ in the first equation:
$$2x_1+2x_2=1 \ 2(-1)+2x_2=1 \ 2x_2-2=1 \ 2x_2=1+2=3 \ x_2= frac 3 2$$
Finally, using any of the second or the third equation will help in finding $x_3$:
$$2x_2+2x_3=3 \ 2 left( frac 3 2 right)+2x_3=3 \ 2x_3=3-3=0 \ x_3=0$$
That's how you solve the equation, but you asked what "span" means, so I hope you find what you are looking for on this Wikipedia article: Linear span
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
$endgroup$
add a comment |
$begingroup$
First, subtract the third equation from the second one like as follows:
$$(x_1+2x_2+2x_3)-(2x_2+2x_3)=2-3 \ x_1=-1$$
Then,we can find $x_2$ by replacing $x_1$ in the first equation:
$$2x_1+2x_2=1 \ 2(-1)+2x_2=1 \ 2x_2-2=1 \ 2x_2=1+2=3 \ x_2= frac 3 2$$
Finally, using any of the second or the third equation will help in finding $x_3$:
$$2x_2+2x_3=3 \ 2 left( frac 3 2 right)+2x_3=3 \ 2x_3=3-3=0 \ x_3=0$$
That's how you solve the equation, but you asked what "span" means, so I hope you find what you are looking for on this Wikipedia article: Linear span
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
$endgroup$
add a comment |
$begingroup$
First, subtract the third equation from the second one like as follows:
$$(x_1+2x_2+2x_3)-(2x_2+2x_3)=2-3 \ x_1=-1$$
Then,we can find $x_2$ by replacing $x_1$ in the first equation:
$$2x_1+2x_2=1 \ 2(-1)+2x_2=1 \ 2x_2-2=1 \ 2x_2=1+2=3 \ x_2= frac 3 2$$
Finally, using any of the second or the third equation will help in finding $x_3$:
$$2x_2+2x_3=3 \ 2 left( frac 3 2 right)+2x_3=3 \ 2x_3=3-3=0 \ x_3=0$$
That's how you solve the equation, but you asked what "span" means, so I hope you find what you are looking for on this Wikipedia article: Linear span
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
$endgroup$
First, subtract the third equation from the second one like as follows:
$$(x_1+2x_2+2x_3)-(2x_2+2x_3)=2-3 \ x_1=-1$$
Then,we can find $x_2$ by replacing $x_1$ in the first equation:
$$2x_1+2x_2=1 \ 2(-1)+2x_2=1 \ 2x_2-2=1 \ 2x_2=1+2=3 \ x_2= frac 3 2$$
Finally, using any of the second or the third equation will help in finding $x_3$:
$$2x_2+2x_3=3 \ 2 left( frac 3 2 right)+2x_3=3 \ 2x_3=3-3=0 \ x_3=0$$
That's how you solve the equation, but you asked what "span" means, so I hope you find what you are looking for on this Wikipedia article: Linear span
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
answered Mar 28 at 17:52
anas pcproanas pcpro
96110
96110
add a comment |
add a comment |
Hung Nguyen is a new contributor. Be nice, and check out our Code of Conduct.
Hung Nguyen is a new contributor. Be nice, and check out our Code of Conduct.
Hung Nguyen is a new contributor. Be nice, and check out our Code of Conduct.
Hung Nguyen is a new contributor. Be nice, and check out our Code of Conduct.
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For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
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– Mohammad Zuhair Khan
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