Changing order of iterated integrals The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Basic integralsRewriting triple iterated integralsEvaluating the integral $int_0^1000 e^x-[x]dx$Triple integral problem involving definite integrals (and Taylor's formula possibly)Calculate the integral : $iiint_G xysin(yz)$ While $0leq xleqpi, 0 leq y leq 1, 0leq z leq pi/6$Changing order of iterated integralOrder of Integration in Divergent IntegralsHow to write iterated triple integralsTrouble with Iterated Integralsgive 5 other equivalent iterated triple integrals
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Changing order of iterated integrals
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Basic integralsRewriting triple iterated integralsEvaluating the integral $int_0^1000 e^x-[x]dx$Triple integral problem involving definite integrals (and Taylor's formula possibly)Calculate the integral : $iiint_G xysin(yz)$ While $0leq xleqpi, 0 leq y leq 1, 0leq z leq pi/6$Changing order of iterated integralOrder of Integration in Divergent IntegralsHow to write iterated triple integralsTrouble with Iterated Integralsgive 5 other equivalent iterated triple integrals
$begingroup$
I am given an integral $int_0^2int_0^4-y^2int_0^y/2 f(x,y,z) dxdzdy$. Hence, retrieving the respective inequalities:
$0<=x<=y/2$
$0<=z<=4-y^2$
$0<=y<=2$
I have tried interchanging the order to $dydzdx$ and this is what I derived at:
$int_0^1int_0^4-4x^2int_0^2x f(x,y,z) dydzdx$, however my answer is incomplete, may I know what went wrong?
calculus integration
asked Mar 31 at 14:47
Cheryl Cheryl
498
$endgroup$
add a comment |
$begingroup$
I am given an integral $int_0^2int_0^4-y^2int_0^y/2 f(x,y,z) dxdzdy$. Hence, retrieving the respective inequalities:
$0<=x<=y/2$
$0<=z<=4-y^2$
$0<=y<=2$
I have tried interchanging the order to $dydzdx$ and this is what I derived at:
$int_0^1int_0^4-4x^2int_0^2x f(x,y,z) dydzdx$, however my answer is incomplete, may I know what went wrong?
calculus integration
asked Mar 31 at 14:47
Cheryl Cheryl
498
$endgroup$
add a comment |
$begingroup$
I am given an integral $int_0^2int_0^4-y^2int_0^y/2 f(x,y,z) dxdzdy$. Hence, retrieving the respective inequalities:
$0<=x<=y/2$
$0<=z<=4-y^2$
$0<=y<=2$
I have tried interchanging the order to $dydzdx$ and this is what I derived at:
$int_0^1int_0^4-4x^2int_0^2x f(x,y,z) dydzdx$, however my answer is incomplete, may I know what went wrong?
calculus integration
asked Mar 31 at 14:47
Cheryl Cheryl
498
$endgroup$
I am given an integral $int_0^2int_0^4-y^2int_0^y/2 f(x,y,z) dxdzdy$. Hence, retrieving the respective inequalities:
$0<=x<=y/2$
$0<=z<=4-y^2$
$0<=y<=2$
I have tried interchanging the order to $dydzdx$ and this is what I derived at:
$int_0^1int_0^4-4x^2int_0^2x f(x,y,z) dydzdx$, however my answer is incomplete, may I know what went wrong?
calculus integration
calculus integration
asked Mar 31 at 14:47
Cheryl Cheryl
498
asked Mar 31 at 14:47
Cheryl Cheryl
498
asked Mar 31 at 14:47
Cheryl Cheryl
498
asked Mar 31 at 14:47
Cheryl Cheryl
498
asked Mar 31 at 14:47
Cheryl Cheryl
498
498
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You are given $x leq y/2$, i.e., $2x leq y$. Therefore your innermost integral should not go from $0$ to $2x$ but rather from $2x$ to $2$.
answered Mar 31 at 14:58
kccukccu
11.2k11231
$endgroup$
add a comment |
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$begingroup$
You are given $x leq y/2$, i.e., $2x leq y$. Therefore your innermost integral should not go from $0$ to $2x$ but rather from $2x$ to $2$.
answered Mar 31 at 14:58
kccukccu
11.2k11231
$endgroup$
add a comment |
$begingroup$
You are given $x leq y/2$, i.e., $2x leq y$. Therefore your innermost integral should not go from $0$ to $2x$ but rather from $2x$ to $2$.
answered Mar 31 at 14:58
kccukccu
11.2k11231
$endgroup$
add a comment |
$begingroup$
You are given $x leq y/2$, i.e., $2x leq y$. Therefore your innermost integral should not go from $0$ to $2x$ but rather from $2x$ to $2$.
answered Mar 31 at 14:58
kccukccu
11.2k11231
$endgroup$
You are given $x leq y/2$, i.e., $2x leq y$. Therefore your innermost integral should not go from $0$ to $2x$ but rather from $2x$ to $2$.
answered Mar 31 at 14:58
kccukccu
11.2k11231
answered Mar 31 at 14:58
kccukccu
11.2k11231
answered Mar 31 at 14:58
kccukccu
11.2k11231
answered Mar 31 at 14:58
kccukccu
11.2k11231
11.2k11231
add a comment |
add a comment |
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