Best way to load image from list python script2019 Community Moderator Election Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) 2019 Moderator Election Q&A - QuestionnaireSave image as for example .png by a scriptHow to get all images for an image sequence? (from Python)3D tool add-on window locks/freezes when importing an image with PythonI can't load an image from a scriptBest way to get a list of modifiers in Python?in python load blender file & delete objectsLoading an image to a texture from a python script filePython UI: How to load an image from drive and select it?Load camera track from an external file (by Python script)Load images with substring in filename from a given path
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Best way to load image from list python script
2019 Community Moderator Election
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
2019 Moderator Election Q&A - QuestionnaireSave image as for example .png by a scriptHow to get all images for an image sequence? (from Python)3D tool add-on window locks/freezes when importing an image with PythonI can't load an image from a scriptBest way to get a list of modifiers in Python?in python load blender file & delete objectsLoading an image to a texture from a python script filePython UI: How to load an image from drive and select it?Load camera track from an external file (by Python script)Load images with substring in filename from a given path
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
For some reason i have append images , now i want load all image by step.
image_path = C:
image_list= []
for fn in os.listdir(image_path):
image_list.append(fn)
###first_image = bpy.data.images.load(image_list[0]) <----?
###second_image = bpy.data.images.load(image_list[1]) <----?
python
$endgroup$
add a comment |
$begingroup$
For some reason i have append images , now i want load all image by step.
image_path = C:
image_list= []
for fn in os.listdir(image_path):
image_list.append(fn)
###first_image = bpy.data.images.load(image_list[0]) <----?
###second_image = bpy.data.images.load(image_list[1]) <----?
python
$endgroup$
add a comment |
$begingroup$
For some reason i have append images , now i want load all image by step.
image_path = C:
image_list= []
for fn in os.listdir(image_path):
image_list.append(fn)
###first_image = bpy.data.images.load(image_list[0]) <----?
###second_image = bpy.data.images.load(image_list[1]) <----?
python
$endgroup$
For some reason i have append images , now i want load all image by step.
image_path = C:
image_list= []
for fn in os.listdir(image_path):
image_list.append(fn)
###first_image = bpy.data.images.load(image_list[0]) <----?
###second_image = bpy.data.images.load(image_list[1]) <----?
python
python
edited Apr 2 at 8:54
Andrea
asked Apr 2 at 8:20
AndreaAndrea
6019
6019
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Try this to batch load a list of images in a folder:
import bpy
from os.path import join, isfile
from os import listdir
imageObjects = []
imagePath = '/users/you/yourImagePath'
imgFiles = [
join( imagePath, fn ) # Create full paths to images
for fn in listdir( imagePath ) # For each item in the image folder
if isfile( join( imagePath, fn ) ) # If the item is indeed a file
and fn.lower().endswith(('.png','.jpg')) # Which ends with an image suffix (can add more types here if needed)
]
# Load entire list of images
for imgFile in imgFiles:
# Add to image object list to use later
imageObjects.append( bpy.data.images.load( imgFile ) )
# Load a specific index from the list (5th in the list in this example)
imgObj = bpy.data.images.load( imgFiles[4] )
$endgroup$
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
$begingroup$
try to replace the imports from os.path and addbasename
. Like this:from os.path import join, isfile, basename
. Then use it in the diffuse.name:diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.
$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try this to batch load a list of images in a folder:
import bpy
from os.path import join, isfile
from os import listdir
imageObjects = []
imagePath = '/users/you/yourImagePath'
imgFiles = [
join( imagePath, fn ) # Create full paths to images
for fn in listdir( imagePath ) # For each item in the image folder
if isfile( join( imagePath, fn ) ) # If the item is indeed a file
and fn.lower().endswith(('.png','.jpg')) # Which ends with an image suffix (can add more types here if needed)
]
# Load entire list of images
for imgFile in imgFiles:
# Add to image object list to use later
imageObjects.append( bpy.data.images.load( imgFile ) )
# Load a specific index from the list (5th in the list in this example)
imgObj = bpy.data.images.load( imgFiles[4] )
$endgroup$
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
$begingroup$
try to replace the imports from os.path and addbasename
. Like this:from os.path import join, isfile, basename
. Then use it in the diffuse.name:diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.
$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
add a comment |
$begingroup$
Try this to batch load a list of images in a folder:
import bpy
from os.path import join, isfile
from os import listdir
imageObjects = []
imagePath = '/users/you/yourImagePath'
imgFiles = [
join( imagePath, fn ) # Create full paths to images
for fn in listdir( imagePath ) # For each item in the image folder
if isfile( join( imagePath, fn ) ) # If the item is indeed a file
and fn.lower().endswith(('.png','.jpg')) # Which ends with an image suffix (can add more types here if needed)
]
# Load entire list of images
for imgFile in imgFiles:
# Add to image object list to use later
imageObjects.append( bpy.data.images.load( imgFile ) )
# Load a specific index from the list (5th in the list in this example)
imgObj = bpy.data.images.load( imgFiles[4] )
$endgroup$
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
$begingroup$
try to replace the imports from os.path and addbasename
. Like this:from os.path import join, isfile, basename
. Then use it in the diffuse.name:diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.
$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
add a comment |
$begingroup$
Try this to batch load a list of images in a folder:
import bpy
from os.path import join, isfile
from os import listdir
imageObjects = []
imagePath = '/users/you/yourImagePath'
imgFiles = [
join( imagePath, fn ) # Create full paths to images
for fn in listdir( imagePath ) # For each item in the image folder
if isfile( join( imagePath, fn ) ) # If the item is indeed a file
and fn.lower().endswith(('.png','.jpg')) # Which ends with an image suffix (can add more types here if needed)
]
# Load entire list of images
for imgFile in imgFiles:
# Add to image object list to use later
imageObjects.append( bpy.data.images.load( imgFile ) )
# Load a specific index from the list (5th in the list in this example)
imgObj = bpy.data.images.load( imgFiles[4] )
$endgroup$
Try this to batch load a list of images in a folder:
import bpy
from os.path import join, isfile
from os import listdir
imageObjects = []
imagePath = '/users/you/yourImagePath'
imgFiles = [
join( imagePath, fn ) # Create full paths to images
for fn in listdir( imagePath ) # For each item in the image folder
if isfile( join( imagePath, fn ) ) # If the item is indeed a file
and fn.lower().endswith(('.png','.jpg')) # Which ends with an image suffix (can add more types here if needed)
]
# Load entire list of images
for imgFile in imgFiles:
# Add to image object list to use later
imageObjects.append( bpy.data.images.load( imgFile ) )
# Load a specific index from the list (5th in the list in this example)
imgObj = bpy.data.images.load( imgFiles[4] )
edited Apr 2 at 8:56
answered Apr 2 at 8:41
TLouskyTLousky
12.3k11951
12.3k11951
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
$begingroup$
try to replace the imports from os.path and addbasename
. Like this:from os.path import join, isfile, basename
. Then use it in the diffuse.name:diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.
$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
add a comment |
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
$begingroup$
try to replace the imports from os.path and addbasename
. Like this:from os.path import join, isfile, basename
. Then use it in the diffuse.name:diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.
$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
$begingroup$
ty but i have to load not full image list because have some variable by controlling the loading , i have to know the way by load single image from list. for example the first image of the list and in the second step , load second image.
$endgroup$
– Andrea
Apr 2 at 8:48
1
1
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
@Andrea see edit and LMK if this is what you meant
$endgroup$
– TLousky
Apr 2 at 8:57
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
$begingroup$
Sorry @TLousky in the first time i put name of node with diffuse = nodes.new(type='ShaderNodeTexImage') diffuse.location = (-600,550) diffuse.name = imgFiles[0] now name is all path of image.. in the first time is only image name. an idea?
$endgroup$
– Andrea
Apr 2 at 9:25
1
1
$begingroup$
try to replace the imports from os.path and add
basename
. Like this: from os.path import join, isfile, basename
. Then use it in the diffuse.name: diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
try to replace the imports from os.path and add
basename
. Like this: from os.path import join, isfile, basename
. Then use it in the diffuse.name: diffuse.name = basename(imgFiles[0])
. Basename extracts the filename from a full path.$endgroup$
– TLousky
Apr 2 at 9:34
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
$begingroup$
Work very fine is very usefull, ty
$endgroup$
– Andrea
Apr 2 at 9:41
add a comment |
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