Can we assume $f$ is linear? The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Common method of calculating zero places of quadratic and linear function.Why can we assume WLOG that $x$ is zero?How can a unit step function be differentiable??Linear function definitionIf $f( cos^2(x) ) = cos^2(x)$ can I assume that $f(x) = x$?Can someone explain to a calculus student what “dual space is the space of linear functions” mean?Graphing systems of linear equations.Suppose f : R → R is continuous. Let λ be a positive real number, and assume that for everyIs $x^-1$ a linear function?If both $f(x)$ and $g(x)$ are one to one functions and $g(f(x))= f(g(x)) = x$, why does this prove they are inverse of each other?
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Can we assume $f$ is linear?
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Common method of calculating zero places of quadratic and linear function.Why can we assume WLOG that $x$ is zero?How can a unit step function be differentiable??Linear function definitionIf $f( cos^2(x) ) = cos^2(x)$ can I assume that $f(x) = x$?Can someone explain to a calculus student what “dual space is the space of linear functions” mean?Graphing systems of linear equations.Suppose f : R → R is continuous. Let λ be a positive real number, and assume that for everyIs $x^-1$ a linear function?If both $f(x)$ and $g(x)$ are one to one functions and $g(f(x))= f(g(x)) = x$, why does this prove they are inverse of each other?
$begingroup$
I read a hint of a question:
If $f(6)-f(3)=9$ then $f(12)-f(2)=...$
The hint: By assuming that $f(x)=ax+b$.
I'm confused why we can assume $f$ as linear function?
calculus algebra-precalculus functions
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add a comment |
$begingroup$
I read a hint of a question:
If $f(6)-f(3)=9$ then $f(12)-f(2)=...$
The hint: By assuming that $f(x)=ax+b$.
I'm confused why we can assume $f$ as linear function?
calculus algebra-precalculus functions
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2
$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34
add a comment |
$begingroup$
I read a hint of a question:
If $f(6)-f(3)=9$ then $f(12)-f(2)=...$
The hint: By assuming that $f(x)=ax+b$.
I'm confused why we can assume $f$ as linear function?
calculus algebra-precalculus functions
$endgroup$
I read a hint of a question:
If $f(6)-f(3)=9$ then $f(12)-f(2)=...$
The hint: By assuming that $f(x)=ax+b$.
I'm confused why we can assume $f$ as linear function?
calculus algebra-precalculus functions
calculus algebra-precalculus functions
edited Mar 31 at 13:38
Bernard
124k741117
124k741117
asked Mar 31 at 13:27
TinaTina
111
111
2
$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34
add a comment |
2
$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34
2
2
$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34
add a comment |
1 Answer
1
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oldest
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$begingroup$
No, you can not.
Say $f(x)= 1over 3x^2$, then $f(6)-f(3)= 9$
or $f(x) = sqrt33x-98$, then again $f(6)-f(3)= 9$
$endgroup$
add a comment |
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$begingroup$
No, you can not.
Say $f(x)= 1over 3x^2$, then $f(6)-f(3)= 9$
or $f(x) = sqrt33x-98$, then again $f(6)-f(3)= 9$
$endgroup$
add a comment |
$begingroup$
No, you can not.
Say $f(x)= 1over 3x^2$, then $f(6)-f(3)= 9$
or $f(x) = sqrt33x-98$, then again $f(6)-f(3)= 9$
$endgroup$
add a comment |
$begingroup$
No, you can not.
Say $f(x)= 1over 3x^2$, then $f(6)-f(3)= 9$
or $f(x) = sqrt33x-98$, then again $f(6)-f(3)= 9$
$endgroup$
No, you can not.
Say $f(x)= 1over 3x^2$, then $f(6)-f(3)= 9$
or $f(x) = sqrt33x-98$, then again $f(6)-f(3)= 9$
answered Mar 31 at 13:32
Maria MazurMaria Mazur
49.9k1361125
49.9k1361125
add a comment |
add a comment |
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$begingroup$
Without further assumptions on $f$, the question does not make sense, nor does the hint. Are you sure you haven't missed some part of the exercise?
$endgroup$
– MisterRiemann
Mar 31 at 13:28
$begingroup$
You sure it was a hint? Maybe it just said assume it's linear, and then find the value....
$endgroup$
– Displayname
Mar 31 at 13:34