Functional Derivative on Vector Field (Definition) Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)How to calculate this functional derivative?Functional derivatives in (Physics) Field Theoryproblem with a functional derivativeAbout the definition of functional derivative and the $L^2$ inner productWhy does the functional have a local minimum at $0$?Finding a functional satisfying a given Frechet derivativeFunctional derivative of a functional that depends on antiderivativeFunctional derivative of integral of minimumVariation and functional derivativeAbout the Frechet derivative of a functional
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Functional Derivative on Vector Field (Definition)
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)How to calculate this functional derivative?Functional derivatives in (Physics) Field Theoryproblem with a functional derivativeAbout the definition of functional derivative and the $L^2$ inner productWhy does the functional have a local minimum at $0$?Finding a functional satisfying a given Frechet derivativeFunctional derivative of a functional that depends on antiderivativeFunctional derivative of integral of minimumVariation and functional derivativeAbout the Frechet derivative of a functional
$begingroup$
Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
$$
int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
$$
I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
$$
int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
$$
calculus functional-analysis derivatives definition calculus-of-variations
$endgroup$
add a comment |
$begingroup$
Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
$$
int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
$$
I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
$$
int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
$$
calculus functional-analysis derivatives definition calculus-of-variations
$endgroup$
add a comment |
$begingroup$
Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
$$
int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
$$
I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
$$
int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
$$
calculus functional-analysis derivatives definition calculus-of-variations
$endgroup$
Given a set $mathcalM$ of functions $mathcalX to mathbbR$, a functional $J: mathcalM to mathbbR$ and $f, phi in mathcalM$, the functional derivative of $J$ at $f$, $D_f(J)$ is the (unique) element of $M$ such that
$$
int_mathcalX D_f(J)(x)phi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0.
$$
I am interested in a case in which the functions are $mathcalX to mathbbR^N$. Do we simply exchange the above for
$$
int_mathcalX D_f(J)(x)^Tphi(x)dx = fracddepsilon J[g + epsilon phi] vert_epsilon = 0?
$$
calculus functional-analysis derivatives definition calculus-of-variations
calculus functional-analysis derivatives definition calculus-of-variations
edited Apr 2 at 21:03
user27182
asked Apr 2 at 14:48
user27182user27182
1,042727
1,042727
add a comment |
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