Nash equilibrium in Cournot competition Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Cournot Nash Equilibrium Between Two FirmsCournot-Nash Equilibrium in DuopolyNash Equilibrium in Cournot DuopolyCournot Duopoly Game - Nash equilibriumCournot Oligopoly in Bayesian Game TheoryCournot competition: profit maximizer vs. market share maximizerGame Theory- Bertrand ProblemCournot Price Competition setupFinding the equilibrium production quantity of each firmSubgame perfect equilibrium question
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Nash equilibrium in Cournot competition
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Cournot Nash Equilibrium Between Two FirmsCournot-Nash Equilibrium in DuopolyNash Equilibrium in Cournot DuopolyCournot Duopoly Game - Nash equilibriumCournot Oligopoly in Bayesian Game TheoryCournot competition: profit maximizer vs. market share maximizerGame Theory- Bertrand ProblemCournot Price Competition setupFinding the equilibrium production quantity of each firmSubgame perfect equilibrium question
$begingroup$
QUESTION:
Assume there are two types of products, labelled $l$ and $n$. Firms compete in the market by choosing which product to sell and then choosing the quantities. Let $Q_n$ and $Q_l$ denote the total demand of product $n$ and $l$, respectively. Let the inverse demand functions be given by:
beginalign*
& P_l(Q_l, Q_n) = (a+gamma) - Q_n - (1+delta)Q_l \
& P_n(Q_l, Q_n) = a - Q_n - Q_l
endalign*
where $P_l$ and $P_n$ denote the prices of product $l$ and $n$, respectively, and $a$, $gamma$, $delta$ are all constants greater than zero. Let $q_l^i$ and $q_n^i$ denote the $i$th firm's output of product $l$ and $n$, respectively. Let $X_l^i$ and $X_n^i$ denote the output of the other firms producing product $l$ and $n$, respectively. Let $N_n$ and $N_l$ denote the number of firms selling product $n$ and $l$, respectively. Let the marginal cost of producing the $l$ product be $c_n + c_p$ and the marginal cost of producing the $n$ product be $c_n$. Find all the sub-game perfect Nash equilibria in this game.
My working so far:
I have almost solved the question but I am stuck towards the end of my working. What I've done so far is as follows. First, fix the number of firms selling each product and solve for the equilibrium quantity choices. Then, we can solve for the equilibrium number of firms making each product.
A firm choosing to sell the $l$ product earns profits:
$$pi_l = (P_l - c_n - c_p)q_l^i cdots (1) $$
while a firm choosing to sell the $n$ product earns profits:
$$pi_n = (P_n - c_n )q_n^i cdots (2) $$
Noting that $Q_l = q_l^i + X_l^i$ and $Q_n = q_n^i + X_n^i$ and substituting into the above and then taking first-order conditions with respect to $q_l^i$ (for $(1)$) and $q_n^i$ (for $(2)$), respectively, yields:
beginalign*
& (a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p) - 2(1+delta)q_l^i = 0 cdots (1') \
& a - X_n^i - Q_l - c_n - 2q_n^i =0 cdots (2')
endalign*
From $(1')$, the best response function of a firm choosing to sell $q_l^i$ of product $l$ is given by
$$q_l^i = frac(a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p)2(1+delta) $$
but noting that $X_l^i = Q_l - q_l^i$, we have
$$q_l^i = frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+delta cdots (3) $$.
From $(2')$, the best response function of a firm choosing to sell $q_n^i$ of product $n$ is given by
$$q_n^i = fraca-X_n^i - Q_l - c_n2 $$
but noting that $X_n^i = Q_n - q_n^i$, we have
$$q_n^i = a-Q_n-Q_l-c_n cdots (4)$$.
Since the right-hand sides of $(3)$ and $(4)$ are constants, the first-order conditions imply that firms making the same product produce the same quantity in equilibrium. Since there are $N_n$ firms making $n$ and $N_l$ firms making $l$, therefore:
beginalign*
& Q_l = N_lq_l^i \
& Q_n = N_nq_n^i.
endalign*
Substituting in $(3)$ and $(4)$ we have the following:
beginalign*
& Q_l = N_lleft(frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+deltaright) cdots (5) \
& Q_n = N_nleft(a-Q_n-Q_l-c_nright) cdots (6)
endalign*
Solving $(5)$ and $(6)$ simultaneously for $Q_l$ and $Q_n$, we obtain the total sales of each product (with each firm selling a given product, selling the same amount):
beginalign*
& Q_l(N_l, N_n) = lambda N_lleft((N_n+1)(a + gamma - c_n - c_p) - N_n(a-c_n) right) cdots (7) \
& Q_n(N_l, N_n) = lambda N_nleft((1+delta)(N_l+1)(a-c_n) - N_l(a+gamma - c_n - c_p) right) cdots (8)
endalign*
where
$$lambda = frac1(1+delta)(N_l+1)(N_n+1) - N_lN_n $$. Therefore in equilibrium, the quantities chosen by firms selling $l$ and $n$ are, respectively:
beginalign*
& q_l(N_l, N_n) = fracQ_l(N_l, N_n)N_l \
& q_n(N_l, N_n) = fracQ_n(N_l, N_n)N_n
endalign*
To find the sub-game perfect Nash equilibrium, we need an additional property, that is, no firm can have an incentive to switch and produce the other product. The profits of firms producing $l$ and $n$, respectively, are given by
beginalign*
& pi_l^i(N_l, N_n) = left[a+gamma - Q_n(N_l, N_n) - (1+delta)Q_l(N_l, N_n) - c_n - c_p right]q_l(N_l, N_n) \
& pi_n^i(N_l, N_n) = left[a - Q_n(N_l, N_n) - Q_l(N_l, N_n) - c_n right]q_n(N_l, N_n).
endalign*
One can show that $pi_l^i(N_l, N_n)$ is decreasing in $N_l$ and $pi_n^i(N_l, N_n)$ is decreasing in $N_n$. Let $N = N_l + N_n$ denote the total firms in the market, then two types of equilibria can be summarized as follows:
- If $pi_l(1, N-1) < pi_n(0, N)$, each of the $N$ firms sells $q_n^* = Q_n(0,N)/N$ of product $n$ where $Q_n$ satisfies $(8)$ and no firms sell product $l$.
- If $pi_n(N-1, 1) < pi_l(N, 0)$, each of the $N$ firms sells $q_l^* = Q_l(N,0)/N$ of product $l$ where $Q_l$ satisfies $(7)$ and no firms sell product $n$.
The intuition behind equilibrium listed in 1. above is simple to see. If $pi_l(1, N-1) < pi_n(0, N)$, then we have
$$underbracepi_l(N,0) < cdots < pi_l(1, N-1)_textSince pi_l^i(N_l, N_n) textis decreasing in N_l < underbracepi_n(0, N) < cdots < pi_n(N-1, 1)_textSince pi_n^i(N_l, N_n) textis decreasing in N_n $$
Therefore, in equilibrium, any firm that is producing $l$ are strictly better off by deviating to producing $n$, so every firm will produce $n$ in equilibrium. The intuition for 2. is similar.
Where I am stuck:
I am told that there is another equilibrium which is characterized as:
If the number of firms in the market and the parameter values are such that the monopoly profits from selling one product exceed the Cournot profits if all firms sell the other product, then, ignoring integer problems, equilibrium is found by setting the profits from selling the two products equal and so $N_l^*$ and $N_n^*$ satisfy
$$
(1+delta)(N_l^* + 1)(a - c_n)^2left[(1+delta)(N_l^*+1)(N-N_l^* + 1) - (N-N_l^*)^2 right] = (N-N_l^* +1)(a+gamma - c_n - c_p)^2left[(1+delta)(N-N_l^*+1)(N_l^*+1) - (N_l^*)^2 right] cdots (9) $$
$$ N_n^* = N - N_l^* cdots (10) $$
If $pi_l(1, N-1) ge pi_n(0, N)$ and $pi_n(N-1, 1) ge pi_l(N, 0)$, then $N_l^*$ firms sell $q_l^* = Q_l(N_l^*, N_n^*)/N_l^*$ of $l$; $N_n^*$ sell $q_n^* = Q_n(N_l^*, N_n^*)/N_n^*$ of $n$ when equations (7), (8), (9), and (10) are satisfied.
What is the reasoning behind this equilibrium? Specifically, how do Equations (9) and (10) come about? And what exactly are $N_n^*$ and $N_l^*$ and how do they come about in the construction of the equilibrium?
game-theory economics nash-equilibrium
$endgroup$
add a comment |
$begingroup$
QUESTION:
Assume there are two types of products, labelled $l$ and $n$. Firms compete in the market by choosing which product to sell and then choosing the quantities. Let $Q_n$ and $Q_l$ denote the total demand of product $n$ and $l$, respectively. Let the inverse demand functions be given by:
beginalign*
& P_l(Q_l, Q_n) = (a+gamma) - Q_n - (1+delta)Q_l \
& P_n(Q_l, Q_n) = a - Q_n - Q_l
endalign*
where $P_l$ and $P_n$ denote the prices of product $l$ and $n$, respectively, and $a$, $gamma$, $delta$ are all constants greater than zero. Let $q_l^i$ and $q_n^i$ denote the $i$th firm's output of product $l$ and $n$, respectively. Let $X_l^i$ and $X_n^i$ denote the output of the other firms producing product $l$ and $n$, respectively. Let $N_n$ and $N_l$ denote the number of firms selling product $n$ and $l$, respectively. Let the marginal cost of producing the $l$ product be $c_n + c_p$ and the marginal cost of producing the $n$ product be $c_n$. Find all the sub-game perfect Nash equilibria in this game.
My working so far:
I have almost solved the question but I am stuck towards the end of my working. What I've done so far is as follows. First, fix the number of firms selling each product and solve for the equilibrium quantity choices. Then, we can solve for the equilibrium number of firms making each product.
A firm choosing to sell the $l$ product earns profits:
$$pi_l = (P_l - c_n - c_p)q_l^i cdots (1) $$
while a firm choosing to sell the $n$ product earns profits:
$$pi_n = (P_n - c_n )q_n^i cdots (2) $$
Noting that $Q_l = q_l^i + X_l^i$ and $Q_n = q_n^i + X_n^i$ and substituting into the above and then taking first-order conditions with respect to $q_l^i$ (for $(1)$) and $q_n^i$ (for $(2)$), respectively, yields:
beginalign*
& (a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p) - 2(1+delta)q_l^i = 0 cdots (1') \
& a - X_n^i - Q_l - c_n - 2q_n^i =0 cdots (2')
endalign*
From $(1')$, the best response function of a firm choosing to sell $q_l^i$ of product $l$ is given by
$$q_l^i = frac(a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p)2(1+delta) $$
but noting that $X_l^i = Q_l - q_l^i$, we have
$$q_l^i = frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+delta cdots (3) $$.
From $(2')$, the best response function of a firm choosing to sell $q_n^i$ of product $n$ is given by
$$q_n^i = fraca-X_n^i - Q_l - c_n2 $$
but noting that $X_n^i = Q_n - q_n^i$, we have
$$q_n^i = a-Q_n-Q_l-c_n cdots (4)$$.
Since the right-hand sides of $(3)$ and $(4)$ are constants, the first-order conditions imply that firms making the same product produce the same quantity in equilibrium. Since there are $N_n$ firms making $n$ and $N_l$ firms making $l$, therefore:
beginalign*
& Q_l = N_lq_l^i \
& Q_n = N_nq_n^i.
endalign*
Substituting in $(3)$ and $(4)$ we have the following:
beginalign*
& Q_l = N_lleft(frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+deltaright) cdots (5) \
& Q_n = N_nleft(a-Q_n-Q_l-c_nright) cdots (6)
endalign*
Solving $(5)$ and $(6)$ simultaneously for $Q_l$ and $Q_n$, we obtain the total sales of each product (with each firm selling a given product, selling the same amount):
beginalign*
& Q_l(N_l, N_n) = lambda N_lleft((N_n+1)(a + gamma - c_n - c_p) - N_n(a-c_n) right) cdots (7) \
& Q_n(N_l, N_n) = lambda N_nleft((1+delta)(N_l+1)(a-c_n) - N_l(a+gamma - c_n - c_p) right) cdots (8)
endalign*
where
$$lambda = frac1(1+delta)(N_l+1)(N_n+1) - N_lN_n $$. Therefore in equilibrium, the quantities chosen by firms selling $l$ and $n$ are, respectively:
beginalign*
& q_l(N_l, N_n) = fracQ_l(N_l, N_n)N_l \
& q_n(N_l, N_n) = fracQ_n(N_l, N_n)N_n
endalign*
To find the sub-game perfect Nash equilibrium, we need an additional property, that is, no firm can have an incentive to switch and produce the other product. The profits of firms producing $l$ and $n$, respectively, are given by
beginalign*
& pi_l^i(N_l, N_n) = left[a+gamma - Q_n(N_l, N_n) - (1+delta)Q_l(N_l, N_n) - c_n - c_p right]q_l(N_l, N_n) \
& pi_n^i(N_l, N_n) = left[a - Q_n(N_l, N_n) - Q_l(N_l, N_n) - c_n right]q_n(N_l, N_n).
endalign*
One can show that $pi_l^i(N_l, N_n)$ is decreasing in $N_l$ and $pi_n^i(N_l, N_n)$ is decreasing in $N_n$. Let $N = N_l + N_n$ denote the total firms in the market, then two types of equilibria can be summarized as follows:
- If $pi_l(1, N-1) < pi_n(0, N)$, each of the $N$ firms sells $q_n^* = Q_n(0,N)/N$ of product $n$ where $Q_n$ satisfies $(8)$ and no firms sell product $l$.
- If $pi_n(N-1, 1) < pi_l(N, 0)$, each of the $N$ firms sells $q_l^* = Q_l(N,0)/N$ of product $l$ where $Q_l$ satisfies $(7)$ and no firms sell product $n$.
The intuition behind equilibrium listed in 1. above is simple to see. If $pi_l(1, N-1) < pi_n(0, N)$, then we have
$$underbracepi_l(N,0) < cdots < pi_l(1, N-1)_textSince pi_l^i(N_l, N_n) textis decreasing in N_l < underbracepi_n(0, N) < cdots < pi_n(N-1, 1)_textSince pi_n^i(N_l, N_n) textis decreasing in N_n $$
Therefore, in equilibrium, any firm that is producing $l$ are strictly better off by deviating to producing $n$, so every firm will produce $n$ in equilibrium. The intuition for 2. is similar.
Where I am stuck:
I am told that there is another equilibrium which is characterized as:
If the number of firms in the market and the parameter values are such that the monopoly profits from selling one product exceed the Cournot profits if all firms sell the other product, then, ignoring integer problems, equilibrium is found by setting the profits from selling the two products equal and so $N_l^*$ and $N_n^*$ satisfy
$$
(1+delta)(N_l^* + 1)(a - c_n)^2left[(1+delta)(N_l^*+1)(N-N_l^* + 1) - (N-N_l^*)^2 right] = (N-N_l^* +1)(a+gamma - c_n - c_p)^2left[(1+delta)(N-N_l^*+1)(N_l^*+1) - (N_l^*)^2 right] cdots (9) $$
$$ N_n^* = N - N_l^* cdots (10) $$
If $pi_l(1, N-1) ge pi_n(0, N)$ and $pi_n(N-1, 1) ge pi_l(N, 0)$, then $N_l^*$ firms sell $q_l^* = Q_l(N_l^*, N_n^*)/N_l^*$ of $l$; $N_n^*$ sell $q_n^* = Q_n(N_l^*, N_n^*)/N_n^*$ of $n$ when equations (7), (8), (9), and (10) are satisfied.
What is the reasoning behind this equilibrium? Specifically, how do Equations (9) and (10) come about? And what exactly are $N_n^*$ and $N_l^*$ and how do they come about in the construction of the equilibrium?
game-theory economics nash-equilibrium
$endgroup$
add a comment |
$begingroup$
QUESTION:
Assume there are two types of products, labelled $l$ and $n$. Firms compete in the market by choosing which product to sell and then choosing the quantities. Let $Q_n$ and $Q_l$ denote the total demand of product $n$ and $l$, respectively. Let the inverse demand functions be given by:
beginalign*
& P_l(Q_l, Q_n) = (a+gamma) - Q_n - (1+delta)Q_l \
& P_n(Q_l, Q_n) = a - Q_n - Q_l
endalign*
where $P_l$ and $P_n$ denote the prices of product $l$ and $n$, respectively, and $a$, $gamma$, $delta$ are all constants greater than zero. Let $q_l^i$ and $q_n^i$ denote the $i$th firm's output of product $l$ and $n$, respectively. Let $X_l^i$ and $X_n^i$ denote the output of the other firms producing product $l$ and $n$, respectively. Let $N_n$ and $N_l$ denote the number of firms selling product $n$ and $l$, respectively. Let the marginal cost of producing the $l$ product be $c_n + c_p$ and the marginal cost of producing the $n$ product be $c_n$. Find all the sub-game perfect Nash equilibria in this game.
My working so far:
I have almost solved the question but I am stuck towards the end of my working. What I've done so far is as follows. First, fix the number of firms selling each product and solve for the equilibrium quantity choices. Then, we can solve for the equilibrium number of firms making each product.
A firm choosing to sell the $l$ product earns profits:
$$pi_l = (P_l - c_n - c_p)q_l^i cdots (1) $$
while a firm choosing to sell the $n$ product earns profits:
$$pi_n = (P_n - c_n )q_n^i cdots (2) $$
Noting that $Q_l = q_l^i + X_l^i$ and $Q_n = q_n^i + X_n^i$ and substituting into the above and then taking first-order conditions with respect to $q_l^i$ (for $(1)$) and $q_n^i$ (for $(2)$), respectively, yields:
beginalign*
& (a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p) - 2(1+delta)q_l^i = 0 cdots (1') \
& a - X_n^i - Q_l - c_n - 2q_n^i =0 cdots (2')
endalign*
From $(1')$, the best response function of a firm choosing to sell $q_l^i$ of product $l$ is given by
$$q_l^i = frac(a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p)2(1+delta) $$
but noting that $X_l^i = Q_l - q_l^i$, we have
$$q_l^i = frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+delta cdots (3) $$.
From $(2')$, the best response function of a firm choosing to sell $q_n^i$ of product $n$ is given by
$$q_n^i = fraca-X_n^i - Q_l - c_n2 $$
but noting that $X_n^i = Q_n - q_n^i$, we have
$$q_n^i = a-Q_n-Q_l-c_n cdots (4)$$.
Since the right-hand sides of $(3)$ and $(4)$ are constants, the first-order conditions imply that firms making the same product produce the same quantity in equilibrium. Since there are $N_n$ firms making $n$ and $N_l$ firms making $l$, therefore:
beginalign*
& Q_l = N_lq_l^i \
& Q_n = N_nq_n^i.
endalign*
Substituting in $(3)$ and $(4)$ we have the following:
beginalign*
& Q_l = N_lleft(frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+deltaright) cdots (5) \
& Q_n = N_nleft(a-Q_n-Q_l-c_nright) cdots (6)
endalign*
Solving $(5)$ and $(6)$ simultaneously for $Q_l$ and $Q_n$, we obtain the total sales of each product (with each firm selling a given product, selling the same amount):
beginalign*
& Q_l(N_l, N_n) = lambda N_lleft((N_n+1)(a + gamma - c_n - c_p) - N_n(a-c_n) right) cdots (7) \
& Q_n(N_l, N_n) = lambda N_nleft((1+delta)(N_l+1)(a-c_n) - N_l(a+gamma - c_n - c_p) right) cdots (8)
endalign*
where
$$lambda = frac1(1+delta)(N_l+1)(N_n+1) - N_lN_n $$. Therefore in equilibrium, the quantities chosen by firms selling $l$ and $n$ are, respectively:
beginalign*
& q_l(N_l, N_n) = fracQ_l(N_l, N_n)N_l \
& q_n(N_l, N_n) = fracQ_n(N_l, N_n)N_n
endalign*
To find the sub-game perfect Nash equilibrium, we need an additional property, that is, no firm can have an incentive to switch and produce the other product. The profits of firms producing $l$ and $n$, respectively, are given by
beginalign*
& pi_l^i(N_l, N_n) = left[a+gamma - Q_n(N_l, N_n) - (1+delta)Q_l(N_l, N_n) - c_n - c_p right]q_l(N_l, N_n) \
& pi_n^i(N_l, N_n) = left[a - Q_n(N_l, N_n) - Q_l(N_l, N_n) - c_n right]q_n(N_l, N_n).
endalign*
One can show that $pi_l^i(N_l, N_n)$ is decreasing in $N_l$ and $pi_n^i(N_l, N_n)$ is decreasing in $N_n$. Let $N = N_l + N_n$ denote the total firms in the market, then two types of equilibria can be summarized as follows:
- If $pi_l(1, N-1) < pi_n(0, N)$, each of the $N$ firms sells $q_n^* = Q_n(0,N)/N$ of product $n$ where $Q_n$ satisfies $(8)$ and no firms sell product $l$.
- If $pi_n(N-1, 1) < pi_l(N, 0)$, each of the $N$ firms sells $q_l^* = Q_l(N,0)/N$ of product $l$ where $Q_l$ satisfies $(7)$ and no firms sell product $n$.
The intuition behind equilibrium listed in 1. above is simple to see. If $pi_l(1, N-1) < pi_n(0, N)$, then we have
$$underbracepi_l(N,0) < cdots < pi_l(1, N-1)_textSince pi_l^i(N_l, N_n) textis decreasing in N_l < underbracepi_n(0, N) < cdots < pi_n(N-1, 1)_textSince pi_n^i(N_l, N_n) textis decreasing in N_n $$
Therefore, in equilibrium, any firm that is producing $l$ are strictly better off by deviating to producing $n$, so every firm will produce $n$ in equilibrium. The intuition for 2. is similar.
Where I am stuck:
I am told that there is another equilibrium which is characterized as:
If the number of firms in the market and the parameter values are such that the monopoly profits from selling one product exceed the Cournot profits if all firms sell the other product, then, ignoring integer problems, equilibrium is found by setting the profits from selling the two products equal and so $N_l^*$ and $N_n^*$ satisfy
$$
(1+delta)(N_l^* + 1)(a - c_n)^2left[(1+delta)(N_l^*+1)(N-N_l^* + 1) - (N-N_l^*)^2 right] = (N-N_l^* +1)(a+gamma - c_n - c_p)^2left[(1+delta)(N-N_l^*+1)(N_l^*+1) - (N_l^*)^2 right] cdots (9) $$
$$ N_n^* = N - N_l^* cdots (10) $$
If $pi_l(1, N-1) ge pi_n(0, N)$ and $pi_n(N-1, 1) ge pi_l(N, 0)$, then $N_l^*$ firms sell $q_l^* = Q_l(N_l^*, N_n^*)/N_l^*$ of $l$; $N_n^*$ sell $q_n^* = Q_n(N_l^*, N_n^*)/N_n^*$ of $n$ when equations (7), (8), (9), and (10) are satisfied.
What is the reasoning behind this equilibrium? Specifically, how do Equations (9) and (10) come about? And what exactly are $N_n^*$ and $N_l^*$ and how do they come about in the construction of the equilibrium?
game-theory economics nash-equilibrium
$endgroup$
QUESTION:
Assume there are two types of products, labelled $l$ and $n$. Firms compete in the market by choosing which product to sell and then choosing the quantities. Let $Q_n$ and $Q_l$ denote the total demand of product $n$ and $l$, respectively. Let the inverse demand functions be given by:
beginalign*
& P_l(Q_l, Q_n) = (a+gamma) - Q_n - (1+delta)Q_l \
& P_n(Q_l, Q_n) = a - Q_n - Q_l
endalign*
where $P_l$ and $P_n$ denote the prices of product $l$ and $n$, respectively, and $a$, $gamma$, $delta$ are all constants greater than zero. Let $q_l^i$ and $q_n^i$ denote the $i$th firm's output of product $l$ and $n$, respectively. Let $X_l^i$ and $X_n^i$ denote the output of the other firms producing product $l$ and $n$, respectively. Let $N_n$ and $N_l$ denote the number of firms selling product $n$ and $l$, respectively. Let the marginal cost of producing the $l$ product be $c_n + c_p$ and the marginal cost of producing the $n$ product be $c_n$. Find all the sub-game perfect Nash equilibria in this game.
My working so far:
I have almost solved the question but I am stuck towards the end of my working. What I've done so far is as follows. First, fix the number of firms selling each product and solve for the equilibrium quantity choices. Then, we can solve for the equilibrium number of firms making each product.
A firm choosing to sell the $l$ product earns profits:
$$pi_l = (P_l - c_n - c_p)q_l^i cdots (1) $$
while a firm choosing to sell the $n$ product earns profits:
$$pi_n = (P_n - c_n )q_n^i cdots (2) $$
Noting that $Q_l = q_l^i + X_l^i$ and $Q_n = q_n^i + X_n^i$ and substituting into the above and then taking first-order conditions with respect to $q_l^i$ (for $(1)$) and $q_n^i$ (for $(2)$), respectively, yields:
beginalign*
& (a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p) - 2(1+delta)q_l^i = 0 cdots (1') \
& a - X_n^i - Q_l - c_n - 2q_n^i =0 cdots (2')
endalign*
From $(1')$, the best response function of a firm choosing to sell $q_l^i$ of product $l$ is given by
$$q_l^i = frac(a+gamma) - (1+delta)X_l^i - Q_n - (c_n + c_p)2(1+delta) $$
but noting that $X_l^i = Q_l - q_l^i$, we have
$$q_l^i = frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+delta cdots (3) $$.
From $(2')$, the best response function of a firm choosing to sell $q_n^i$ of product $n$ is given by
$$q_n^i = fraca-X_n^i - Q_l - c_n2 $$
but noting that $X_n^i = Q_n - q_n^i$, we have
$$q_n^i = a-Q_n-Q_l-c_n cdots (4)$$.
Since the right-hand sides of $(3)$ and $(4)$ are constants, the first-order conditions imply that firms making the same product produce the same quantity in equilibrium. Since there are $N_n$ firms making $n$ and $N_l$ firms making $l$, therefore:
beginalign*
& Q_l = N_lq_l^i \
& Q_n = N_nq_n^i.
endalign*
Substituting in $(3)$ and $(4)$ we have the following:
beginalign*
& Q_l = N_lleft(frac(a+gamma) - (1+delta)Q_l - Q_n - (c_n + c_p)1+deltaright) cdots (5) \
& Q_n = N_nleft(a-Q_n-Q_l-c_nright) cdots (6)
endalign*
Solving $(5)$ and $(6)$ simultaneously for $Q_l$ and $Q_n$, we obtain the total sales of each product (with each firm selling a given product, selling the same amount):
beginalign*
& Q_l(N_l, N_n) = lambda N_lleft((N_n+1)(a + gamma - c_n - c_p) - N_n(a-c_n) right) cdots (7) \
& Q_n(N_l, N_n) = lambda N_nleft((1+delta)(N_l+1)(a-c_n) - N_l(a+gamma - c_n - c_p) right) cdots (8)
endalign*
where
$$lambda = frac1(1+delta)(N_l+1)(N_n+1) - N_lN_n $$. Therefore in equilibrium, the quantities chosen by firms selling $l$ and $n$ are, respectively:
beginalign*
& q_l(N_l, N_n) = fracQ_l(N_l, N_n)N_l \
& q_n(N_l, N_n) = fracQ_n(N_l, N_n)N_n
endalign*
To find the sub-game perfect Nash equilibrium, we need an additional property, that is, no firm can have an incentive to switch and produce the other product. The profits of firms producing $l$ and $n$, respectively, are given by
beginalign*
& pi_l^i(N_l, N_n) = left[a+gamma - Q_n(N_l, N_n) - (1+delta)Q_l(N_l, N_n) - c_n - c_p right]q_l(N_l, N_n) \
& pi_n^i(N_l, N_n) = left[a - Q_n(N_l, N_n) - Q_l(N_l, N_n) - c_n right]q_n(N_l, N_n).
endalign*
One can show that $pi_l^i(N_l, N_n)$ is decreasing in $N_l$ and $pi_n^i(N_l, N_n)$ is decreasing in $N_n$. Let $N = N_l + N_n$ denote the total firms in the market, then two types of equilibria can be summarized as follows:
- If $pi_l(1, N-1) < pi_n(0, N)$, each of the $N$ firms sells $q_n^* = Q_n(0,N)/N$ of product $n$ where $Q_n$ satisfies $(8)$ and no firms sell product $l$.
- If $pi_n(N-1, 1) < pi_l(N, 0)$, each of the $N$ firms sells $q_l^* = Q_l(N,0)/N$ of product $l$ where $Q_l$ satisfies $(7)$ and no firms sell product $n$.
The intuition behind equilibrium listed in 1. above is simple to see. If $pi_l(1, N-1) < pi_n(0, N)$, then we have
$$underbracepi_l(N,0) < cdots < pi_l(1, N-1)_textSince pi_l^i(N_l, N_n) textis decreasing in N_l < underbracepi_n(0, N) < cdots < pi_n(N-1, 1)_textSince pi_n^i(N_l, N_n) textis decreasing in N_n $$
Therefore, in equilibrium, any firm that is producing $l$ are strictly better off by deviating to producing $n$, so every firm will produce $n$ in equilibrium. The intuition for 2. is similar.
Where I am stuck:
I am told that there is another equilibrium which is characterized as:
If the number of firms in the market and the parameter values are such that the monopoly profits from selling one product exceed the Cournot profits if all firms sell the other product, then, ignoring integer problems, equilibrium is found by setting the profits from selling the two products equal and so $N_l^*$ and $N_n^*$ satisfy
$$
(1+delta)(N_l^* + 1)(a - c_n)^2left[(1+delta)(N_l^*+1)(N-N_l^* + 1) - (N-N_l^*)^2 right] = (N-N_l^* +1)(a+gamma - c_n - c_p)^2left[(1+delta)(N-N_l^*+1)(N_l^*+1) - (N_l^*)^2 right] cdots (9) $$
$$ N_n^* = N - N_l^* cdots (10) $$
If $pi_l(1, N-1) ge pi_n(0, N)$ and $pi_n(N-1, 1) ge pi_l(N, 0)$, then $N_l^*$ firms sell $q_l^* = Q_l(N_l^*, N_n^*)/N_l^*$ of $l$; $N_n^*$ sell $q_n^* = Q_n(N_l^*, N_n^*)/N_n^*$ of $n$ when equations (7), (8), (9), and (10) are satisfied.
What is the reasoning behind this equilibrium? Specifically, how do Equations (9) and (10) come about? And what exactly are $N_n^*$ and $N_l^*$ and how do they come about in the construction of the equilibrium?
game-theory economics nash-equilibrium
game-theory economics nash-equilibrium
edited Apr 2 at 21:18
elbarto
asked Apr 1 at 19:16
elbartoelbarto
1,574830
1,574830
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