space of projective plane curves of degree dGenus formula for curve on surfaceBirational Maps of Nonsingular Projective CurvesGeometric interpretation of the Riemann-Roch for curvesDegree of ample bundle over projective curve is positiveProjective curve $x^d+y^d+z^d=0$ is nonsingular using Jacobian matrixResolving a node singularity on a plane curve“Canonical map” of singular stable curvesWhy geometrically irreducible quartic curves in projective plane corresponds to an open subset of projective space of dimension 14Only finitely many genus $g$ smooth projective curves over a finite fieldRemoving singular points from curves

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space of projective plane curves of degree d


Genus formula for curve on surfaceBirational Maps of Nonsingular Projective CurvesGeometric interpretation of the Riemann-Roch for curvesDegree of ample bundle over projective curve is positiveProjective curve $x^d+y^d+z^d=0$ is nonsingular using Jacobian matrixResolving a node singularity on a plane curve“Canonical map” of singular stable curvesWhy geometrically irreducible quartic curves in projective plane corresponds to an open subset of projective space of dimension 14Only finitely many genus $g$ smooth projective curves over a finite fieldRemoving singular points from curves













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This is basically from Hartshorne Exercise I.5.13 where he writes there is a correspondence from the set of plane projective curves of degree $d$ to points in a projective space $mathbb P^N$ where $N=binomd+22-1$. All seems reasonable and I can easily produce this canonical correspondence.



However he writes that this is not 1-1 if we look at the image of a curve of degree $d$ that is reducible. I seem to be too stupid to find two points in the preimage of a point in $mathbb P^N$. Perhaps I misunderstood something?










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$endgroup$
















    0












    $begingroup$


    This is basically from Hartshorne Exercise I.5.13 where he writes there is a correspondence from the set of plane projective curves of degree $d$ to points in a projective space $mathbb P^N$ where $N=binomd+22-1$. All seems reasonable and I can easily produce this canonical correspondence.



    However he writes that this is not 1-1 if we look at the image of a curve of degree $d$ that is reducible. I seem to be too stupid to find two points in the preimage of a point in $mathbb P^N$. Perhaps I misunderstood something?










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      This is basically from Hartshorne Exercise I.5.13 where he writes there is a correspondence from the set of plane projective curves of degree $d$ to points in a projective space $mathbb P^N$ where $N=binomd+22-1$. All seems reasonable and I can easily produce this canonical correspondence.



      However he writes that this is not 1-1 if we look at the image of a curve of degree $d$ that is reducible. I seem to be too stupid to find two points in the preimage of a point in $mathbb P^N$. Perhaps I misunderstood something?










      share|cite|improve this question











      $endgroup$




      This is basically from Hartshorne Exercise I.5.13 where he writes there is a correspondence from the set of plane projective curves of degree $d$ to points in a projective space $mathbb P^N$ where $N=binomd+22-1$. All seems reasonable and I can easily produce this canonical correspondence.



      However he writes that this is not 1-1 if we look at the image of a curve of degree $d$ that is reducible. I seem to be too stupid to find two points in the preimage of a point in $mathbb P^N$. Perhaps I misunderstood something?







      algebraic-geometry algebraic-curves moduli-space






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      edited Mar 28 at 20:54







      quantum

















      asked Mar 28 at 20:30









      quantumquantum

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      538210




















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          $begingroup$

          $newcommandPmathbb P$I think I know why I was not getting the example:



          1. I was thinking of a function from the set of projective plane curves of degree $d$ to $P^N$

          2. I thought I could get an example if $d=2$ (maybe this is not posssible).

          So Hartshorne meant a map from points in $P^N$ to the set of curves that can be defined by forms of degree $d$. So not only reverse of what I thought, but also we are not talking about the degree of the curve here which I misunderstood as well. One way to get a fiber with more than one point using this map is to consider $d=4$ and now the point in $P^N$ corresponding to $x^2y^2$ which is different from the point in $P^N$ corresponding to $x^3y$ map to the same curve.






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            $begingroup$

            $newcommandPmathbb P$I think I know why I was not getting the example:



            1. I was thinking of a function from the set of projective plane curves of degree $d$ to $P^N$

            2. I thought I could get an example if $d=2$ (maybe this is not posssible).

            So Hartshorne meant a map from points in $P^N$ to the set of curves that can be defined by forms of degree $d$. So not only reverse of what I thought, but also we are not talking about the degree of the curve here which I misunderstood as well. One way to get a fiber with more than one point using this map is to consider $d=4$ and now the point in $P^N$ corresponding to $x^2y^2$ which is different from the point in $P^N$ corresponding to $x^3y$ map to the same curve.






            share|cite|improve this answer









            $endgroup$

















              0












              $begingroup$

              $newcommandPmathbb P$I think I know why I was not getting the example:



              1. I was thinking of a function from the set of projective plane curves of degree $d$ to $P^N$

              2. I thought I could get an example if $d=2$ (maybe this is not posssible).

              So Hartshorne meant a map from points in $P^N$ to the set of curves that can be defined by forms of degree $d$. So not only reverse of what I thought, but also we are not talking about the degree of the curve here which I misunderstood as well. One way to get a fiber with more than one point using this map is to consider $d=4$ and now the point in $P^N$ corresponding to $x^2y^2$ which is different from the point in $P^N$ corresponding to $x^3y$ map to the same curve.






              share|cite|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                $newcommandPmathbb P$I think I know why I was not getting the example:



                1. I was thinking of a function from the set of projective plane curves of degree $d$ to $P^N$

                2. I thought I could get an example if $d=2$ (maybe this is not posssible).

                So Hartshorne meant a map from points in $P^N$ to the set of curves that can be defined by forms of degree $d$. So not only reverse of what I thought, but also we are not talking about the degree of the curve here which I misunderstood as well. One way to get a fiber with more than one point using this map is to consider $d=4$ and now the point in $P^N$ corresponding to $x^2y^2$ which is different from the point in $P^N$ corresponding to $x^3y$ map to the same curve.






                share|cite|improve this answer









                $endgroup$



                $newcommandPmathbb P$I think I know why I was not getting the example:



                1. I was thinking of a function from the set of projective plane curves of degree $d$ to $P^N$

                2. I thought I could get an example if $d=2$ (maybe this is not posssible).

                So Hartshorne meant a map from points in $P^N$ to the set of curves that can be defined by forms of degree $d$. So not only reverse of what I thought, but also we are not talking about the degree of the curve here which I misunderstood as well. One way to get a fiber with more than one point using this map is to consider $d=4$ and now the point in $P^N$ corresponding to $x^2y^2$ which is different from the point in $P^N$ corresponding to $x^3y$ map to the same curve.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 28 at 20:54









                quantumquantum

                538210




                538210



























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