Interval of Convergence on a single point Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Finding the interval convergence power series?Interval of convergence of a power series, with a check for convergence at endpointsConvergence of series of the form $sum 1/n^x$find interval of convergence for power series of the following functionFind the radius of convergence and interval of convergence of the seriesRadius and Interval of Convergence $sum_n=0^inftyfrac7^nn!x^n$Calculus 2 infinite series $frac13n + 2cos n$Radius of Convergence of a sparse Power SeriesWhat does the interval of convergence mean for this power series?What is the interval of convergence for power series
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Interval of Convergence on a single point
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Finding the interval convergence power series?Interval of convergence of a power series, with a check for convergence at endpointsConvergence of series of the form $sum 1/n^x$find interval of convergence for power series of the following functionFind the radius of convergence and interval of convergence of the seriesRadius and Interval of Convergence $sum_n=0^inftyfrac7^nn!x^n$Calculus 2 infinite series $frac13n + 2cos n$Radius of Convergence of a sparse Power SeriesWhat does the interval of convergence mean for this power series?What is the interval of convergence for power series
$begingroup$
I was wondering why this series has a single point for the interval of convergence of 7?
Question: power series from one to infinity: $sum_n=1^infty n!(x-7)^n$
After applying the ratio test,I know that I can factor out $x-7$ from the limit and that the limit of $(n+1)$ goes infinity meaning that it would diverge.
calculus
edited Mar 31 at 18:15
Max
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
$endgroup$
add a comment |
$begingroup$
I was wondering why this series has a single point for the interval of convergence of 7?
Question: power series from one to infinity: $sum_n=1^infty n!(x-7)^n$
After applying the ratio test,I know that I can factor out $x-7$ from the limit and that the limit of $(n+1)$ goes infinity meaning that it would diverge.
calculus
edited Mar 31 at 18:15
Max
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
$endgroup$
1
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07
add a comment |
$begingroup$
I was wondering why this series has a single point for the interval of convergence of 7?
Question: power series from one to infinity: $sum_n=1^infty n!(x-7)^n$
After applying the ratio test,I know that I can factor out $x-7$ from the limit and that the limit of $(n+1)$ goes infinity meaning that it would diverge.
calculus
edited Mar 31 at 18:15
Max
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
$endgroup$
I was wondering why this series has a single point for the interval of convergence of 7?
Question: power series from one to infinity: $sum_n=1^infty n!(x-7)^n$
After applying the ratio test,I know that I can factor out $x-7$ from the limit and that the limit of $(n+1)$ goes infinity meaning that it would diverge.
calculus
calculus
edited Mar 31 at 18:15
Max
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
edited Mar 31 at 18:15
Max
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
edited Mar 31 at 18:15
Max
1,0061319
edited Mar 31 at 18:15
Max
1,0061319
edited Mar 31 at 18:15
Max
1,0061319
1,0061319
asked Mar 31 at 18:00
MCCMCC
368
asked Mar 31 at 18:00
MCCMCC
368
asked Mar 31 at 18:00
MCCMCC
368
368
1
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07
add a comment |
1
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07
1
1
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07
add a comment |
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1
$begingroup$
At $x = 7$, the sum is 0 since $a_n = n!(7 - 7)^n = 0$
$endgroup$
– Andrew Li
Mar 31 at 18:02
$begingroup$
Hint: you can factor out $x-7$ unless...
$endgroup$
– Yves Daoust
Mar 31 at 18:17
$begingroup$
Are you asking why is $7$ a point of convergence or why other points are not?
$endgroup$
– copper.hat
Mar 31 at 18:36
$begingroup$
@copper.hat yes, usually its an interval of convergence which implies that it should be more then one value?
$endgroup$
– MCC
Mar 31 at 20:28
$begingroup$
It is not of much use if the ROC is zero...
$endgroup$
– copper.hat
Mar 31 at 21:07