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What is the “natural” smooth structure on the subsets of $mathbbR^n$ that are topological manifolds?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)Smooth structure on the topological spaceAn example of a smooth map between manifolds that is a topological embedding, but is NOT a smooth embedding.Smooth functions between manifolds and subsets of manifoldsAre topological manifolds with boundary metrizable?topological structure on smooth manifoldsTopological embedding and smooth structureHow can I see that the product smooth manifold structure is a maximal atlas?Let $θ$ be a smooth flow on an oriented smooth manifold $M$. Show that for every $tin mathbbR$, $θ_t: M to M$ is orientation-preserving.Definition of smooth manifolds: What is the difference between differentiable structures and smooth structures?Book for manifolds that are used in scientific computation










0












$begingroup$


Most of the differential topology book describe a manifold that is a subset of $mathbbR^n$ and without describing the smooth structure, they talk about their properties as smooth manifolds, such as a square which is mentioned in a question in Lee's book on p75.



What is the "natural" smooth structure on the subsets of $mathbbR^n$ that are topological manifolds ? Can you explicitly specify it ?



For example, if we were talking about the "natural" topology on the subsets of $mathbbR^n$, it would be the topology generated by the basis whose elements are the intersection of open balls with that subset; so now the topic is about smooth structure on those topological manifolds.










share|cite|improve this question









$endgroup$











  • $begingroup$
    Do you possibly mean open subsets of $mathbb R^n$?
    $endgroup$
    – lush
    Apr 2 at 8:28










  • $begingroup$
    @lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
    $endgroup$
    – onurcanbektas
    Apr 2 at 8:41










  • $begingroup$
    @onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
    $endgroup$
    – levap
    Apr 2 at 13:11











  • $begingroup$
    @levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
    $endgroup$
    – onurcanbektas
    Apr 2 at 18:20










  • $begingroup$
    @onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
    $endgroup$
    – levap
    Apr 3 at 10:11
















0












$begingroup$


Most of the differential topology book describe a manifold that is a subset of $mathbbR^n$ and without describing the smooth structure, they talk about their properties as smooth manifolds, such as a square which is mentioned in a question in Lee's book on p75.



What is the "natural" smooth structure on the subsets of $mathbbR^n$ that are topological manifolds ? Can you explicitly specify it ?



For example, if we were talking about the "natural" topology on the subsets of $mathbbR^n$, it would be the topology generated by the basis whose elements are the intersection of open balls with that subset; so now the topic is about smooth structure on those topological manifolds.










share|cite|improve this question









$endgroup$











  • $begingroup$
    Do you possibly mean open subsets of $mathbb R^n$?
    $endgroup$
    – lush
    Apr 2 at 8:28










  • $begingroup$
    @lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
    $endgroup$
    – onurcanbektas
    Apr 2 at 8:41










  • $begingroup$
    @onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
    $endgroup$
    – levap
    Apr 2 at 13:11











  • $begingroup$
    @levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
    $endgroup$
    – onurcanbektas
    Apr 2 at 18:20










  • $begingroup$
    @onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
    $endgroup$
    – levap
    Apr 3 at 10:11














0












0








0





$begingroup$


Most of the differential topology book describe a manifold that is a subset of $mathbbR^n$ and without describing the smooth structure, they talk about their properties as smooth manifolds, such as a square which is mentioned in a question in Lee's book on p75.



What is the "natural" smooth structure on the subsets of $mathbbR^n$ that are topological manifolds ? Can you explicitly specify it ?



For example, if we were talking about the "natural" topology on the subsets of $mathbbR^n$, it would be the topology generated by the basis whose elements are the intersection of open balls with that subset; so now the topic is about smooth structure on those topological manifolds.










share|cite|improve this question









$endgroup$




Most of the differential topology book describe a manifold that is a subset of $mathbbR^n$ and without describing the smooth structure, they talk about their properties as smooth manifolds, such as a square which is mentioned in a question in Lee's book on p75.



What is the "natural" smooth structure on the subsets of $mathbbR^n$ that are topological manifolds ? Can you explicitly specify it ?



For example, if we were talking about the "natural" topology on the subsets of $mathbbR^n$, it would be the topology generated by the basis whose elements are the intersection of open balls with that subset; so now the topic is about smooth structure on those topological manifolds.







manifolds smooth-manifolds






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Apr 2 at 8:01









onurcanbektasonurcanbektas

3,50211037




3,50211037











  • $begingroup$
    Do you possibly mean open subsets of $mathbb R^n$?
    $endgroup$
    – lush
    Apr 2 at 8:28










  • $begingroup$
    @lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
    $endgroup$
    – onurcanbektas
    Apr 2 at 8:41










  • $begingroup$
    @onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
    $endgroup$
    – levap
    Apr 2 at 13:11











  • $begingroup$
    @levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
    $endgroup$
    – onurcanbektas
    Apr 2 at 18:20










  • $begingroup$
    @onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
    $endgroup$
    – levap
    Apr 3 at 10:11

















  • $begingroup$
    Do you possibly mean open subsets of $mathbb R^n$?
    $endgroup$
    – lush
    Apr 2 at 8:28










  • $begingroup$
    @lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
    $endgroup$
    – onurcanbektas
    Apr 2 at 8:41










  • $begingroup$
    @onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
    $endgroup$
    – levap
    Apr 2 at 13:11











  • $begingroup$
    @levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
    $endgroup$
    – onurcanbektas
    Apr 2 at 18:20










  • $begingroup$
    @onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
    $endgroup$
    – levap
    Apr 3 at 10:11
















$begingroup$
Do you possibly mean open subsets of $mathbb R^n$?
$endgroup$
– lush
Apr 2 at 8:28




$begingroup$
Do you possibly mean open subsets of $mathbb R^n$?
$endgroup$
– lush
Apr 2 at 8:28












$begingroup$
@lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
$endgroup$
– onurcanbektas
Apr 2 at 8:41




$begingroup$
@lush No. I'm asking specifially the closed subsets of $mathbbR^n$, such as square.
$endgroup$
– onurcanbektas
Apr 2 at 8:41












$begingroup$
@onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
$endgroup$
– levap
Apr 2 at 13:11





$begingroup$
@onurcanbektas: Note that the question in Lee's book doesn't treat the square as a smooth manifold or something which has smooth structure (although this is possible in the context of manifolds with corners). It asks about a diffeomorphism of the ambient space $mathbbR^2$ which maps a certain subset to another subset.
$endgroup$
– levap
Apr 2 at 13:11













$begingroup$
@levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
$endgroup$
– onurcanbektas
Apr 2 at 18:20




$begingroup$
@levap To be able to diffeomorphism, do we not need spaces to be smooth manifolds ? After all, diffeomorphisms should preserve the smooth structure ?
$endgroup$
– onurcanbektas
Apr 2 at 18:20












$begingroup$
@onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
$endgroup$
– levap
Apr 3 at 10:11





$begingroup$
@onurcanbektas: You do, but the question asks to show that there is no diffeomorphism from $mathbbR^2$ to $mathbbR^2$ (which has a natural smooth structure) which maps a set $A subseteq mathbbR^2$ (circle) to a set $B subseteq mathbbR^2$ (boundary of a square). This is a legitimate question to ask for any two subsets of $mathbbR^2$, you don't need to endow them with a topology or a smooth structure.
$endgroup$
– levap
Apr 3 at 10:11











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