Computing the gradient of L_2 cost function The 2019 Stack Overflow Developer Survey Results Are InUsing summation notation to prove the Leibniz rule for the gradient of productFinding the Gradient of a Tensor FieldFinding the Gradient of a Vector Function by its ComponentsThe connection between the Jacobian, Hessian and the gradient?Connection of Gradient, Jacobian and Hessian matrix in Newton methodDifferentiability and gradient of a function of a single variableRecover scalar field from gradientIs the gradient of a vector product a row or a column?Is this bounded below by $2$ ?Gradient of an interpolated function
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Computing the gradient of L_2 cost function
The 2019 Stack Overflow Developer Survey Results Are InUsing summation notation to prove the Leibniz rule for the gradient of productFinding the Gradient of a Tensor FieldFinding the Gradient of a Vector Function by its ComponentsThe connection between the Jacobian, Hessian and the gradient?Connection of Gradient, Jacobian and Hessian matrix in Newton methodDifferentiability and gradient of a function of a single variableRecover scalar field from gradientIs the gradient of a vector product a row or a column?Is this bounded below by $2$ ?Gradient of an interpolated function
$begingroup$
Suppose $x, y in mathbbR^2.$ We define $c(x,y) = x^t x + c y^t y,$ for some non-zero $c in mathbbR.$ In particular, we have $fracddx x^t x = 2x^t$ and $fracddy cy^t y = 2c y^t.$ Does this imply that the gradient of $c(x,y)$ is $2 (x, cy) = 2(x_1, x_2, cy_1, cy_2)$? Confirmation would be useful, as I am not familiar with matrix calculus. Thank you.
calculus multivariable-calculus vector-analysis
$endgroup$
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$begingroup$
Suppose $x, y in mathbbR^2.$ We define $c(x,y) = x^t x + c y^t y,$ for some non-zero $c in mathbbR.$ In particular, we have $fracddx x^t x = 2x^t$ and $fracddy cy^t y = 2c y^t.$ Does this imply that the gradient of $c(x,y)$ is $2 (x, cy) = 2(x_1, x_2, cy_1, cy_2)$? Confirmation would be useful, as I am not familiar with matrix calculus. Thank you.
calculus multivariable-calculus vector-analysis
$endgroup$
add a comment |
$begingroup$
Suppose $x, y in mathbbR^2.$ We define $c(x,y) = x^t x + c y^t y,$ for some non-zero $c in mathbbR.$ In particular, we have $fracddx x^t x = 2x^t$ and $fracddy cy^t y = 2c y^t.$ Does this imply that the gradient of $c(x,y)$ is $2 (x, cy) = 2(x_1, x_2, cy_1, cy_2)$? Confirmation would be useful, as I am not familiar with matrix calculus. Thank you.
calculus multivariable-calculus vector-analysis
$endgroup$
Suppose $x, y in mathbbR^2.$ We define $c(x,y) = x^t x + c y^t y,$ for some non-zero $c in mathbbR.$ In particular, we have $fracddx x^t x = 2x^t$ and $fracddy cy^t y = 2c y^t.$ Does this imply that the gradient of $c(x,y)$ is $2 (x, cy) = 2(x_1, x_2, cy_1, cy_2)$? Confirmation would be useful, as I am not familiar with matrix calculus. Thank you.
calculus multivariable-calculus vector-analysis
calculus multivariable-calculus vector-analysis
asked Mar 30 at 22:19
R. RosenR. Rosen
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