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10

1

I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:

cd /
find . -name "ABC_MPSC/ABC.jpg"

But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could allow me not have to search manually?

find

share|improve this question

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
  
  – Jeff Schaller♦
  Mar 29 at 18:31
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  You can also find it using locate, which should be significantly faster, but only works if the file already existed when updatedb was last run.
  
  – Simon Richter
  Mar 29 at 20:01
  
  

  
  
  
  

add a comment | 

10

1

I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:

cd /
find . -name "ABC_MPSC/ABC.jpg"

But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could allow me not have to search manually?

find

share|improve this question

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
  
  – Jeff Schaller♦
  Mar 29 at 18:31
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  You can also find it using locate, which should be significantly faster, but only works if the file already existed when updatedb was last run.
  
  – Simon Richter
  Mar 29 at 20:01
  
  

  
  
  
  

add a comment | 

I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:

cd /
find . -name "ABC_MPSC/ABC.jpg"

But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could allow me not have to search manually?

find

share|improve this question

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

cd /
find . -name "ABC_MPSC/ABC.jpg"

share|improve this question

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

share|improve this question

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

edited 7 hours ago

Rui F Ribeiro

42k1483142

edited 7 hours ago

Rui F Ribeiro

42k1483142

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

asked Mar 29 at 18:27

PascLeRascPascLeRasc

1584

2 Answers
2

active

oldest

votes

16

There's a -path predicate that's useful here:

find . -path '*/ABC_MPSC/ABC.jpg'

The POSIX description for that predicate is:

The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.

The reason that your -name "ABC_MPSC/ABC.jpg" failed is because the -name predicate:

shall evaluate as true if the basename of the current pathname matches pattern

In other words, -name never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).

share|improve this answer

edited Mar 29 at 18:40

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

add a comment | 

9

Two ways (apart from using -path):

1. 
   

   Look for the directory, then detect the file:

   
   
   

   find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
   

   
   
   

   This relies on the find implementation to expand to the current pathname of the found directory, even though it's concatenated with /ABC.jpg (it's not required to do that). It could also be written as

   
   
   

   find / -type d -name 'ABC_MPSC' 
    -exec sh -c 'test -f "$1"/ABC.jpg' sh ; -print
   

   
   


2. 
   

   Look for the file, then check it's parent directory name:

   
   
   

   find / -type f -name 'ABC.jpg' -exec sh -c '
    case $(dirname "$1") in
    */ABC_MPSC) exit 0 ;;
    *) exit 1
    esac' sh ; -print
   

   
   

Both of these alternatives would be slower than using -path in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.

share|improve this answer

edited Mar 29 at 23:34

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

add a comment | 

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16

There's a -path predicate that's useful here:

find . -path '*/ABC_MPSC/ABC.jpg'

The POSIX description for that predicate is:

The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.

The reason that your -name "ABC_MPSC/ABC.jpg" failed is because the -name predicate:

shall evaluate as true if the basename of the current pathname matches pattern

In other words, -name never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).

share|improve this answer

edited Mar 29 at 18:40

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

add a comment | 

16

There's a -path predicate that's useful here:

find . -path '*/ABC_MPSC/ABC.jpg'

The POSIX description for that predicate is:

The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.

The reason that your -name "ABC_MPSC/ABC.jpg" failed is because the -name predicate:

shall evaluate as true if the basename of the current pathname matches pattern

In other words, -name never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).

share|improve this answer

edited Mar 29 at 18:40

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

add a comment | 

There's a -path predicate that's useful here:

find . -path '*/ABC_MPSC/ABC.jpg'

The POSIX description for that predicate is:

The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.

The reason that your -name "ABC_MPSC/ABC.jpg" failed is because the -name predicate:

shall evaluate as true if the basename of the current pathname matches pattern

In other words, -name never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).

share|improve this answer

edited Mar 29 at 18:40

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

find . -path '*/ABC_MPSC/ABC.jpg'

share|improve this answer

edited Mar 29 at 18:40

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

answered Mar 29 at 18:30

Jeff Schaller♦Jeff Schaller

44.7k1163145

9

Two ways (apart from using -path):

1. 
   

   Look for the directory, then detect the file:

   
   
   

   find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
   

   
   
   

   This relies on the find implementation to expand to the current pathname of the found directory, even though it's concatenated with /ABC.jpg (it's not required to do that). It could also be written as

   
   
   

   find / -type d -name 'ABC_MPSC' 
    -exec sh -c 'test -f "$1"/ABC.jpg' sh ; -print
   

   
   


2. 
   

   Look for the file, then check it's parent directory name:

   
   
   

   find / -type f -name 'ABC.jpg' -exec sh -c '
    case $(dirname "$1") in
    */ABC_MPSC) exit 0 ;;
    *) exit 1
    esac' sh ; -print
   

   
   

Both of these alternatives would be slower than using -path in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.

share|improve this answer

edited Mar 29 at 23:34

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

add a comment | 

9

Two ways (apart from using -path):

1. 
   

   Look for the directory, then detect the file:

   
   
   

   find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
   

   
   
   

   This relies on the find implementation to expand to the current pathname of the found directory, even though it's concatenated with /ABC.jpg (it's not required to do that). It could also be written as

   
   
   

   find / -type d -name 'ABC_MPSC' 
    -exec sh -c 'test -f "$1"/ABC.jpg' sh ; -print
   

   
   


2. 
   

   Look for the file, then check it's parent directory name:

   
   
   

   find / -type f -name 'ABC.jpg' -exec sh -c '
    case $(dirname "$1") in
    */ABC_MPSC) exit 0 ;;
    *) exit 1
    esac' sh ; -print
   

   
   

Both of these alternatives would be slower than using -path in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.

share|improve this answer

edited Mar 29 at 23:34

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

add a comment | 

Two ways (apart from using -path):

1. 
   

   Look for the directory, then detect the file:

   
   
   

   find / -type d -name 'ABC_MPSC' -exec test -f /ABC.jpg ; -print
   

   
   
   

   This relies on the find implementation to expand to the current pathname of the found directory, even though it's concatenated with /ABC.jpg (it's not required to do that). It could also be written as

   
   
   

   find / -type d -name 'ABC_MPSC' 
    -exec sh -c 'test -f "$1"/ABC.jpg' sh ; -print
   

   
   


2. 
   

   Look for the file, then check it's parent directory name:

   
   
   

   find / -type f -name 'ABC.jpg' -exec sh -c '
    case $(dirname "$1") in
    */ABC_MPSC) exit 0 ;;
    *) exit 1
    esac' sh ; -print
   

   
   

Both of these alternatives would be slower than using -path in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.

share|improve this answer

edited Mar 29 at 23:34

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

share|improve this answer

edited Mar 29 at 23:34

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435

answered Mar 29 at 18:37

Kusalananda♦Kusalananda

140k17261435