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Functional Derivative on Vector Field (Definition)



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)How to calculate this functional derivative?Functional derivatives in (Physics) Field Theoryproblem with a functional derivativeAbout the definition of functional derivative and the $L^2$ inner productWhy does the functional have a local minimum at $0$?Finding a functional satisfying a given Frechet derivativeFunctional derivative of a functional that depends on antiderivativeFunctional derivative of integral of minimumVariation and functional derivativeAbout the Frechet derivative of a functional










0












$begingroup$


Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
$$
int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
$$



I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
$$
int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
$$










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
    $$
    int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
    $$



    I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
    $$
    int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
    $$










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
      $$
      int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
      $$



      I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
      $$
      int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
      $$










      share|cite|improve this question











      $endgroup$




      Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
      $$
      int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
      $$



      I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
      $$
      int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
      $$







      calculus functional-analysis derivatives definition calculus-of-variations






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Apr 2 at 21:03







      user27182

















      asked Apr 2 at 14:48









      user27182user27182

      1,042727




      1,042727




















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