Ratio of Gamma function equality. The 2019 Stack Overflow Developer Survey Results Are InIncomplete gamma functionPartial Fractions Decomposition of the Gamma FunctionProof of a formula involving Gamma functionUpper bound on ratio of incomplete Gamma function and Gamma function $frac Gamma left( x; aright)Gamma(x)$What substitution (to be used in integration) can proof the following equality?Power series of a function related to Gamma functionQusetion about Gamma functionEquality of Ratio of Gamma FunctionsGamma fuction of odd numbers divided by 2Asymptotic approximation regarding the Gamma function $Gamma$.
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Ratio of Gamma function equality.
The 2019 Stack Overflow Developer Survey Results Are InIncomplete gamma functionPartial Fractions Decomposition of the Gamma FunctionProof of a formula involving Gamma functionUpper bound on ratio of incomplete Gamma function and Gamma function $frac Gamma left( x; aright)Gamma(x)$What substitution (to be used in integration) can proof the following equality?Power series of a function related to Gamma functionQusetion about Gamma functionEquality of Ratio of Gamma FunctionsGamma fuction of odd numbers divided by 2Asymptotic approximation regarding the Gamma function $Gamma$.
$begingroup$
Let $m,ninmathbb N$ with $m<n$ and $0<s<1$, $1leq p<infty$. Is the following holds $$fracGamma(fracsp+p+n-22)Gamma(fracn-m+sp2)Gamma(fracn+sp2)Gamma(fracsp+p+n-m-22)=1.$$
Where $Gamma$ is the usual gamma function.
Clearly for $p=2$, its true.
I'm trying to show this for any $p$ with the above range but couldn't do.
real-analysis integration complex-analysis gamma-function
$endgroup$
add a comment |
$begingroup$
Let $m,ninmathbb N$ with $m<n$ and $0<s<1$, $1leq p<infty$. Is the following holds $$fracGamma(fracsp+p+n-22)Gamma(fracn-m+sp2)Gamma(fracn+sp2)Gamma(fracsp+p+n-m-22)=1.$$
Where $Gamma$ is the usual gamma function.
Clearly for $p=2$, its true.
I'm trying to show this for any $p$ with the above range but couldn't do.
real-analysis integration complex-analysis gamma-function
$endgroup$
add a comment |
$begingroup$
Let $m,ninmathbb N$ with $m<n$ and $0<s<1$, $1leq p<infty$. Is the following holds $$fracGamma(fracsp+p+n-22)Gamma(fracn-m+sp2)Gamma(fracn+sp2)Gamma(fracsp+p+n-m-22)=1.$$
Where $Gamma$ is the usual gamma function.
Clearly for $p=2$, its true.
I'm trying to show this for any $p$ with the above range but couldn't do.
real-analysis integration complex-analysis gamma-function
$endgroup$
Let $m,ninmathbb N$ with $m<n$ and $0<s<1$, $1leq p<infty$. Is the following holds $$fracGamma(fracsp+p+n-22)Gamma(fracn-m+sp2)Gamma(fracn+sp2)Gamma(fracsp+p+n-m-22)=1.$$
Where $Gamma$ is the usual gamma function.
Clearly for $p=2$, its true.
I'm trying to show this for any $p$ with the above range but couldn't do.
real-analysis integration complex-analysis gamma-function
real-analysis integration complex-analysis gamma-function
asked Mar 30 at 21:16
MathRockMathRock
316
316
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1 Answer
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$begingroup$
For example with $m=1$ , $n=2$ , $s=frac12$ , $p=4$
$Gamma(fracsp+p+n-22)= 2$
$Gamma(fracn-m+sp2) = fracsqrtpi2$
$Gamma(fracn+sp2) = 1$
$Gamma(fracsp+p+n-m-22) = frac3sqrtpi4$
$$fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) = frac2fracsqrtpi21frac3sqrtpi4 = frac43$$
The result is different from $1$.
Thus, $fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) $ is not always equal to $1$.
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
For example with $m=1$ , $n=2$ , $s=frac12$ , $p=4$
$Gamma(fracsp+p+n-22)= 2$
$Gamma(fracn-m+sp2) = fracsqrtpi2$
$Gamma(fracn+sp2) = 1$
$Gamma(fracsp+p+n-m-22) = frac3sqrtpi4$
$$fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) = frac2fracsqrtpi21frac3sqrtpi4 = frac43$$
The result is different from $1$.
Thus, $fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) $ is not always equal to $1$.
$endgroup$
add a comment |
$begingroup$
For example with $m=1$ , $n=2$ , $s=frac12$ , $p=4$
$Gamma(fracsp+p+n-22)= 2$
$Gamma(fracn-m+sp2) = fracsqrtpi2$
$Gamma(fracn+sp2) = 1$
$Gamma(fracsp+p+n-m-22) = frac3sqrtpi4$
$$fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) = frac2fracsqrtpi21frac3sqrtpi4 = frac43$$
The result is different from $1$.
Thus, $fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) $ is not always equal to $1$.
$endgroup$
add a comment |
$begingroup$
For example with $m=1$ , $n=2$ , $s=frac12$ , $p=4$
$Gamma(fracsp+p+n-22)= 2$
$Gamma(fracn-m+sp2) = fracsqrtpi2$
$Gamma(fracn+sp2) = 1$
$Gamma(fracsp+p+n-m-22) = frac3sqrtpi4$
$$fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) = frac2fracsqrtpi21frac3sqrtpi4 = frac43$$
The result is different from $1$.
Thus, $fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) $ is not always equal to $1$.
$endgroup$
For example with $m=1$ , $n=2$ , $s=frac12$ , $p=4$
$Gamma(fracsp+p+n-22)= 2$
$Gamma(fracn-m+sp2) = fracsqrtpi2$
$Gamma(fracn+sp2) = 1$
$Gamma(fracsp+p+n-m-22) = frac3sqrtpi4$
$$fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) = frac2fracsqrtpi21frac3sqrtpi4 = frac43$$
The result is different from $1$.
Thus, $fracGamma(fracsp+p+n-22) Gamma(fracn-m+sp2) Gamma(fracn+sp2) Gamma(fracsp+p+n-m-22) $ is not always equal to $1$.
answered Mar 30 at 22:14
JJacquelinJJacquelin
45.6k21857
45.6k21857
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