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How can a “non-function” be graphed?


Graphing inverse of parabola, should the domain be restricted or not?Moriarty's calculator: some bizarre and deceptive graphical anomaliesCan trigonometric equations be graphed?Best program for creating educational math animations?Visualising High Powers of Sin and Cos without GraphingBehaviour of multivariate functionsFunctional Square Root Grapher3D Graphing TI-Nspire CXHow to sketch an $xy$ graph from a $yu$ and $xu$ graph.Better method for graphing functions with greater complexity













1












$begingroup$


I am trying to create a program that requires the graphing of a "non-function", i.e, a function where "x" isn't strictly dependent on "y".



Let's answer the obvious question: Is it even possible?



Yes, it is possible, as demonstrated by online graphing calculators such as Desmos and GeoGebra, as well as several other open-source softwares. However, I haven't had success in figuring out how these graphing calculators graph non-functions. I have done some research, and have found nothing helpful.



Now, I'm looking for means to graph any non-functions, not just simple ones such as a circle or a sideways parabola, which simply require the graphs of +f(x) and -f(x). Maybe more complicated ones such as sin(x) + sin(y)= 1. The following graph is of the said non-function, as graphed by Desmos.



sin(x)+sin(y)=1



Any help on how to graph non-functions is appreciated. Thanks in advance.










share|cite|improve this question









$endgroup$
















    1












    $begingroup$


    I am trying to create a program that requires the graphing of a "non-function", i.e, a function where "x" isn't strictly dependent on "y".



    Let's answer the obvious question: Is it even possible?



    Yes, it is possible, as demonstrated by online graphing calculators such as Desmos and GeoGebra, as well as several other open-source softwares. However, I haven't had success in figuring out how these graphing calculators graph non-functions. I have done some research, and have found nothing helpful.



    Now, I'm looking for means to graph any non-functions, not just simple ones such as a circle or a sideways parabola, which simply require the graphs of +f(x) and -f(x). Maybe more complicated ones such as sin(x) + sin(y)= 1. The following graph is of the said non-function, as graphed by Desmos.



    sin(x)+sin(y)=1



    Any help on how to graph non-functions is appreciated. Thanks in advance.










    share|cite|improve this question









    $endgroup$














      1












      1








      1





      $begingroup$


      I am trying to create a program that requires the graphing of a "non-function", i.e, a function where "x" isn't strictly dependent on "y".



      Let's answer the obvious question: Is it even possible?



      Yes, it is possible, as demonstrated by online graphing calculators such as Desmos and GeoGebra, as well as several other open-source softwares. However, I haven't had success in figuring out how these graphing calculators graph non-functions. I have done some research, and have found nothing helpful.



      Now, I'm looking for means to graph any non-functions, not just simple ones such as a circle or a sideways parabola, which simply require the graphs of +f(x) and -f(x). Maybe more complicated ones such as sin(x) + sin(y)= 1. The following graph is of the said non-function, as graphed by Desmos.



      sin(x)+sin(y)=1



      Any help on how to graph non-functions is appreciated. Thanks in advance.










      share|cite|improve this question









      $endgroup$




      I am trying to create a program that requires the graphing of a "non-function", i.e, a function where "x" isn't strictly dependent on "y".



      Let's answer the obvious question: Is it even possible?



      Yes, it is possible, as demonstrated by online graphing calculators such as Desmos and GeoGebra, as well as several other open-source softwares. However, I haven't had success in figuring out how these graphing calculators graph non-functions. I have done some research, and have found nothing helpful.



      Now, I'm looking for means to graph any non-functions, not just simple ones such as a circle or a sideways parabola, which simply require the graphs of +f(x) and -f(x). Maybe more complicated ones such as sin(x) + sin(y)= 1. The following graph is of the said non-function, as graphed by Desmos.



      sin(x)+sin(y)=1



      Any help on how to graph non-functions is appreciated. Thanks in advance.







      graphing-functions






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Sep 18 '17 at 3:16









      Rapid ReadersRapid Readers

      12516




      12516




















          3 Answers
          3






          active

          oldest

          votes


















          0












          $begingroup$

          A lot of the time examples like these "look" like functions locally. Therefore they can broken up into little pieces by using a valid set of initial conditions or a function which is valid and describes part of the overall relation you are trying to graph.



          In your example we can convert the equation to look like:



          $$
          y = sin^-1(1-sin(x))
          $$



          Which gives a starting point looking like the bottom half of a single warped sphere. Then we see that since $sin(y)=sin(pi-y)$ we can cap the warped sphere. Then we can argue that the equation is clearly unchanged if we were to replace $(x,y)$ with $(x+2pi n ,y+2pi m)$ (for integer values of m,n) and so we can repeat our pattern throughout the entire grid due to the periodicity of the $sin$ function.



          Another good example is $y^2 = x$ where we have two sets of solutions corresponding to $y=pm sqrtx $.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
            $endgroup$
            – Rapid Readers
            Sep 18 '17 at 4:11











          • $begingroup$
            If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
            $endgroup$
            – Ryan Watt
            Sep 19 '17 at 6:36


















          0












          $begingroup$

          An aproach for this would be to take some values.

          x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy

          For example x=5. We substitute this value. And later we try different values for y until we have a equality (left part is some as right side). Some mechanisms help to do this, looking on how quick we get a approximation. I would first convert this to a equation equal to 0 :

          x arcsin( x/y) + sqrt( y^2 - x^2) - 4xy = 0


          This is trivial, and now for each x-value, we can get a y value (or many y-values) using a aproximation methode like Newton, which use derivates.

          Daniel



          P.S. see https://en.wikipedia.org/wiki/Newton%27s_method






          share|cite|improve this answer









          $endgroup$




















            0












            $begingroup$

            According from what you asked, let's see images below and take conclusions.



            https://i.ytimg.com/vi/y7N0Pr3N1RY/maxresdefault.jpg
            (points tracing)



            https://i.stack.imgur.com/SAubS.png
            (from the same equation in 3D graph)



            To trace a XY graph which is non-function, it is actually calculate the equation with every X and Y in the graph in range.
            And it is determined by intersection between XY plane.






            share|cite|improve this answer











            $endgroup$













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              3 Answers
              3






              active

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              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0












              $begingroup$

              A lot of the time examples like these "look" like functions locally. Therefore they can broken up into little pieces by using a valid set of initial conditions or a function which is valid and describes part of the overall relation you are trying to graph.



              In your example we can convert the equation to look like:



              $$
              y = sin^-1(1-sin(x))
              $$



              Which gives a starting point looking like the bottom half of a single warped sphere. Then we see that since $sin(y)=sin(pi-y)$ we can cap the warped sphere. Then we can argue that the equation is clearly unchanged if we were to replace $(x,y)$ with $(x+2pi n ,y+2pi m)$ (for integer values of m,n) and so we can repeat our pattern throughout the entire grid due to the periodicity of the $sin$ function.



              Another good example is $y^2 = x$ where we have two sets of solutions corresponding to $y=pm sqrtx $.






              share|cite|improve this answer









              $endgroup$












              • $begingroup$
                I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
                $endgroup$
                – Rapid Readers
                Sep 18 '17 at 4:11











              • $begingroup$
                If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
                $endgroup$
                – Ryan Watt
                Sep 19 '17 at 6:36















              0












              $begingroup$

              A lot of the time examples like these "look" like functions locally. Therefore they can broken up into little pieces by using a valid set of initial conditions or a function which is valid and describes part of the overall relation you are trying to graph.



              In your example we can convert the equation to look like:



              $$
              y = sin^-1(1-sin(x))
              $$



              Which gives a starting point looking like the bottom half of a single warped sphere. Then we see that since $sin(y)=sin(pi-y)$ we can cap the warped sphere. Then we can argue that the equation is clearly unchanged if we were to replace $(x,y)$ with $(x+2pi n ,y+2pi m)$ (for integer values of m,n) and so we can repeat our pattern throughout the entire grid due to the periodicity of the $sin$ function.



              Another good example is $y^2 = x$ where we have two sets of solutions corresponding to $y=pm sqrtx $.






              share|cite|improve this answer









              $endgroup$












              • $begingroup$
                I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
                $endgroup$
                – Rapid Readers
                Sep 18 '17 at 4:11











              • $begingroup$
                If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
                $endgroup$
                – Ryan Watt
                Sep 19 '17 at 6:36













              0












              0








              0





              $begingroup$

              A lot of the time examples like these "look" like functions locally. Therefore they can broken up into little pieces by using a valid set of initial conditions or a function which is valid and describes part of the overall relation you are trying to graph.



              In your example we can convert the equation to look like:



              $$
              y = sin^-1(1-sin(x))
              $$



              Which gives a starting point looking like the bottom half of a single warped sphere. Then we see that since $sin(y)=sin(pi-y)$ we can cap the warped sphere. Then we can argue that the equation is clearly unchanged if we were to replace $(x,y)$ with $(x+2pi n ,y+2pi m)$ (for integer values of m,n) and so we can repeat our pattern throughout the entire grid due to the periodicity of the $sin$ function.



              Another good example is $y^2 = x$ where we have two sets of solutions corresponding to $y=pm sqrtx $.






              share|cite|improve this answer









              $endgroup$



              A lot of the time examples like these "look" like functions locally. Therefore they can broken up into little pieces by using a valid set of initial conditions or a function which is valid and describes part of the overall relation you are trying to graph.



              In your example we can convert the equation to look like:



              $$
              y = sin^-1(1-sin(x))
              $$



              Which gives a starting point looking like the bottom half of a single warped sphere. Then we see that since $sin(y)=sin(pi-y)$ we can cap the warped sphere. Then we can argue that the equation is clearly unchanged if we were to replace $(x,y)$ with $(x+2pi n ,y+2pi m)$ (for integer values of m,n) and so we can repeat our pattern throughout the entire grid due to the periodicity of the $sin$ function.



              Another good example is $y^2 = x$ where we have two sets of solutions corresponding to $y=pm sqrtx $.







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered Sep 18 '17 at 3:36









              Ryan WattRyan Watt

              262




              262











              • $begingroup$
                I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
                $endgroup$
                – Rapid Readers
                Sep 18 '17 at 4:11











              • $begingroup$
                If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
                $endgroup$
                – Ryan Watt
                Sep 19 '17 at 6:36
















              • $begingroup$
                I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
                $endgroup$
                – Rapid Readers
                Sep 18 '17 at 4:11











              • $begingroup$
                If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
                $endgroup$
                – Ryan Watt
                Sep 19 '17 at 6:36















              $begingroup$
              I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
              $endgroup$
              – Rapid Readers
              Sep 18 '17 at 4:11





              $begingroup$
              I really like your explanation. However, there is a problem. Some non-functions cannot be simplified exclusively to have y be dependent on x. For instance, x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy, which isn't even symmetric like the other examples, but can still be graphed by Desmos.
              $endgroup$
              – Rapid Readers
              Sep 18 '17 at 4:11













              $begingroup$
              If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
              $endgroup$
              – Ryan Watt
              Sep 19 '17 at 6:36




              $begingroup$
              If you are alright with approximate solutions then you can differentiate w.r.t. x to isolate for $fracdydx$ and then expand around as many sets of valid initial conditions as you can find. I'm sure there are some fancier tricks for finding a complete graph for an equation but I was just trying to point out that such an equation acts like a function somewhere around every set of valid initial conditions.
              $endgroup$
              – Ryan Watt
              Sep 19 '17 at 6:36











              0












              $begingroup$

              An aproach for this would be to take some values.

              x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy

              For example x=5. We substitute this value. And later we try different values for y until we have a equality (left part is some as right side). Some mechanisms help to do this, looking on how quick we get a approximation. I would first convert this to a equation equal to 0 :

              x arcsin( x/y) + sqrt( y^2 - x^2) - 4xy = 0


              This is trivial, and now for each x-value, we can get a y value (or many y-values) using a aproximation methode like Newton, which use derivates.

              Daniel



              P.S. see https://en.wikipedia.org/wiki/Newton%27s_method






              share|cite|improve this answer









              $endgroup$

















                0












                $begingroup$

                An aproach for this would be to take some values.

                x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy

                For example x=5. We substitute this value. And later we try different values for y until we have a equality (left part is some as right side). Some mechanisms help to do this, looking on how quick we get a approximation. I would first convert this to a equation equal to 0 :

                x arcsin( x/y) + sqrt( y^2 - x^2) - 4xy = 0


                This is trivial, and now for each x-value, we can get a y value (or many y-values) using a aproximation methode like Newton, which use derivates.

                Daniel



                P.S. see https://en.wikipedia.org/wiki/Newton%27s_method






                share|cite|improve this answer









                $endgroup$















                  0












                  0








                  0





                  $begingroup$

                  An aproach for this would be to take some values.

                  x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy

                  For example x=5. We substitute this value. And later we try different values for y until we have a equality (left part is some as right side). Some mechanisms help to do this, looking on how quick we get a approximation. I would first convert this to a equation equal to 0 :

                  x arcsin( x/y) + sqrt( y^2 - x^2) - 4xy = 0


                  This is trivial, and now for each x-value, we can get a y value (or many y-values) using a aproximation methode like Newton, which use derivates.

                  Daniel



                  P.S. see https://en.wikipedia.org/wiki/Newton%27s_method






                  share|cite|improve this answer









                  $endgroup$



                  An aproach for this would be to take some values.

                  x arcsin( x/y) + sqrt( y^2 - x^2) = 4xy

                  For example x=5. We substitute this value. And later we try different values for y until we have a equality (left part is some as right side). Some mechanisms help to do this, looking on how quick we get a approximation. I would first convert this to a equation equal to 0 :

                  x arcsin( x/y) + sqrt( y^2 - x^2) - 4xy = 0


                  This is trivial, and now for each x-value, we can get a y value (or many y-values) using a aproximation methode like Newton, which use derivates.

                  Daniel



                  P.S. see https://en.wikipedia.org/wiki/Newton%27s_method







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Sep 18 '17 at 6:25









                  Daniel PolDaniel Pol

                  33425




                  33425





















                      0












                      $begingroup$

                      According from what you asked, let's see images below and take conclusions.



                      https://i.ytimg.com/vi/y7N0Pr3N1RY/maxresdefault.jpg
                      (points tracing)



                      https://i.stack.imgur.com/SAubS.png
                      (from the same equation in 3D graph)



                      To trace a XY graph which is non-function, it is actually calculate the equation with every X and Y in the graph in range.
                      And it is determined by intersection between XY plane.






                      share|cite|improve this answer











                      $endgroup$

















                        0












                        $begingroup$

                        According from what you asked, let's see images below and take conclusions.



                        https://i.ytimg.com/vi/y7N0Pr3N1RY/maxresdefault.jpg
                        (points tracing)



                        https://i.stack.imgur.com/SAubS.png
                        (from the same equation in 3D graph)



                        To trace a XY graph which is non-function, it is actually calculate the equation with every X and Y in the graph in range.
                        And it is determined by intersection between XY plane.






                        share|cite|improve this answer











                        $endgroup$















                          0












                          0








                          0





                          $begingroup$

                          According from what you asked, let's see images below and take conclusions.



                          https://i.ytimg.com/vi/y7N0Pr3N1RY/maxresdefault.jpg
                          (points tracing)



                          https://i.stack.imgur.com/SAubS.png
                          (from the same equation in 3D graph)



                          To trace a XY graph which is non-function, it is actually calculate the equation with every X and Y in the graph in range.
                          And it is determined by intersection between XY plane.






                          share|cite|improve this answer











                          $endgroup$



                          According from what you asked, let's see images below and take conclusions.



                          https://i.ytimg.com/vi/y7N0Pr3N1RY/maxresdefault.jpg
                          (points tracing)



                          https://i.stack.imgur.com/SAubS.png
                          (from the same equation in 3D graph)



                          To trace a XY graph which is non-function, it is actually calculate the equation with every X and Y in the graph in range.
                          And it is determined by intersection between XY plane.







                          share|cite|improve this answer














                          share|cite|improve this answer



                          share|cite|improve this answer








                          edited Jan 5 '18 at 7:04

























                          answered Jan 3 '18 at 9:58









                          A-KouZ1A-KouZ1

                          11




                          11



























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                              Trouble understanding the speech of overseas colleaguesHow can I better understand manager or clients with strong accents?Adding more movement and speech at the fundamental level to a highly-sedentary job?Difficulty in understanding Manager's accent(language and communication)How to adjust yourself where your colleagues are not understanding to you?Understanding manager's expectationsForeigner and colleagues using slangHaving difficulty understanding meetingsHow do you breathe when giving a speech?Trouble Waking Up for Emergencies (On-Call)Problems with colleaguesColleagues feeling insecure when I do my work

                              Ballerup Komuun Stääden an saarpen | Futnuuten | Luke uk diar | Nawigatsjuunwww.ballerup.dkwww.statistikbanken.dk: Tabelle BEF44 (Folketal pr. 1. januar fordelt på byer)Commonskategorii: Ballerup Komuun55° 44′ N, 12° 22′ O