Evaluate $intint_Ge^yover x+ydxdy$evaluating this difficult integralSurface Integral over a Vector Field questionEvaluate$int_-2^2int_y^2-3^5-y^2dxdy$Evaluate $int_-2^2int_y^2-3^5-y^2dxdy$Explain why you could have have predicted the result… By inspection: $int^2_0 int^4-x^2_0 x^3 dydx = frac163 units^3 $Evaluate the double integral boundedEvaluate the double integral $intint_R(x^2-2y) $ $dxdy$Changing integration order of $int_0^1int_e^y-1^e^y f(x,y)dxdy$$iint f(x)g(y)dxdy =int f(x)dx int g(y)dy $ Why?finding area using double integrals

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Evaluate $intint_Ge^yover x+ydxdy$


evaluating this difficult integralSurface Integral over a Vector Field questionEvaluate$int_-2^2int_y^2-3^5-y^2dxdy$Evaluate $int_-2^2int_y^2-3^5-y^2dxdy$Explain why you could have have predicted the result… By inspection: $int^2_0 int^4-x^2_0 x^3 dydx = frac163 units^3 $Evaluate the double integral boundedEvaluate the double integral $intint_R(x^2-2y) $ $dxdy$Changing integration order of $int_0^1int_e^y-1^e^y f(x,y)dxdy$$iint f(x)g(y)dxdy =int f(x)dx int g(y)dy $ Why?finding area using double integrals













0












$begingroup$


Evaluate $intint_Ge^yover x+ydxdy$ where G is the triangle enclosed by $x+y=1$, x axis and y axis.

My attempt:

let $u=x+y$, $v=y$, $|J|=1$
$$int_0^1int_0^-x+1e^yover x+ydydx=int_0^1int_0^1e^vover udvdu$$



But still I couldn't figure out this.










share|cite|improve this question









$endgroup$











  • $begingroup$
    In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
    $endgroup$
    – Robert Israel
    Jan 27 at 18:54











  • $begingroup$
    Yes, I did miss that, thank you!
    $endgroup$
    – Yibei He
    Jan 27 at 19:00















0












$begingroup$


Evaluate $intint_Ge^yover x+ydxdy$ where G is the triangle enclosed by $x+y=1$, x axis and y axis.

My attempt:

let $u=x+y$, $v=y$, $|J|=1$
$$int_0^1int_0^-x+1e^yover x+ydydx=int_0^1int_0^1e^vover udvdu$$



But still I couldn't figure out this.










share|cite|improve this question









$endgroup$











  • $begingroup$
    In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
    $endgroup$
    – Robert Israel
    Jan 27 at 18:54











  • $begingroup$
    Yes, I did miss that, thank you!
    $endgroup$
    – Yibei He
    Jan 27 at 19:00













0












0








0





$begingroup$


Evaluate $intint_Ge^yover x+ydxdy$ where G is the triangle enclosed by $x+y=1$, x axis and y axis.

My attempt:

let $u=x+y$, $v=y$, $|J|=1$
$$int_0^1int_0^-x+1e^yover x+ydydx=int_0^1int_0^1e^vover udvdu$$



But still I couldn't figure out this.










share|cite|improve this question









$endgroup$




Evaluate $intint_Ge^yover x+ydxdy$ where G is the triangle enclosed by $x+y=1$, x axis and y axis.

My attempt:

let $u=x+y$, $v=y$, $|J|=1$
$$int_0^1int_0^-x+1e^yover x+ydydx=int_0^1int_0^1e^vover udvdu$$



But still I couldn't figure out this.







calculus






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 27 at 18:40









Yibei HeYibei He

3139




3139











  • $begingroup$
    In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
    $endgroup$
    – Robert Israel
    Jan 27 at 18:54











  • $begingroup$
    Yes, I did miss that, thank you!
    $endgroup$
    – Yibei He
    Jan 27 at 19:00
















  • $begingroup$
    In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
    $endgroup$
    – Robert Israel
    Jan 27 at 18:54











  • $begingroup$
    Yes, I did miss that, thank you!
    $endgroup$
    – Yibei He
    Jan 27 at 19:00















$begingroup$
In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
$endgroup$
– Robert Israel
Jan 27 at 18:54





$begingroup$
In this triangle, $u ge v$ so you'd want the $v$ integral to go from $0$ to $u$.
$endgroup$
– Robert Israel
Jan 27 at 18:54













$begingroup$
Yes, I did miss that, thank you!
$endgroup$
– Yibei He
Jan 27 at 19:00




$begingroup$
Yes, I did miss that, thank you!
$endgroup$
– Yibei He
Jan 27 at 19:00










1 Answer
1






active

oldest

votes


















0












$begingroup$

Consider the substitution
$$x=rcos^2phi,quad y=rsin^2phi,
$$

with $|J|=rsin2phi $, which results in



$$
intint_Ge^yover x+ydxdy=int_0^1 drint_0^pi/2e^sin^2phirsin2phi; dphi\
stackrelsin^2phimapsto u=int_0^1 rdrint_0^1e^udu=frac e-12.
$$






share|cite|improve this answer











$endgroup$













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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    Consider the substitution
    $$x=rcos^2phi,quad y=rsin^2phi,
    $$

    with $|J|=rsin2phi $, which results in



    $$
    intint_Ge^yover x+ydxdy=int_0^1 drint_0^pi/2e^sin^2phirsin2phi; dphi\
    stackrelsin^2phimapsto u=int_0^1 rdrint_0^1e^udu=frac e-12.
    $$






    share|cite|improve this answer











    $endgroup$

















      0












      $begingroup$

      Consider the substitution
      $$x=rcos^2phi,quad y=rsin^2phi,
      $$

      with $|J|=rsin2phi $, which results in



      $$
      intint_Ge^yover x+ydxdy=int_0^1 drint_0^pi/2e^sin^2phirsin2phi; dphi\
      stackrelsin^2phimapsto u=int_0^1 rdrint_0^1e^udu=frac e-12.
      $$






      share|cite|improve this answer











      $endgroup$















        0












        0








        0





        $begingroup$

        Consider the substitution
        $$x=rcos^2phi,quad y=rsin^2phi,
        $$

        with $|J|=rsin2phi $, which results in



        $$
        intint_Ge^yover x+ydxdy=int_0^1 drint_0^pi/2e^sin^2phirsin2phi; dphi\
        stackrelsin^2phimapsto u=int_0^1 rdrint_0^1e^udu=frac e-12.
        $$






        share|cite|improve this answer











        $endgroup$



        Consider the substitution
        $$x=rcos^2phi,quad y=rsin^2phi,
        $$

        with $|J|=rsin2phi $, which results in



        $$
        intint_Ge^yover x+ydxdy=int_0^1 drint_0^pi/2e^sin^2phirsin2phi; dphi\
        stackrelsin^2phimapsto u=int_0^1 rdrint_0^1e^udu=frac e-12.
        $$







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Mar 30 at 0:21

























        answered Jan 27 at 20:50









        useruser

        6,34611031




        6,34611031



























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