Skip to main content

Lucy Lawless Isi kandungan Biografi | Rujukan | Pautan luar | Menu pandu arahLucy Lawless Biography (1968-)"Lawless Bulimic No More"Lucy LawlessOfficial fan club siteLucy LawlessLucy LawlessLucy Lawless Interview, May 2007Interview with TheStarScoop, Sept 2006

Kelahiran 1968Orang hidupPelakon wanita New ZealandPenyanyi wanita New Zealand


29 Mac1968pelakonpenyanyiNew Zealandwatak tajukNombor TigaMount AlbertNew Zealandbulimia












Lucy Lawless




Daripada Wikipedia, ensiklopedia bebas.






Jump to navigation
Jump to search










Lucy Lawless
20120713 Lucy Lawless @ Comic-con cropped.jpg
Kelahiran
Lucille Frances Ryan
(1968-03-29) 29 Mac 1968 (umur 51)
Mount Albert, Auckland City, New Zealand
Nama lainLucy Tapert
Tahun aktif1989–present
Pasangan
Garth Lawless (1988–1995),
Robert Tapert
(1998–kini)[perlu rujukan]

Lucy Lawless (lahir Lucille Frances Ryan; 29 Mac 1968) ialah seorang pelakon dan penyanyi New Zealand yang terkenal dalam memainkan watak tajuk siri televisyen Xena: Warrior Princess dan lakonan beliau sebagai Nombor Tiga di Battlestar Galactica.




Isi kandungan





  • 1 Biografi

    • 1.1 Kehidupan awal



  • 2 Rujukan


  • 3 Pautan luar




Biografi |



Kehidupan awal |


Lawless dilahirkan di Mount Albert, New Zealand dan merupakan anak kelima daripada tujuh orang adik-beradik. Beliau ialah anak perempuan Julie dan Frank Ryan[1].


Beliau mula berlakon semasa di sekolah menengah. Semasa membesar, Lucy menghidap penyakit bulimia dan berjaya melawan penyakit itu.[2]



Rujukan |




  1. ^ Lucy Lawless Biography (1968-)


  2. ^ "Lawless Bulimic No More". People. 17 May 1999. Dicapai 18 June 2011. 




Pautan luar |




  • Official fan club site


  • Lucy Lawless di Pangkalan Data Filem Internet (IMDb)


  • Lucy Lawless di TV.com

  • Lucy Lawless Interview, May 2007

  • Interview with TheStarScoop, Sept 2006


















Persondata
Nama
Lawless, Lucy
Nama alternatif
Tapert, Lucy; Ryan, Lucille Frances
Pemerihalan ringkas

Pelakon dan penyanyi New Zealand yang dikenali untuk lakonannya sebagai Xena siri televisyen Amerika Syarikat Xena: Warrior Princess, dan Nombor Tiga di Battlestar Galactica.
Tarikh kelahiran

29 Mac 1968
Tempat kelahiran

Mount Albert, New Zealand
Tarikh kematian

Tempat kematian




Diambil daripada "https://ms.wikipedia.org/w/index.php?title=Lucy_Lawless&oldid=3818705"










Menu pandu arah



























(window.RLQ=window.RLQ||[]).push(function()mw.config.set("wgPageParseReport":"limitreport":"cputime":"0.200","walltime":"0.277","ppvisitednodes":"value":1335,"limit":1000000,"ppgeneratednodes":"value":0,"limit":1500000,"postexpandincludesize":"value":10502,"limit":2097152,"templateargumentsize":"value":2142,"limit":2097152,"expansiondepth":"value":18,"limit":40,"expensivefunctioncount":"value":0,"limit":500,"unstrip-depth":"value":0,"limit":20,"unstrip-size":"value":1317,"limit":5000000,"entityaccesscount":"value":1,"limit":400,"timingprofile":["100.00% 244.038 1 -total"," 46.49% 113.463 1 Templat:Infobox_actor"," 37.57% 91.676 1 Templat:Infobox"," 17.34% 42.306 1 Templat:Imdb_name"," 17.17% 41.912 1 Templat:Reflist"," 14.76% 36.019 1 Templat:Cite_news"," 12.17% 29.688 5 Templat:Br_separated_entries"," 7.57% 18.475 1 Templat:Commonscat"," 6.03% 14.720 1 Templat:Birth_date_and_age"," 5.55% 13.545 1 Templat:Sister"],"scribunto":"limitreport-timeusage":"value":"0.053","limit":"10.000","limitreport-memusage":"value":2181357,"limit":52428800,"cachereport":"origin":"mw1272","timestamp":"20190414054402","ttl":3600,"transientcontent":true);mw.config.set("wgBackendResponseTime":406,"wgHostname":"mw1272"););

Popular posts from this blog

Boston (Lincolnshire) Stedsbyld | Berne yn Boston | NavigaasjemenuBoston Borough CouncilBoston, Lincolnshire

Ballerup Komuun Stääden an saarpen | Futnuuten | Luke uk diar | Nawigatsjuunwww.ballerup.dkwww.statistikbanken.dk: Tabelle BEF44 (Folketal pr. 1. januar fordelt på byer)Commonskategorii: Ballerup Komuun55° 44′ N, 12° 22′ O

Why is this an NFA, but not an FA? The 2019 Stack Overflow Developer Survey Results Are InConvert from DFA to NFAProve that a PDA with accept states accepts all context-free languagesHow can a DFA corresponding to an NFA have a transition that the original NFA does not?Intersection of 2 deterministic finite state automata, but nondeterministicallyFinite automata as dynamical systemsLanguages acceptable with just a single final stateFind equivalence classes of given regular expressionWhy is this transition considered to be non deterministic?Converting NFA to DFA. Loops and exits.Given a transition table do digraph, determine if it is DFA or NFA and build grammar