Suppose that $X_1, ldots, X_n oversetidsim F$. Is there a function $h$ such that $h(X_1), ldots, h(X_n) oversetiidsim G$? The 2019 Stack Overflow Developer Survey Results Are InSuppose $X_1,ldots,X_n$ are independent random variables. Find $rho(S_k,S_n)$.Suppose that $X_1, X_2, …, X_n$ are i.i.d. random variables such that $X_1sim N(mu, 0.5)$ and $n = 100$.calculating $P(X_n=max(X_1,X_2,ldots, X_n))$$X_1, dots, X_n$ are independent random variables. Suppose $M = min(X_1, X_2, dots, X_n)$Do we not have that $X_1, ldots, X_n sim F$ iff $X_1, ldots, X_n sim f$?If $X_1 perp X_2 perp ldots perp Z$, where $X_1, ldots, X_n$ are iid, is $fracX_1Z, ldots ,fracX_1Z$ are independent of $Z$?Suppose that $X_1, X_2$ are iid random variables with the same CDF, is it true that $P(X_2>X_1) = X_1$?Suppose $X_1, ldots, X_n$ are iid standard Cauchy random variables, does $frac1nsum_i=1^nX_i$ converge in probability or almost surely?If $X_1,ldots,X_n$ are independent, does $mathbbPX_n>maxX_1,ldots,X_n-1=mathbbP{X_n>X_1)cdotsmathbbPX_n>X_n-1$ hold?
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Suppose that $X_1, ldots, X_n oversetidsim F$. Is there a function $h$ such that $h(X_1), ldots, h(X_n) oversetiidsim G$?
The 2019 Stack Overflow Developer Survey Results Are InSuppose $X_1,ldots,X_n$ are independent random variables. Find $rho(S_k,S_n)$.Suppose that $X_1, X_2, …, X_n$ are i.i.d. random variables such that $X_1sim N(mu, 0.5)$ and $n = 100$.calculating $P(X_n=max(X_1,X_2,ldots, X_n))$$X_1, dots, X_n$ are independent random variables. Suppose $M = min(X_1, X_2, dots, X_n)$Do we not have that $X_1, ldots, X_n sim F$ iff $X_1, ldots, X_n sim f$?If $X_1 perp X_2 perp ldots perp Z$, where $X_1, ldots, X_n$ are iid, is $fracX_1Z, ldots ,fracX_1Z$ are independent of $Z$?Suppose that $X_1, X_2$ are iid random variables with the same CDF, is it true that $P(X_2>X_1) = X_1$?Suppose $X_1, ldots, X_n$ are iid standard Cauchy random variables, does $frac1nsum_i=1^n}X_i$ converge in probability or almost surely?If $X_1,ldots,X_n$ are independent, does $mathbbP{X_n>maxX_1,ldots,X_n-1=mathbbP{X_n>X_1)cdotsmathbbPX_n>X_n-1$ hold?
$begingroup$
Suppose that we have $n$ dependent random variables distributed as:
$$
X_1, ldots, X_n oversetidsim F
$$
Is there a function $h$ such that:
$$
h(X_1), ldots, h(X_n) oversetiidsim G
$$
for a new distribution $G$ where each of the $h(X_i)$ are now independent as well? I thought about the following:
$$
h(x) = 0cdot x + epsilon
$$
where $epsilon sim N(0,1)$. However, this relies on a random variable, which I am not sure if it would be valid.
probability statistics
$endgroup$
add a comment |
$begingroup$
Suppose that we have $n$ dependent random variables distributed as:
$$
X_1, ldots, X_n oversetidsim F
$$
Is there a function $h$ such that:
$$
h(X_1), ldots, h(X_n) oversetiidsim G
$$
for a new distribution $G$ where each of the $h(X_i)$ are now independent as well? I thought about the following:
$$
h(x) = 0cdot x + epsilon
$$
where $epsilon sim N(0,1)$. However, this relies on a random variable, which I am not sure if it would be valid.
probability statistics
$endgroup$
1
$begingroup$
Is $G$ given to you?
$endgroup$
– Minus One-Twelfth
Mar 31 at 1:34
add a comment |
$begingroup$
Suppose that we have $n$ dependent random variables distributed as:
$$
X_1, ldots, X_n oversetidsim F
$$
Is there a function $h$ such that:
$$
h(X_1), ldots, h(X_n) oversetiidsim G
$$
for a new distribution $G$ where each of the $h(X_i)$ are now independent as well? I thought about the following:
$$
h(x) = 0cdot x + epsilon
$$
where $epsilon sim N(0,1)$. However, this relies on a random variable, which I am not sure if it would be valid.
probability statistics
$endgroup$
Suppose that we have $n$ dependent random variables distributed as:
$$
X_1, ldots, X_n oversetidsim F
$$
Is there a function $h$ such that:
$$
h(X_1), ldots, h(X_n) oversetiidsim G
$$
for a new distribution $G$ where each of the $h(X_i)$ are now independent as well? I thought about the following:
$$
h(x) = 0cdot x + epsilon
$$
where $epsilon sim N(0,1)$. However, this relies on a random variable, which I am not sure if it would be valid.
probability statistics
probability statistics
asked Mar 30 at 23:41
user321627user321627
998515
998515
1
$begingroup$
Is $G$ given to you?
$endgroup$
– Minus One-Twelfth
Mar 31 at 1:34
add a comment |
1
$begingroup$
Is $G$ given to you?
$endgroup$
– Minus One-Twelfth
Mar 31 at 1:34
1
1
$begingroup$
Is $G$ given to you?
$endgroup$
– Minus One-Twelfth
Mar 31 at 1:34
$begingroup$
Is $G$ given to you?
$endgroup$
– Minus One-Twelfth
Mar 31 at 1:34
add a comment |
1 Answer
1
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$begingroup$
$h= 1$ is such a function. There are cases where $h$ is necessarily constant: e.g., $X_1=X_2$ with standard normal distribution.
$endgroup$
add a comment |
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$begingroup$
$h= 1$ is such a function. There are cases where $h$ is necessarily constant: e.g., $X_1=X_2$ with standard normal distribution.
$endgroup$
add a comment |
$begingroup$
$h= 1$ is such a function. There are cases where $h$ is necessarily constant: e.g., $X_1=X_2$ with standard normal distribution.
$endgroup$
add a comment |
$begingroup$
$h= 1$ is such a function. There are cases where $h$ is necessarily constant: e.g., $X_1=X_2$ with standard normal distribution.
$endgroup$
$h= 1$ is such a function. There are cases where $h$ is necessarily constant: e.g., $X_1=X_2$ with standard normal distribution.
answered Mar 31 at 0:00
Kavi Rama MurthyKavi Rama Murthy
74.1k53270
74.1k53270
add a comment |
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Is $G$ given to you?
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– Minus One-Twelfth
Mar 31 at 1:34